__CH4 + __S8 ----> __CS2 + __H2SBalance this equation and calculate the mol CS2 produced when 1.50 mol S8 is used.
Answers
2 CH4 + 1 S8 ----> 2 CS2 + 4 H2S
1.50 mol S8 x 2 mol CS2 = 3 mol CS2
1 1 mol S8
Final answer:
The balanced chemical equation is CH4 + 4S8 --> CS2 + 4H2S. The moles of CS2 produced from 1.50 mol S8 will be 1.50 mol.
Explanation:
To balance the chemical equation CH4 + S8 --> CS2 + H2S, we'll start by balancing the sulfur atoms. The balanced equation becomes: CH4 + 4S8 --> CS2 + 4H2S. Now, count the carbon and the hydrogen atoms on both sides. These are balanced successfully, and hence the overall equation is balanced.
Now, let us calculate the moles of CS2 produced from 1.50 mol S8. Using stoichiometry, a ratio derived from the balanced equation, we find that 1 mol of S8 produces 1 mol of CS2. So, 1.50 mol S8 will produce 1.50 mol CS2.
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Answers
1 mol ----- 18.0 g
3.5 moles --- ?
Mass ( H₂O) = 3.5 x 18.0 / 1
=> 63.0 g
hope this helps!
Answers
Answers
? ? --------------------------- 2.90x10²² molecules
mass = 2.90x10²² * 40.0 / 6.02x10²³
mass = 1.16x10²⁴ / 6.02x10²³
mass = 1.9269 g
hope this helps!