Answer
81.94 m
Explanation
The centripetal force of an object moving in a circular path is given by:
F = mv²/r Where m is the mass of the object, v is the constant velocity and r is the radius of the curve.
F = mv²/r
3,300 = (1600×13²)/r
3,300 = 270,400/r
r = 270,400/3,300
= 81.94 m
b. the distance a spring stretches has nothing to do with how much force is applied to it.
c. as the force on a spring increases, the distance it stretches increases.
d. as the force on a spring increases, the distance it stretches decreases.
Answer: option c. as the force on a spring increases, the distance it stretches increases.
Explanation:
Hooke's Law relates the force (F) applied on the spring and extension (x) of the spring:
F = - k x
Where, k is the spring constant.
as the force on a spring increases, the distance it stretches increases but it is limited by its elastic limit. The negative sign means that spring force is a restoring force which means that the stretch of the spring is in opposite direction to force.
with a 4.63 N force at a 63.0° angle.
What is the force of friction on the
toy?
(Hint: You do NOT need to know the
coefficient of friction.)
The force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.
A force called friction prevents one solid object from rolling or sliding over another. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion.
Given parameters:
mass of the toy dog: M = 0.398 kg.
Applied force: F = 4.63 N.
Angle of application of force: θ = 63.0°
Hence, horizontal component of applied force = F cosθ
= 4.63 × cos63.0° N
= 2.10 N.
As the child drags a 0.398 kg toy dog across flat ground at constant speed, this component of applied force is nullified by force of friction.
Hence, the force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.
Learn more about friction here:
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Answer:
-2.1 N
Explanation:
Answer:
1500N
Explanation:
we have ,
w= f*d
45,000 =f * 30
f=45000/30
f=1500N..
The free-body diagram of your question is; 2 downward forces (253 kg mass of barbell & 133 kg body mass of Kurlovich) acting together on a point supported by 2 upward forces as normal forces exerted by Kurlovich's feet.
Solving the normal forces exerted by 2 feet :
Summation of Forces Vertical = 0
2 Dowwnard Forces = 2 Upward Forces (2F)
253 + 133 = 2F
2F = 386 Kgs
F = 386 / 2
F = 193 Kgs (Normal Force Exerted by Each Foot)
To calculate the normal force exerted on each of Vladimir Kurlovich's feet while lifting the barbell, we need to consider the weights of Kurlovich and the barbell. The normal force is equal to the sum of the two weights.
To calculate the normal force exerted on each of Vladimir Kurlovich's feet while lifting the barbell, we need to consider the weight of Kurlovich and the weight of the barbell. The normal force is equal to the sum of Kurlovich's weight and the weight of the barbell, as it balances the gravitational force pulling them downwards. Kurlovich's weight can be calculated using his mass and the acceleration due to gravity, which is approximately 9.8 m/s².
Step 1:
Calculate Kurlovich's weight:
Mass = 133 kg
Acceleration due to gravity = 9.8 m/s²
Weight = Mass × Acceleration due to gravity
Weight = 133 kg × 9.8 m/s²
Step 2:
Calculate the weight of the barbell:
Mass = 253 kg
Acceleration due to gravity = 9.8 m/s²
Weight = Mass × Acceleration due to gravity
Weight = 253 kg × 9.8 m/s²
Step 3:
Calculate the normal force exerted on each foot:
Normal force = Kurlovich's weight + Barbell's weight
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