A weather balloon of known initial volume is released. The air pressures ar its initial and final altitudes are known. Why can't you find its new volume by using these known values and Boyle's law?
Answers
Answer: you cannot find its new volume by using these known values and Boyle's law because the temperature does not remain constant.
Explanation:
Boyle's law states that the volume of a fixed amount of gas, at a constant temperature, varies inversely with the pressure.
So, it is a condition that the temperature does not change.
For the wheater ballon case, as it travels through the atmosphere, the temperature at different altitudes will be different.
So, you might use other equation of states, such as the combined law, which does deal with changes in the three variables: volume, pressure, and temperature.
The mathematical formulation of Boyle's law is:
pV = constanjt ⇒ p₁ V₁ = p₂ V₂, at constant T.
The mathematical formulation of the combined law of gases is:
pV/T = constant ⇒ p₁ V₁ / T₁ = p₂ V₂ / T₂, for a fixed amount of gas, then it might work for the weather ballon (if you know the initial and end temperatures).
You cannot find the new volume by using initial volume of the weather balloon and air pressure ai its initial and final altitudes and Boyle’s law because the given values are not the same. Boyle’s law holds for the pressure and volume of the GAS at constant temperature. Here you are given the air pressure outside the weather balloon not the inside of the balloon. They have different gases and so it would not apply.
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A .35 m solution of weak acid, HX, has a h+ of 4.15×10^-3. what is the value of ka for this acid
Please help ASAP ty :)
Answers
Answer:
The easiest way is to heat matter which raises its internal energy andso the mass as well. Another possibility is to accelerate matter as in case of protons or heavy ions in the LHC, Protons ,for example , are accelerated to the energies of 6500 GeV which means increase of the rest mass by a factor of almost 7000
Answers
Answers
Answer:
t = 50,000s
Explanation:
Reaction is second order.
Initial conc. [A]o = 0.020 M
Rate constant = 1.0x10-3 M-1s-1
Final conc. [A] = 0.010M
Time = ?
1 / [A] = kt + 1 / [A]o
Substituting the values;
1 / 0.010 = 1.0x10-3 * t + (1/0.020)
100 - 50 = 1.0x10-3 * t
t = 50 / (1.0x10-3)
t = 50,000s
Answer:
Time required is 50000s
Explanation:
General formula of a second-order reaction is:
Where [A] is concentration of reactant after time t passed, [A]₀ is initial concentration of reactant and K is rate constant of reaction.
Replacing:
50M⁻¹ = 1.0x10⁻³M⁻¹s⁻¹ t
50000s = t
Thus, after 50000s, the reactant concentration decrease from 0.020M to 0.010M
They are both carried from place to place by particles.
B.
They are both kinds of mechanical energy.
C.
They both need a medium to travel through.
D.
They both have a wavelength and a frequency.
Explanation
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D.
HOPE THIS WILL HELP U
Answers
0.708M = 0.098mol/L
Rearrange to find L:
0.098mol/0.708M = .138L
For every liter there is 1000 mL:
.138L • 1000mL =138mL KOH