The most easily polluted groundwater reservoirs are ______ aquifers?

Answers

Answer 1
Answer: Water-table aquifers.

The most easily polluted groundwater reservoirs are water-table aquifers.

Infiltration is the process by which rainwater becomes groundwater. In the water cycle, which involves primarily; evaporation, condensation and precipitation. Henceforth, after precipitation comes infiltration in the land areas leaving the rainwater aggregated in a single location which accumulates over time. Then this process is followed by runoff and subsurface flow by which water flows through other bodies of water, either in river, sea or ocean, even lake. Other rainwaters that has segregated and wasn’t able to transport itself stays in the process of infiltration, thus groundwater.



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SKILL LEVELMastery
Which of these subatomic particles has virtually no mass?
a
Proton
b Nucleus
C Neutron
d Electron
Chockit
int?

Answers

the answer is D electron

Which statement describes J.J. Thomson’s plum-pudding model of the atom?A. The electrons take up most of the space in an atom.
B. The electrons in the atom orbit around the protons.
C. The electrons are embedded in a positive sphere.

Answers

Option C: the electrons are embedded in a positive sphere.

As we know that was a wrong model and nowadays the electrons are considered to be around the nucleus, in regions called orbitals.

Who did not lead voyages of exploration?
Prince Henry
da Gama
Dias
Cabot

Answers

prince Henry is your answer (:

Answer:

prince Henry

Explanation:

Click on the diagram to choose which atom is more reactive.

Answers

Answer:

Second graph is more reactive.

Explanation:

I just did the lesson myself, chose the first graph, and obviously got it wrong.

Therefore I can tell you with 100% certainty that the correct answer is graph #2 in this case.  Hope this helps.

The first diagram is the atom that is more reactive

Which of the following statements describes a scientific law?a. A scientific law explains a set of events.
b. A scientific law describes what occurs every time in a situation.
c. A scientific law is constantly modified.
d. A scientific law is developed without experimentation.

Answers

The correct answer is B.

scientific law which describes what occurs every time in a situation. Scientific law always applies under same condition.


Laws differs from scientific theory because they does not posit explanation of phenomena.

Different laws takes mathematical forms. Scientific law is being associated with natural science but social sciences also contains laws.


A good example of scientific law in social sciences is Zipf's law.

Answer:

B. a law is a proven fact that cannot be changed.

Explanation:

How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2?

Answers

First we establish the chemical reaction equation. 
2Mg + O2 = 2MgO. 
Then we need to know which of the reactant is limiting. We do that by multiplying the number of moles of reactant to the stoichiomeric coefficient. For Magnesium: 97.2 g* (mol)/(24g) *2 = 8
For O2: 88.5g*(mol)/(32g) *1 = 2.7
Since O2 has the smaller moles, this is the Limiting reactant. Then we solve basing on the number of O2 used. 

88.5g* (mol)/(32g) * (2)/(1) * (56g)/(mol) = 309.75 g

Answer : The mass of magnesium oxide produced will be, 161.2 g

Solution : Given,

Mass of Mg = 97.2 g

Mass of O_2 = 88.5 g

Molar mass of Mg = 24.3 g/mole

Molar mass of O_2 = 32 g/mole

Molar mass of MgO = 40.3 g/mole

First we have to calculate the moles of Mg and O_2.

\text{Moles of Mg}=\frac{\text{Mass of Mg}}{\text{Molar mass of Mg}}=(97.2g)/(24.3g/mole)=4\text{ moles}

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=(88.5g)/(32g/mole)=2.7\text{ moles}

The balanced reaction is,

2Mg+O_2\rightarrow 2MgO

As, 2 moles of Mg react with 1 moles of O_2

So, 4 moles of Mg react with (4)/(2)=2 moles of O_2

From this we conclude that the O_2 is in excess amount and Mg is in limited amount.

Now from the reaction we conclude that

As, 2 moles of Mg react to give 2 moles of MgO

So, 4 moles of Mg react to give 4 moles of MgO

Now we have to calculate the mass of MgO.

\text{Mass of MgO}=\text{Moles of MgO}* \text{Molar mass of MgO}

\text{Mass of MgO}=(4moles)* (40.3g/mole)=161.2g

Therefore, the mass of magnesium oxide produced will be, 161.2 g