Carbon dioxide is one of the main gases in the mixture of gases coming out of the kiln.Give two reasons why.

Answers

Answer 1

Answer: because the kiln utilizes fire, fire uses oxygen and the fuel to create CO2
CO2 would be the main gas because the main components of the reactants are carbon and oxygen, which make up CO2

Related Questions

How many grams of hydrogen peroxide (H2O2) must be added to 1,500 mL of water to produce a concentration of 1.33 m (molal solution)? (Recall that the density of water is 1.0 gram/mL.)
Which of the following is not produced by nuclear decay?A) Alpha particles B) Beta particles C) Gamma rays D) Delta particles
Identify the correct formula for each of the following compounds? boron tribromide a. b3br b. bbr3 c. 3bbr
Suppose a 1.30 g nugget of pure gold has zero net charge. What would be its net charge after it has 1.68% of its electrons removed?
Mendeleev saw trends in the physical and chemical properties of elements when he organized them by _____.

Select all (there's more than one) of the below chemicals that would be insoluble in water.a
NH4OH

b
NaNO3

c
PbCrO4

d
SrSO4

e
K3PO4

f
AgClO4

g
HgCl2

h
FeCO3

i
NH4Br

j
Li2Cr2O7

Answers

FeCO₃ and PbCrO₄ is insoluble in water.

Explanation:

If any substance added to water and it form ions then it is soluble in water otherwise it is insoluble in water.

a. NH₄OH - soluble in water

b. NaNO₃ - soluble in water

C. PbCrO₄ is insoluble in water

d. SrSO₄ slightly soluble in water

e. K₃PO₄ - Soluble in water

f. AgClO₄- Highly Soluble in water

g. HgCl₂ - Slightly soluble in water

h. FeCO₃ - insoluble in water

i. NH₄Br - soluble in water

j. Li₂Cr₂O₇ - soluble in water

A.) Thermal Decomposition of 2.765 g NaHCO3 yields 1.234g of a solid Na2CO3 . Calculate the theoreticial yield and percent yield of Na2CO3.B) Thermal decomposition of 2.968 g of a mixture containing NaHCO3 lost 0.453 g . Calculate the percentage of NaHCO3 in this unknown mixture

Answers

Answer:

For A: The percent yield of sodium carbonate is 70.5 %

For B: The percent of sodium hydrogen carbonate in the unknown mixture is 15.26 %

Explanation:

For A:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of sodium hydrogen carbonate = 2.765 g

Molar mass of sodium hydrogen carbonate = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of sodium hydrogen carbonate}=(2.765g)/(84g/mol)=0.033mol$

The chemical equation for the thermal decomposition of sodium hydrogen carbonate follows:

$2NaHCO_3(s)\rightarrow Na_2CO_3(s)+CO_2(g)+H_2O(g)$

By Stoichiometry of the reaction:

2 moles of sodium hydrogen carbonate produces 1 mole of sodium carbonate

So, 0.033 moles of sodium hydrogen carbonate will produce = $(1)/(2)* 0.033=0.0165mol$ of sodium carbonate

Now, calculating the mass of sodium carbonate from equation 1, we get:

Molar mass of sodium carbonate = 106 g/mol

Moles of sodium carbonate = 0.0165 moles

Putting values in equation 1, we get:

$0.0165mol=\frac{\text{Mass of sodium carbonate}}{106g/mol}\n\n\text{Mass of sodium carbonate}=(0.0165mol* 106g/mol)=1.75g$

To calculate the percentage yield of sodium carbonate, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}* 100$

Experimental yield of sodium carbonate = 1.234 g

Theoretical yield of sodium carbonate = 1.75 g

Putting values in above equation, we get:

$\%\text{ yield of sodium carbonate}=(1.234g)/(1.75g)* 100\n\n\% \text{yield of sodium carbonate}=70.5\%$

Hence, the percent yield of sodium carbonate is 70.5 %

For B:

To calculate the percentage composition of sodium hydrogen carbonate in mixture, we use the equation:

$\%\text{ composition of sodium hydrogen carbonate}=\frac{\text{Mass of sodium hydrogen carbonate}}{\text{Mass of mixture}}* 100$

Mass of mixture = 2.968 g

Mass of sodium hydrogen carbonate = 0.453 g

Putting values in above equation, we get:

$\%\text{ composition of sodium hydrogen carbonate}=(0.453g)/(2.968g)* 100=15.26\%$

Hence, the percent of sodium hydrogen carbonate in the unknown mixture is 15.26 %

2NaHCO3 -> Na2CO3 + H2O + CO2
2.765g NaHCO3/MM = moles NaHCO3
moles NaHCO3 x (1 mole Na2CO3 / 2 moles NaHCO3) x MM Na2CO3 = theoretical yield of Na2CO3

Percent yield is simply the actual yield/theoretical yield (x100 to put it into percentage).

MM = Molar mass (grams of substance per mol)

1. Plants use energy from sunlight, water, and carbon dioxide to produce 10 pointssugar. Which structure is found only in plant cells and helps plants capture
energy from sunlight?
A. Vacuole
B. Nucleus
C. Chloroplast
D. Cell Membrane

Answers

The answer is c chloroplast

Answer:

Chloroplast

Explanation:

Magnesium reacts with hydrochloric acid (HCl) as follows. mc025-1.jpg How many milliliters of hydrogen gas are produced by the reaction 0.020 mol of magnesium with excess of hydrochloric acid at STP? 0.448 mL 0.45 mL 448 mL 450 mL

Answers

Answer: 448 mL of hydrogen gas.

Solution:

$Mg(s)+HCl(aq)\rightarrow MgCl_2(aq)_+H_2(g)$

Now,according to reaction

1 mole of magnesium produces one mole of hydrogen gas.

Then 0.020 moles of magnesium will produce 0.020 moles of hydrogen gas.

Moles of $H_$ gas : 0.020 mol

At STP, 1 mol of gas occupies 22.4 L

So volume of 0.020 mol of $H_2$ produced at STP :

= 22.4/times 0.020 = 0.448 L = 448 mL (1L=1000mL)

Answer:

The answer is D 450

Explanation:

I just did the quiz

What is a crystal?a. a type of rock
b. the smallest unit of an element
c. an artificial, decorative substance
d. a solid made of atoms arranged in an orderly fashion

Answers

A crystal is a solid made of atoms arranged in an orderly fashion .

answer: d. a solid made of atoms arranged in an orderly fashion.

D solid made of atoms arranged in an orderly configuration.

The main function of the kidney bladder and ureter is-?

Answers

Answer:

The urinary system's function is to filter blood and create urine as a waste by-product. The organs of the urinary system include the kidneys, renal pelvis, ureters, bladder and urethra.

Explanation:

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