When plastic deformation of a material occurs, the material _____.

Answers

Answer 1

Answer: The material is permanently (irreversibly) modified

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Given the incomplete equation representing an organic addition reaction:X(g) + Cl2(g)==> XCl2(g)Which compound could be represented by X?(1) CH (3) C3H8(2) C2H4 (4) C4H10
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Which group would react with group 16 to form a compound?

Answers

Final answer:

Group 16 elements, also known as chalcogens, commonly react with nonmetals to form compounds.

Explanation:

In chemistry, group 16 elements are known as the chalcogens. Chalcogens react with various groups of elements, including metals and nonmetals. However, their reactions with nonmetals are more common.For example, sulfur (group 16) readily reacts with most nonmetals to form compounds. The resulting compounds can vary depending on the specific nonmetal involved. Therefore, the group that would most likely react with group 16 to form a compound is the nonmetals group.

Learn more about Chalcogens and their reactions here:

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Calculate the number of moles in a 14.5 gram sample of C4H10.

Answers

Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
= 58.14g/mol

Moles=14.5g / 58.14g/mol
=0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10

A.) Thermal Decomposition of 2.765 g NaHCO3 yields 1.234g of a solid Na2CO3 . Calculate the theoreticial yield and percent yield of Na2CO3.B) Thermal decomposition of 2.968 g of a mixture containing NaHCO3 lost 0.453 g . Calculate the percentage of NaHCO3 in this unknown mixture

Answers

Answer:

For A: The percent yield of sodium carbonate is 70.5 %

For B: The percent of sodium hydrogen carbonate in the unknown mixture is 15.26 %

Explanation:

For A:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of sodium hydrogen carbonate = 2.765 g

Molar mass of sodium hydrogen carbonate = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of sodium hydrogen carbonate}=(2.765g)/(84g/mol)=0.033mol$

The chemical equation for the thermal decomposition of sodium hydrogen carbonate follows:

$2NaHCO_3(s)\rightarrow Na_2CO_3(s)+CO_2(g)+H_2O(g)$

By Stoichiometry of the reaction:

2 moles of sodium hydrogen carbonate produces 1 mole of sodium carbonate

So, 0.033 moles of sodium hydrogen carbonate will produce = $(1)/(2)* 0.033=0.0165mol$ of sodium carbonate

Now, calculating the mass of sodium carbonate from equation 1, we get:

Molar mass of sodium carbonate = 106 g/mol

Moles of sodium carbonate = 0.0165 moles

Putting values in equation 1, we get:

$0.0165mol=\frac{\text{Mass of sodium carbonate}}{106g/mol}\n\n\text{Mass of sodium carbonate}=(0.0165mol* 106g/mol)=1.75g$

To calculate the percentage yield of sodium carbonate, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100$

Experimental yield of sodium carbonate = 1.234 g

Theoretical yield of sodium carbonate = 1.75 g

Putting values in above equation, we get:

$\%\text{ yield of sodium carbonate}=(1.234g)/(1.75g)* 100\n\n\% \text{yield of sodium carbonate}=70.5\%$

Hence, the percent yield of sodium carbonate is 70.5 %

For B:

To calculate the percentage composition of sodium hydrogen carbonate in mixture, we use the equation:

$\%\text{ composition of sodium hydrogen carbonate}=\frac{\text{Mass of sodium hydrogen carbonate}}{\text{Mass of mixture}}* 100$

Mass of mixture = 2.968 g

Mass of sodium hydrogen carbonate = 0.453 g

Putting values in above equation, we get:

$\%\text{ composition of sodium hydrogen carbonate}=(0.453g)/(2.968g)* 100=15.26\%$

Hence, the percent of sodium hydrogen carbonate in the unknown mixture is 15.26 %

2NaHCO3 -> Na2CO3 + H2O + CO2
2.765g NaHCO3/MM = moles NaHCO3
moles NaHCO3 x (1 mole Na2CO3 / 2 moles NaHCO3) x MM Na2CO3 = theoretical yield of Na2CO3

Percent yield is simply the actual yield/theoretical yield (x100 to put it into percentage).

MM = Molar mass (grams of substance per mol)

Which belief is the basis of Ptolemy's geocentric model of the solar system?

Answers

Answer:

"Earth-centered," or "geocentric" Ptolemy thought that all celestial objects — including the planets, Sun, Moon, and stars — orbited Earth. Earth, in the center of the universe, did not move at all.

Explanation:

Answer:

Geocentric

Explanation:

Its the belief that earth was the center of the solar system instead of the sun

A chemical system that resists changes in pH and prevents large swings in the pH is called __________. a) A base b) An acid c) An anion d) A buffer

Answers

Answer:

Explanation:

okay so first add two to four and the ten

What occurs in both fusion and fission reactions?(1) Small amounts of energy are converted into
large amounts of matter.
(2) Small amounts of matter are converted into
large amounts of energy.
(3) Heavy nuclei are split into lighter nuclei.
(4) Light nuclei are combined into heavier nuclei

Answers

Fusion and fission are nuclear reactions that convert a small amount of matter into a large amount of energy.

The fusion reaction is the reaction in which the molecules combine and form energy. The fission reaction is the decomposition nuclear reaction where the matter is degraded into a small entity and the energy is released.

The energy is not converted into matter in both reactions. There is no splitting or combination of nuclei in both reactions.

Thus, the small amount of matter is converted into a large amount of energy is correct.

For more information, refer to the link:

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I believe the correct answer from the choices listed above is option 2. Small amounts of matter are converted into
large amounts of energy occurs in both fusion and fission reactions. They are nuclear reactions where a change in the identity or characteristics of an atomic nucleus results when it is bombarded with an energetic particle, as in fission, fusion, or radioactive decay.

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