What is the total number of atoms contained in 2.11 moles of nickel?

Answers

Answer 1

Answer: The total number of atoms contained in 2.11 moles of nickel is
1.27 x10^24 atoms

calculation

By use of Avogadro law constant

That is 1 mole= 6.02 x10^23 atoms
what about 2.11 moles of nickel

by use of cross multiplication
[ 2.11 moles x ( 6.02 x10^23)] / 1 moles = 1.27 x10^24 atoms

Answer 2

Answer:

1.27 × 10²⁴ atoms of nickel are contained in 2.11 moles of nickel. For every mole of a substance there are 6.022 × 10²³ representative particles of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation

To convert from the number of moles to number of representative particles, the formula below may be used:

$\boxed {no. \ of \ particles \ = given \ no. \ of \ moles * (6.022 * 10^(23) \ particles)/(1 \ mole)}$

For this problem, the number of nickel atoms can be determined by plugging in the given values in the equation above:

$no. \ of \ Ni \ atoms = 2.11 \ mol \ Ni * (6.022 * 10^(23) Ni \ atoms)/(1 \ mol \ Ni)\n\n\boxed {no. \ of \ Ni \ atoms = 1.270642 * 10^(24) \ atoms}$

Since the given only has three significant figures, the final answer with the correct number of significant figures is:

$\boxed {\boxed {no. \ of \ Ni \ atoms = 1.27 * 10^(24) \ atoms}}$

Learn More

Learn more about representative particles brainly.com/question/8969313
Learn more about Avogadro's number brainly.com/question/229300
Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number

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Answers

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Using her new telescope Ashley discovers a spherical meteor passing between the earth and the moon and measures it’s radius as 3 kilometers how many cubic kilometers are in the meteor

Answers

Answer:

113 km³

Explanation:

Step 1: Given data

Radius of the meteor (r): 3 km

Step 2: Calculate the volume (V) of the meteor

The meteor is spherical. Given the radius (r), we can calculate the volume of a sphere using the following expression.

V = 4/3 × π × r³

V = 4/3 × π × (3 km)³

V = 4/3 × π × 27 km³

V = 113 km³

The volume of the meteor is 113 km³.

Consider an element Z that has two naturally occurring isotopes with the following percent abundances: the isotope with a mass number of 19.0 is 55.0% abundant; the isotope with a mass number of 21.0 is 45.0% abundant. What is the average atomic mass for element Z?Average atomic mass of Z = [mass]

Answers

Answer:

Average atomic mass = 19.9 amu

Explanation:

Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.

Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).

Given the following data;

Relative abundance of Z-19 = 55%

Relative abundance of Z-21 = 45%

Atomic mass of Z-19 = 19 amu

Atomic mass of Z-21 = 21 amu

To find the average atomic mass;

Average atomic mass = 19 * (55/100) + 21 * (45/100)

Average atomic mass = 19*0.55 + 21*0.45

Average atomic mass = 10.45 + 9.45

Average atomic mass = 19.9 amu

Therefore, the average atomic mass for element Z is 19.9 amu.

What type of compound is disulfur dichloride?a. organic compound
b. acid (ionic compound)
c. covalent compound
d. ionic compound

Answers

Answer:

Covalent compound

Explanation:

It is formed by covalent bonds, in which the atoms share a pair of valence electrons

2.67 grams of butane (C4H10) is combusted in a bomb calorimeter. The temperature increases from 25.68 C to 36.2C. What is the change in the internal energy (deltaE) in KJ/mol for the reaction if the heat capacity of the bomb calorimeter is 5.73 kJ/C?

Answers

The internal energy : 1310.43 kJ/mol

Further explanation

Internal energy (ΔE) can be formulated for Calorimeter :

$\tt \Delta E=C*.\Delta t$

C= the heat capacity of the calorimeter

Δt=36.2-25.68=10.52°C

$\tt \Delta E=5.73 kJ/^oC* 10.52^oC=60.2796~kJ$

mol butane(MW=58,12 g/mol)

$\tt (2.67)/(58,12 )=0.046$

the internal energy (ΔE) in KJ/mol

$\tt (60.2796)/(0.046)=1310.43~kJ/mol$

Final answer:

The change in internal energy when 2.67 grams of butane is combusted in a bomb calorimeter, given a temperature increase from 25.68 C to 36.2C and a heat capacity of 5.73 kJ/C for the calorimeter, is approximately 1308 kJ/mol.

Explanation:

To solve the problem of calculating the changes in internal energy when 2.67 grams of butane (C4H10) is combusted in a bomb calorimeter, it is necessary to understand calorimeter's heat capacity and how a bomb calorimeter works.

The first step will be to calculate the change in temperature which here is the final temperature subtracted from the initial temperature: 36.2 C - 25.68 C = 10.52 C.

Then, we multiply this temperature change by the heat capacity of the calorimeter to find the total heat produced by the reaction in kJ: 10.52 C * 5.73 kJ/C = 60.18 kJ.

The final step is to convert grams of butane to moles, because we are asked to find the energy change in kJ/mol. The molar mass of butane (C4H10) is approximately 58.12 g/mol. So we have approximately 2.67 g / 58.12 g/mol = 0.046 mol.

Finally, we divide the heat produced by the number of moles to get the energy change per mole of butane: 60.18 kJ / 0.046 mol = approximately 1308 kJ/mol.