Explain how paper chromatography could be used to separate a mixture of different coloured inks

Answers

Answer 1

Answer: The mobile phase is a suitable liquid solvent or mixture of solvents. You probably used paper chromatographyas one of the first things you ever did in chemistry to separate out mixturesof coloured dyes - for example, the dyes which make up a particular ink

I hope that this answer helps you out

Related Questions

Which statement correctly compares an atom of an alkali metal with an atom of the alkaline earth metal next to it on the periodic table? aThe alkali metal atom forms a +1 ion, while the alkaline earth metal atom forms a +2 ion. bThe alkali metal atom forms a +2 ion, while the alkaline earth metal atom forms a +1 ion. cThe alkali metal atom has one less shell of electrons than the atom of the alkaline earth metal. dThe alkali metal atom has one more shell of electrons than the atom of the alkaline earth metal.
how does the presence of a strong electrolyte in solution affect the colligative properties of a solution when compared to the same number of moles of a nonelectrolyte solute?
Compare and contrast how observations and results can be used tosupport a conclusion to an experiment.
What is the daughter nucleus produced when 63 Zn undergoes electron capture? Replace each question mark with the appropriate integer or symbol.
A Carbon-10 nucleus has 6 protons and 4 neutrons. Through radioactive beta decay, it turns into a Boron-10 nucleus, with 5 protons and 5 neutrons, plus another particle. What kind of additional particle, if any, is produced during this decay

Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is 2.5 x 10-14. Calculate the molar solubility of Cd(OH)2 when buffered at a pH = 12.30. The Ksp for Cd(OH)2 is a.2.5 x 10-14 M.
b. 8.5 x 10-6 M
c. 6.3 x 10-11 M
d. 1.3 x 10-12 M
e. 5.0 x 10-2 M
f. 1.8 x 10-5 M

Answers

Answer:

c. 6,3x10⁻¹¹M

Explanation:

The solubility of a buffer is defined as the concentration of the dissolved solid in a saturated solution. For the Cd(OH)₂, solubility is:

[Cd²⁺] = S

The dissolution of Cd(OH)₂ is:

Cd(OH)₂ ⇄ Cd²⁺ + 2OH⁻

And the ksp is defined as:

ksp = [Cd²⁺][OH⁻]²

As ksp = 2,5x10⁻¹⁴ and [OH⁻] at pH=12,30 = 10^-(14-12,30) = 0,01995M

2,5x10⁻¹⁴ = [Cd²⁺]×(0,01995M)²

[Cd²⁺] = 6,3x10⁻¹¹M

That means solubility is c. 6,3x10⁻¹¹M

I hope it helps!

Final answer:

The molar solubility of Cd(OH)2 when buffered at a pH of 12.30 can be calculated using the concept of hydrolysis. The correct answer is 6.3 x 10^(-11) M.

Explanation:

To calculate the molar solubility of Cd(OH)2 when buffered at a pH of 12.30, we need to use the concept of hydrolysis. Cd(OH)2 is a slightly soluble salt that undergoes hydrolysis in aqueous solution. At a high pH value, OH- ions react with water to form more OH- ions, shifting the equilibrium towards the hydrolysis reaction.

First, we write the balanced equation for the hydrolysis reaction: Cd(OH)2(s) ⇌ Cd2+(aq) + 2OH-(aq)
Since OH- is being produced, we can assume that the concentration of OH- is much greater than that of Cd2+. Therefore, we can ignore the concentration of Cd2+ when calculating the solubility product (Ksp).
Next, we use the equation for the hydrolysis reaction to write the expression for the solubility product constant (Ksp): Ksp = [Cd2+][OH-]^2
The concentration of OH- ions in a basic solution is related to the pH by the equation: pOH = 14 - pH
Using this equation, we can calculate the pOH of the buffered solution: pOH = 14 - 12.30 = 1.70
Then, we convert the pOH back to OH- concentration: [OH-] = 10^(-pOH) = 10^(-1.70)
Finally, we substitute the calculated [OH-] into the expression for Ksp to solve for the molar solubility of Cd(OH)2: [Cd(OH)2] = sqrt(Ksp / [OH-]^2)

After performing the calculations, the molar solubility of Cd(OH)2 when buffered at a pH of 12.30 is approximately 6.3 x 10^(-11) M. Therefore, the correct answer is option c. 6.3 x 10^(-11) M.

Learn more about Molar solubility of Cd(OH)2 here:

brainly.com/question/30905557

#SPJ11

1. Write the structural formulas and give IUPAC names for all isorneric alcohols of molecular formulaС4Н9OH

Answers

Explanation:

Butanol (С4Н9OH)

Structural formula is :-

CH3-CH2-CH2-CH2-OH

Which is not a product of the fractional distillation of petroleum?A) Gasoline
B) Jet Fuel
C) steel

Answers

Answer:
Option-C, STEEL is not a product of the fractional distillation of petroleum.

Explanation:
Petroleum is the mixture of Hydrocarbons *carbon and hydrogen containing compounds) present beneath the Earth's surface. Petroleum is formed from the remains of animals and plants beneath earth's surface in an anaerobic conditions.
Petroleum contains from small hydrocarbons (gases) to medium (liquids) and long chain hydrocarbons (Solids). These hydrocarbons are separated from each other by Fractional Distillation method (separation due to difference in boiling points)
Gasoline is a derivative of one of the fraction of petroleum used in internal combustion engines.
Jet Fuel is also derived from Kerosene and Naphtha fractions of petroleum.
While, Steel is inorganic Alloy (mixture of metals) composed of mainly Iron, Carbon and other elements.

What mass of CO2 (in kilograms) does the combustion of a 16-gallon tank of gasoline release into the atmosphere? Assume the gasoline is pure octane (C8H18) and that it has a density of 0.70 g/mL.Express your answer in kilograms to two significant figures.

Answers

Mass of CO₂ = 1.3 x 10⁵ kg

Further explanation

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

2C₈H₁₈ + 25O₂⇒ 16CO₂ + 18H₂O

16 gallon = 60566,6 ml

mass C₈H₁₈ :

$\tt mass=\rho* V\n\nmass=0.7* 60566.6=42396.62~g$

mol C₈H₁₈ :

$\tt MW=114.232~g/mol\n\nmol=(42396.62)/(114.232)=371.145$

mol CO₂ :

$\tt (16)/(2)* 371.145=2969.159$

mass CO₂ :

$\tt =2969.159* 44(MW~CO_2)=130642.996~g=1.3* 10^5~kg$

Please help me and promise I will mark as brainiest I need it in ISEF please how much energy does the vehicle hydrogen fuel cell need to break hydrogen into ions ?!

Answers

Answer: A typical hydrogen fuel cell produces 0.5 V to 0.8 V per cell. To increase the voltage individual cells can be connected in series.

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1860 N to the right. The forces acting on the crate are

Answers

are radioactive waves , hope this helps

Other Questions

The steps in a reaction mechanism are as follows. Which species is acting as a catalyst? Step 1: Ag+(aq) + Ce4+(aq) <-----> Ag2+(aq) + Ce3+(aq) Step 2: Tl+(aq) + Ag2+(aq) -----> Tl2+(aq) + Ag+(aq) Step 3: Tl2+(aq) + Ce4+(aq) -----> Tl3+(aq) + Ce3+(aq)

In what way(s) is(are) the structure of water similar to that of CHCl3? In what way is the structure of water different from that of CHCl3?

What is the pOH of a solution with a [OH^ - ] of 10^ -11?

The rate constant of the elementary reaction CH3OCH3(g) CH4(g) +CH2O(g) is k = 8.33×10-6 s-1 at 427°C, and the reaction has an activation energy of 245 kJ mol-1. (a) Compute the rate constant of the reaction at a temperature of 545°C. s-1 (b) At a temperature of 427°C, 8.32×104 s is required for half of the CH3OCH3 originally present to be consumed. How long will it take to consume half of the reactant if an identical experiment is performed at 545°C?