A protein denatures when you cook it at 60°C. What is that temperature on the Kelvin scale?

Answers

Answer 1

Answer: Kelvin = Celsius + 273
60°C +273 = 333 K

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In this diagram, medium A represents water and medium B represents air. The phenomenon in this diagram, moving from A to B, is calledA) diffraction.
B) dispersion.
C) refraction.
D) resolution.

Answers

The answer is C) Refraction.
Hope this helps!

Hey there

The correct answer is (C)

= refraction

Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride: S(g) + 3F2(g) ->SF6(g) If 50 g S is allowed to react as completely as possible with 105.0g F2(g), what mass of the excess reactant is left.

Answers

Answer: The mass of excess reagent left is 20.48 g

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For sulfur:

Given mass of sulfur = 50 g

Molar mass of sulfur = 32 g/mol

Putting values in equation 1, we get:

$\text{Moles of sulfur}=(50g)/(32g/mol)=1.56mol$

For fluorine gas:

Given mass of fluorine gas = 105 g

Molar mass of fluorine gas = 37.99 g/mol

Putting values in equation 1, we get:

$\text{Moles of fluorine gas}=(105g)/(37.99g/mol)=2.76mol$

The chemical equation for the reaction of sulfur and fluorine gas follows:

$S(g)+3F_2(g)\rightarrow SF_6(g)$

By Stoichiometry of the reaction:

3 moles of fluorine gas reacts with 1 mole of sulfur

So, 2.76 moles of fluorine gas will react with = $(1)/(3)* 2.76=0.92mol$ of sulfur

As, given amount of sulfur is more than the required amount. So, it is considered as an excess reagent.

Thus, fluorine gas is considered as a limiting reagent because it limits the formation of product.

Moles of excess reagent (sulfur) left = 1.56 - 0.92 = 0.64 moles

Now, calculating the mass of sulfur from equation 1, we get:

Molar mass of sulfur = 32 g/mol

Moles of sulfur = 0.64 moles

Putting values in equation 1, we get:

$0.64mol=\frac{\text{Mass of sulfur}}{32g/mol}\n\n\text{Mass of sulfur}=20.48g$

Hence, the mass of excess reagent left is 20.48 g

The mole number of 50 g S is 1.563 mol. 105.0 g F2 is 2.763 mol. The ratio of S and F2 is 1:3. So the excess one is S. And mass left is 0.642*32=20.52 g.

What type of bond is this combination most likely to form?

Answers

Sodium is a group 1 element with atomic number 1. It has 11 electrons. It is soft reactive metal. It has 1 valence electron.

Fluorine is a group 7 element, a hologen with 7 valence electron. It is a most reactive non metal.

When sodium react with fluorine, ionic bond is formed in the resulting compound sodium fluoride.

One sodium and fluorine each totaling 2 atoms are enough to make the bond.

As the bond is formed, both atoms have octet structure. That is they each have 8 electrons on their outermost shells.

The positive charge on sodium indicates that sodium had lost 1 electron to fluorine atom.

The negative charge on fluorine ion indicates that fluorine atom had gained 1 electron from sodium atom to form negative ion.

The name of the compound is sodium fluoride with formula NaF.

brainliest please <3

Ayala is making salad dressing. She mixes oil and vinegar in a blender until a smooth consistency is formed. Explain whether this is a heterogeneous or a homogeneous mixture and why.

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Answer: The mixture formed will be heterogeneous mixture.

Explanation: When we mix oil and vinegar and blend it together to form a smooth mixture, the final mixture will still be heterogeneous in nature.

As we know that vinegar is a solution of acetic acid in water, which is polar in nature and oil is non-polar in nature.

When, we mix polar compound with a non-polar one, the resulting mixture may mix for a certain time, but after a time, we will be able to see the two layers in a mixture.

And heterogeneous mixtures are defined as the mixtures in which there is a distinct physical boundary present between the solutions in a mixture.

Hence, the mixture of oil and vinegar is a heterogeneous mixture.

Sample Response: A homogeneous mixture can only form when one of the substances can dissolve the other one. Oil and water cannot dissolve each other, so they must form a heterogeneous mixture with small particles of vinegar dispersed throughout the oil, yet not dissolved.

Explanation: Hope this Helps!

29. Some physical changes involve chemical reactions.
TRUE
FALSE

Answers

True. Some physical changes involve chemical reactions. Ice melting is an example of a chemical change in matter

"Each value below represents a different aqueous solution at 25 °C. Classify each solution as acidic, basic, or?Are the following acidic, basic or nuetral? pOH=3.37 pOH=11.40 [h+]=3.8x10^-4 [h+]=5.8x10^-8 [OH-]=3.5x10^-12 [OH-]=6.6x10^-3 [h+]=1.0x10^-7 pOh=7 pH=5.11 pH=12.94"

Answers

Final answer:

The solutions having pOH=3.37, [h+]=3.8x10^-4 and pH=5.11 are acidic. Solutions with pOH=11.40, [OH-]=6.6x10^-3 and pH=12.94 are basic. The solution with [h+]=1.0x10^-7 is neutral. The solutions with [h+]=5.8x10^-8 and [OH-]=3.5x10^-12 are mildly acidic and basic respectively.

Explanation:

In an aqueous solution at 25 °C, the pH and pOH scales are defined so that water, which is neutral, has a pH of 7.00 and a pOH of 7.00. If the pH is less than 7, the solution is acidic. If the pH is greater than 7, the solution is basic. Hence, solutions with pOH=3.37 and [h+]=3.8x10^-4 are acidic, as they would have a pH lower than 7. The solutions with pOH=11.40, [OH-]=6.6x10^-3 and pH=12.94 are basic, as they would have a pH higher than 7. The solution with [h+]=1.0x10^-7 is neutral as it has a pH of 7. The solutions with [h+]=5.8x10^-8 and [OH-]=3.5x10^-12 are slightly acidic and basic respectively due to being close to the pH of 7. The solution with pH=5.11 is acidic as it's less than 7.

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Final answer:

The given solutions can be classified based on pH, pOH, [H+] and [OH-]. Based on these values, they are categorised as acidic, basic, or neutral.

Explanation:

The values provided are measures of the concentration of Hydronium ions [H+], hydroxide ions [OH-], pH, and pOH, which help determine whether a solution is acidic, basic, or neutral. At 25 degrees Celsius, a neutral solution has pH = 7, pOH=7, [H+] = 1.0x10^-7, and [OH-] = 1.0x10^-7. If the pH or [H+] is less than 7, or pOH or [OH-] is greater than 7, the solution is acidic. If the pH or [H+] is greater than 7, or pOH or [OH-] is less than 7, the solution is basic.

Applying this for each solution: pOH=3.37, acidic; pOH=11.40, basic; [H+]=3.8x10^-4, acidic; [H+]=5.8x10^-8, acidic; [OH-]=3.5x10^-12, acidic; [OH-]=6.6x10^-3, basic; [H+]=1.0x10^-7, neutral; pOH=7, neutral; pH=5, acidic; pH=12.94, basic.

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