Calculate the wavelength of a radio wave whose frequency is 900 kHz. (v = 3.00 · 108 m/s.)

Answers

Answer 1
Answer:

The wavelength of a radio wave whose frequency is 900 kHz will be 10³/3, or you can write it as 333.33 meters.

What is Wavelength?

To characterize waveform signals that are transmitted across wires or into space, the term "wavelength" is used to refer to the separation between two identical positions (adjacent crests) in succeeding cycles. Typically, this length in wireless systems is measured in meters (m), centimeters (cm), or millimeters (mm) (mm). When describing the wavelength of infrared (IR), visible light (UV), and gamma radiation, units of 10⁻⁹  nanometers (nm) or angstroms (10-10 m) are more usually used.

Frequency, which is defined as the number of wave cycles per second, and wavelength have an inverse relationship. The wavelength of a signal decreases with increasing frequency, or we can say that wavelength and refractive index are inversely proportional to each other.

According to the question, the given values are :

v = 3 × 10⁸ m/s and,

frequency, f = 900 kHz or,

f = 900 × 10³ Hz

λ = v / f

λ = (3 × 10⁸) / (3 × 10³)

λ = 10³/3 metes or,

λ = 333.33 meters.

So, the wavelength of a radio wave is 333.33 meters.

To get more information about wavelength :

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Answer 2
Answer:      Just use the Fundamental Equation of Periodic Waves:

v=\lambda f \n \lambda= (3* 10^8)/(900* 10^3) \n \lambda = \boxed {(10^3)/(3)~m}

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Which of the following is a true statement? A) It's easier to lift a heavy weight straight up than to slide it up a ramp. B) When you use a lot of effort, a load becomes lighter. C) When you use a minimum amount of effort, a load becomes heavier. D) When you increase the distance over which effort is expended, you don't have to work as hard.

What is the speed of a boat that travels 20 miles in 60 minutes? Please answer in miles per hour.Formula : speed = distance

time

Answers

d = r*t     r = d/t = 20/45 mi/min
20/45 mi/min * 60 min/hr = 1200/45 mi/hr
= 26.667 mi/hr
Hope i helped :)
As you reminded us at the end of the question:

         Speed  =  (distance) / (time)

                     =  (20 miles) / (60 minutes)

                     =    (1/3) mile/minute

To convert to the units you asked for . . .

                 (1/3 mile/minute) · (60 minutes/hour)

             =    (1/3 · 60)  (mile · minute) / (minute · hour)

             =            20  mile/hour .

P waves move through the crust at a speed of about 6.5 km/s. How far will the P wave move in five seconds?

Answers

Distance= speed x time
D=6.5x5
D=32.5km

A tropical storm turns into a hurricane when wind speeds reach?

Answers

A tropical storm turns into a hurricane when wind speeds reach more than 33 knots. It happens when the tropical depression strengthens and then the speed of the wind starts increasing and reaches a stage when it is called a hurricane. Right type of condition can create a powerful hurricane, but when the right conditions are not there, then the storm fizzles out. 

Answer:

74mph

Explanation:

the internet

Where are magnetic fields strongest near a bar magnet

Answers

The answer is letter A or 'top'

At the poles of the magnet.

Could anyone help me figure out d and e? How can you find the work of the friction when the force of friction is not given?

Answers

Wow !  This is not simple, Shoot, and I give you a lot of credit
and an extra merit badge if you're generally keeping up with it.

I scratched my head for a few minutes, and I think I've got it.
Here's what I think is going on:

KE₁ = KE of the box before pushing
               (1/2) (m) (speed²) = 10 x 2² = 40 joules

KE₂ = KE of the box after pushing 3m
               (1/2) (m) (speed²) = 10 x 4² = 160 joules

The box gained (160 - 40) = 120 J of kinetic energy.

Now look at the cluttered force diagram.
Cat's component of force in the direction of motion is 120N.
That's the part of her force that does the work on the box.
How much work does she do ?

     (force) x (distance) = (120N) x (3m) = 360 joules .

Only 120 J of that energy showed up as increased kinetic energy
of the box.  The other 240J of her hard-earned work was consumed
by friction.

       Work of friction = (Friction force) x (distance)

               240 J        = (friction force)  x  (3 m)

              240 J / 3 m  =  friction 'force'  =  80 N . 

I think that's it.

What I did was:

-- Find the work that Cat did.

-- Find the increase in the kinetic energy of the box.

-- The difference ... the 'missing energy' ... was the work done
by friction in the same distance.

Does this do anything for you ?

Which does more work, a force of 500 N moving through 10 m or a force of 100 N moving through 40 m?​

Answers

Explanation:

To determine which force does more work, we can calculate the work done by each force using the formula:

Work = Force × Distance

For the first scenario:

Work = 500 N × 10 m = 5000 N·m

For the second scenario:

Work = 100 N × 40 m = 4000 N·m

Therefore, the force of 500 N moving through 10 m does more work, with a total of 5000 N·m.