What is the vapor pressure of the pure solvent if the vapor pressure of a solution of 10 g of sucrose (C6H12O6) in 100 g of ethanol (C2H6O) is 55 mmHg?

Answers

Answer 1
Answer:

Answer:

56.4 mmHg

Explanation:

Given:

Vapor pressure of the solution, P solution = 55 mmHg

The mass of sucrose (C₆H₁₂O₆) = 10 g

Also, Molar mass of sucrose (C₆H₁₂O₆) = 180 g/mol

So, moles = Given mass/ molar mass

Hence, moles of sucrose in the solution = 10 g / 180 g/mol = 0.05556 mol

Given that: Mass of ethanol = 100 g

Molar mass of ethanol = 46 g/mol

Hence, moles of ethanol = 100 g / 46 g/mol = 2.174 mol

Mole fraction of solvent, ethanol is:

X ethanol = 2.174 mol / (2.174 + 0.05556) mol = 0.975

Applying Raoult's Law

P solution = X ethanol*P° ethanol

=> P° ethanol  = P solution / X ethanol  = 55 mmHg / 0.975 = 56.4 mm Hg

Answer 2
Answer:

Explanation:

The given data is as follows.

Vapor pressure of the solution (P_(solution)) = 55 mm Hg

Mass of sucrose = 10 g

Molar mass of sucrose = 180 g/mol

Therefore, moles of sucrose present into the solution will be calculated as follows.

             No. of moles = (mass)/(molar mass)

                                   = (10 g)/(180 g/mol)

                                   = 0.055 mol

Mass of ethanol is given as 100 g and its molar mass is 46 g/mol.

Hence, number of moles of ethanol will be calculated as follows.

            No. of moles = (mass)/(molar mass)

                                  = (100 g)/(46 g)

                                  = 2.174 mol

As mole fraction = (no. of moles)/(total number of moles)

Hence, mole fraction of etahnol will be calculated as follows.

            X_(ethanol) = (no. of moles)/(total number of moles)

                                              = (2.174)/(2.174 + 0.055)

                                              = 0.975

Now, using Raoult's Law  as follows.

              P_(solution) = X_(ethanol) * P_(ethanol)

             P_(ethanol) = (P_(solution))/(X_(ethanol))

                                    = \frac{55 mm Hg}}{0.975}}

                                    = 56.4 mm Hg

Thus, we can conclude that the vapor pressure of the pure solvent is 56.4 mm Hg.


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Answers

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Hello,

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Answers

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Answers

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Hello there!

Explanation:

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HELP ASAPFor the reaction 2H2(g) + S2(g)<---> 2H2S(g), determine the equilibrium constant at 700oC if at this temperature, the equilibrium concentrations are as follows:
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Answers

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Answers

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