CHEMISTRY HIGH SCHOOL

_________ refers to the total energy of a system.a. Enthalpy
c. Entropy
b. Heating curve
d. Free energy

Answers

Answer 1
Answer:     Enthalpy refers to the total energy of a system. Hope this helped!
Answer 2
Answer:

Answer:   a. Enthalpy

Explanation:

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Which observation illustrates the law of conservation of mass?a. Burning 10 g of propane produces twice as much carbon dioxide as burning 5 g of propane.
b. The C:O mass ratio of one compound is exactly double that of another compound.
c. When 3 g of carbon reacts with 8 g of oxygen, 11 g of carbon dioxide is produced.
d. The C:O mass ratio of a particular compound is the same, regardless of the size or source of the sample.

Answers

I believe that the answer is C. 

Which of the following explains the importance of the activation energy acting as a barrier for reactants?

Answers

The energy needed for a chemical reaction is called the activation energy. This energy is to be present in order for the reaction to happen. This can be achieved by supplying or releasing heat from a system of reactants. This can achieved faster by using a catalyst.

What coefficients are needed to balance the equation for the complete combustion of methane? enter the coefficients in the order ch4, o2, co2, and h2o, respectively.

Answers

The coefficients in the order CH₄, O₂, CO₂, and H₂O, are 1,2,1,2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

Further explanation

Complete combustion of hydrocarbon with oxygen will be obtained by CO₂ and H₂O compounds.

If O is insufficient there will be incomplete combustion produced by CO and H and O

Hydrocarbon combustion reactions (specifically alkanes)

\large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 ----> nCO_2 + (n + 1) H_2O}}}

Equalization of chemical reaction equations can be done using variables.

Steps in equalizing the reaction equation:

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product
  • 3. Select the coefficient of the substance with the most complex chemical formula equal to 1

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:

Balancing C atoms, H and last atoms O atoms

Methana combustion reaction

CH₄ (g) + O₂ (g) -> CO₂ (g) + H₂0 (g)

We give the most complex compounds, namely Methane, we give the number 1

So the reaction becomes

CH₄ (g) + aO₂ (g) -> bCO₂ (g) + cH₂0 (g)

C atom on the left 1, right b, so b = 1

H atom on the left 4, right 2c, so 2c = 4 ---> c = 2

Atom O on the left 2a, right 2b + c, so 2a = 2b + c

2a = 2.1 + 2

2a = 4

a = 2

The equation becomes:

CH₄ (g) + 2O₂ (g) -> CO₂ (g) + 2H₂0 (g)

Learn more

the combustion of octane in gasoline

brainly.com/question/8175791

brainly.com/question/897044

hydrogen and excess oxygen

brainly.com/question/1405182

Keywords: methane, combustion, hydrocarbons, equalization of reaction equations

The balanced chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left( g \right) + 2{{\text{O}}_2}\left( g \right) \to {\text{C}}{{\text{O}}_{\text{2}}}\left( g \right) + 2{{\text{H}}_{\text{2}}}{\text{O}}\left( g \right)

The coefficients of {\mathbf{C}}{{\mathbf{H}}_{\mathbf{4}}} is \boxed1, {{\mathbf{O}}_{\mathbf{2}}} is \boxed2, {\mathbf{C}}{{\mathbf{O}}_{\mathbf{2}}} is \boxed1 and {{\mathbf{H}}_{\mathbf{2}}}{\mathbf{O}} is \boxed2

Further Explanation:

The chemical reaction that contains equal number of atoms of the different elements in the reactant as well as in the product side is known as balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Combustion reaction is the reaction in which the reactant reacts with molecular oxygen to form carbon dioxide and water molecule. Molecularoxygen acts as the oxidizing agent in these reactions. The large amount of heat is released and therefore combustion reactions are exothermic reaction.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In the combustion reaction, {\text{C}}{{\text{H}}_4} reacts with {{\text{O}}_2} to form {\text{C}}{{\text{O}}_{\text{2}}} and {{\text{H}}_{\text{2}}}{\text{O}}. The physical state of {\text{C}}{{\text{H}}_4} is gas, {{\text{O}}_2} is gas, {\text{C}}{{\text{O}}_{\text{2}}} is gas and {{\text{H}}_{\text{2}}}{\text{O}} is gas. The unbalanced chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left(g\right)+{{\text{O}}_2}\left(g\right)\to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately. There is one carbon atom on both the reactant and product side. 2 oxygen atoms are present on the reactant side while 3 oxygen atoms are present on the product side. The number of hydrogen atoms on the reactant and product sides is 4 and 2 respectively. (Refer table in the attached image).

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side but in the combustion reaction there is only carbon, hydrogen and oxygen atom.

Step 4: After this, we balance the number of atoms of oxygen and then carbon atom followed by hydrogen atoms. To balance the number of atoms of oxygen and hydrogen, we have to multiply {{\text{O}}_2} by 2 and {{\text{H}}_{\text{2}}}{\text{O}} by 2. The chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left(g\right)+2{{\text{O}}_2}\left(g\right)\to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)

Step 5: Finally, we check the number of atoms of each element on both sides. If the number is same then the chemical equation is balanced. The balanced chemical equation is as follows:

{\text{C}}{{\text{H}}_4}\left(g\right)+2{{\text{O}}_2}\left( g \right) \to{\text{C}}{{\text{O}}_{\text{2}}}\left(g\right)+2{{\text{H}}_{\text{2}}}{\text{O}}\left(g\right)

The coefficients of {\text{C}}{{\text{H}}_4} is 1,  {{\text{O}}_2} is 2, {\text{C}}{{\text{O}}_{\text{2}}} is 1 and {{\text{H}}_{\text{2}}}{\text{O}} is 2.

Learn more:

1. Balanced chemical equation brainly.com/question/1405182

2. Learn more about how to calculate moles of the base in given volume brainly.com/question/4283309

Answer details:  

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: Balancing, CH4, O2, CO2, H2O, phases, physical state, solid, liquid, gas, aqueous, coefficients, and combustion reactions.

• 1) The pressure of a sample of gas in a 2.00-L container is 876 mmHg.What will the pressure be if the sample is placed in a 400 mL
container? P1V1=P2V2

Answers

Answer:

4380 mmHg

Explanation:

Boyle's Law can be used to explain the relationship between pressure and volume of an ideal gas. The pressure is inversely related to volume, so if volume decrease the pressure will increase. It can be expressed in the equation as:

P1V1=P2V2

In this question, the first condition is 2L volume and 876 mmHg pressure. Then the system changed into the second condition where the volume is 400ml and the pressure is unknown. The pressure will be:

P1V1= P2V2

876 mmHg * 2L = P2 * 400ml /(1000ml/L)

P2= 876 mmHg * 2L / 0.4L

P2= 4380 mmHg

A major function of your nose is cleaning the air you breathe.
True
False

Answers

Answer:

It's true I got it wrong.

Explanation:

Explain the four quantum numbers

Answers

 Principal (shell) quantum number - n 
 

Describes the energy level in the atom (1 through 7)The maximum number of electrons in n is 2n2  
2. Angular (subshell) quantum number - l 
 Describes the sublevel in nEach energy level has n sublevels  
3. Magnetic quantum number - m 
 Describes the orbital within ls has 1 orbitalp has 3 orbitalsd has 5 orbitalsf has 7 orbitals  
4. Spin quantum number - s 
 Describes the spin of the electrons in an orbital.Electrons in the same orbital must have oppisite spins.Possible spins are clockwise or counterclockwise.
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