MATHEMATICS HIGH SCHOOL

Choose the equation of the horizontal line that passes through the point (-2,-1). A.) y = -1

B.) y = -2

C.) x = -2

D.) x = -1

Answers

Answer 1

Answer:

Answer:

A.) y = -1

Step-by-step explanation:

The equation of a horizontal line is ...

y = constant

To make that line go through the point (x, y) = (-2, -1), the constant must match the y-coordinate of the point: -1.

y = -1

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Please help brainiest will give you!Find the slope of it!A. -3B. -1/3C. 1/3D. 3

How do you figure out what is 1/4 of 10.

Answers

You can multiply 10 by 1/4 or .25

10x.25=2.5

as you know ( i think) of means to multiply so do 1 over 3 1/3 times 10 over 1 (10/1
because 10/1 =10 hope i helped :)

Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist.X + 3y = 9

3x –y = 7

Answers

Let's write both equations in the standard form of [ y = mx + b ],
and then see what we can tell about their graphs.

First equation:   x + 3y = 9
Subtract 'x' from each side: 3y = -x + 9
Divide each side by 3: y = -1/3 x + 3
This line crosses the y-axis at y=3, and it has a slope of -1/3 .

Second equation:    3x - y = 7
Subtract 3x from each side: -y = -3x + 7
Multiply each side by -1 : y = 3x - 7
This line crosses the y-axis at y=-7, and it has a slope of 3 .

-- The two lines have different slopes, so they're not parallel.
They must intersect somewhere.
-- They're not the same line, so they can't 'intersect' everywhere.
-- They have slopes of -1/3 and 3 . Their slopes are negative reciprocals,
so the lines are perpendicular.

All of this says that the two equations can't have no solution, and they can't have
infinitely many solutions. They must have one and only one solution.
I guess that means that it's our job to find it now.

============================================

For each equation, the "mx + b" form is equal to 'y' . Since these two things are
equal to the same thing, they must be equal to each other, and we can write:

   -1/3 x + 3 = 3x - 7

Multiply each side by 3 : -x + 9 = 9x - 21

Add 'x' to each side: 9 = 10x - 21

Add 21 to each side:    30 = 10x

Divide each side by 10 : 3 = x

The intersection/solution is some place where x=3 .
Let's put that back into the first equation:

   x + 3y = 9

   3 + 3y = 9

Subtract 3 from each side:   3y = 6

Divide each side by 3 : y = 2

And there's your solution: x = 3
   y = 2
On the graph, the two lines intersect at the point (3, 2) .

We used the first equation to get part of the solution, so we can't use
the same equation to check the solution. We'll put our solution into the
second equation, and see whether it checks there:

   3x - y = 7

3(3) - (2) = 7

   9 - 2 = 7

   7 = 7 yay !

The two equations have one and only one solution,
and it is definitely x = 3, y = 2 .

Substitution or Elimination

im using substitution

1. solve for variable for one of the equation

x + 3y = 9

x = 9 - 3y

2. Substitute the variable into one of the equation

3 (9-3y) - y = 7

27 - 9y - y = 7

27 - 10y = 7

-10y = 7 - 27

-10y = -20

y = 2

3. sub y = 2 into any equation to find x

3x - 2 = 7

3x = 7 -2

3x = 5

x = 5/3

X+3(2) = 9

x + 6 = 9

x = 9-6

x= 3

therefore there are two solutions x = 3 and x= 5/3

Which expression represents the series 1+5+25+125+625?

Answers

it is a geometric sequence
an=a1(r)^(n-1)
a1=first term
r=common ratio
n=which term
first term is 1
common ratio is 5
an=1(5)^(n-1)

that is the equatin/formulf for the nth term

if you want a summation formula of the sequence to the nth term
Sn= $(a1(1-r^(n)))/(1-r)$
in this case
Sn= $(1(1-5^(n)))/(1-5)$ or
Sn= $(1-5^(n))/(-4)$
so in this case
up to 5th term

S5= $(1-5^(5))/(-4)$
S5= $(1-3125)/(-4)$
S5= $(-3124)/(-4)$
S5=781

anyway
$a_(n)=(5)^(n-1)$ is the nth term
and
Sn= $(1-5^(n))/(-4)$ is the summation up to the nth term

1(5)^0 + 1(5)^1 + 1(5)^2...

The expression representing the series would be

f(x) = 5^(x-1)

Carly bought a new house for $125,000. The value of the house appreciates approximately 3.5% each year. What will be the value of the house after 10 years?

Answers

This problem can be solved using the formula for interest which is: F = P (1 + i)^n where:

F = future value
P = principal value
i = interest per year
n = interest period

Since we are already provided with the values of each, direct substitution should be done. This is shown below:

F = P(1 + i)^n
F = 125000(1 + 0.035)^10
F = 176324.85

Therefore, the value of the house after 10 years will be $176,324.85

Suppose Richard walks 1 kilometer every 10 minutes.how many meters further can he walk in 1 hour at this new rate?explain how you found your answer.

Answers

This Problem Is Actually Quite Simple If You Look. There Are 60 Minutes In One Hour. A Proportional Relationship Will Help.
10 60
---- = ---
1 X

10X = 60.
-------------
10 10
X = 6.

Since X = 6, That Means Richard Can Walk 6 kilometers In One Hour. :D
I Hope This Helps You!

The cost, in dollars, of parking a car in a busy downtown area for h hours is $10 + $3h.Which statement is correct?
A.
For every hour the car is parked, the cost increases by $10.

B.
For every hour the car is parked, the cost increases by $7.

C.
For every hour the car is parked, the cost increases by $13.

D.
For every hour the car is parked, the cost increases by $3.