According to reference table J, which of these metals would react most readily with 1.0 M HCl to produce H2(g)
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Molecules in a sample of NH3(l) are held closely together by intermolecular forces(1) existing between ions(2) existing between electrons(3) caused by different numbers of neutrons(4) caused by unequal charge distribution
The average kinetic energy of water molecules is greatest in which of these samples?(1) 10 g of water at 35°C(2) 10 g of water at 55°C(3) 100 g of water at 25°C(4) 100 g of water at 45°C
Answer the following questions: On a 10-fold dilution of a weak acid, the pH will ______________ . On a 10-fold dilution of a weak base, the pH will ______________. If one adds a very small amount of strong base to a buffered solution, the pH will _______________. Can you make a buffer using a strong acid
Calculate the pH of a solution in which [OH–] = 4.5 × 10–9M.8.356.114.945.65 - this one is correct
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AgNO3 + NaCl ⇒ NaNO3 + AgCl(s)
The moles of Na+ present:
0.5 L * 0.001 mol/L
= 5 x 10⁻⁴ mol
Moles of Ag+ present:
0.5 * 0.02
= 0.01 mol
The limiting reactant is Na
Therefore, the moles of Ag reacted:
5 x 10⁻⁴
AgCl is insoluble in water; therefore, the AgCl formed will precipitate
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Answer:
3,495.02
Explanation: TRY THAT FOR AN ANSWER
increases to 100 times the original concentration
decreases to 1/100 of the original concentration
decreases to 1/2 of the original concentration
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Answer: The correct answer is 'increases to 100 times the original concentration'.
Explanation:
let the initial pH be x
The original concentration of initially present be y
...(1)
Final concentration of when pH reduced by 2 be z
...(2)
Putting the value of 'x' from (1) into (2) we get :
When pH of a solution decreases by 2.0, hydronium ion concentration of the solution increases to 100 times the original concentration
Answer:
B, is the answer
B. The greater the dipole moment, the stronger the dipole-dipole forces.
C. The polarizability of elongated molecules is greater than that of compact, more spherical molecules.
D. London dispersion forces weaken in the order Xe < Kr < Ar
E. Hydrogen bonding leads to the strongest intermolecular forces.
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Answer:
D. London dispersion forces weaken in the order Xe < Kr < Ar is an incorrect order, the correct order of London dispersion forces weaken in the order Ar < Kr < Xe.
Explanation:
A. Dispersion forces are present in all molecular substances.
is a correct statement London dispersion forces are weak intermolecular forces found in all molecular substances.
B. Clearly, greater the dipole moment, greater will be dipole-dipole forces. Hence true.
C) The polarizability of elongated molecules is greater than that of compact, more spherical molecules. The more elongated the molecule is more will be its ability to get polarized.
D. London dispersion forces weaken in the order Xe < Kr < Ar is an incorrect order, the correct order of London dispersion forces weaken in the order Ar< Kr < Xe.
E) Hydrogen bonding leads to the strongest intermolecular forces is also a correct statement. Hydrogen bonding leads to increase in boiling point.
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Answer:
i need help with that too.
Explanation:
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Answer:
6.64 moles of carbon.
Explanation:
Given data:
Number of moles of C = ?
Number of moles of CCl₂F₂ = 6.64 mol
Solution:
In one mole ofCCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.
In 6.6 moles of CCl₂F₂ :
Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.
Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine
Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine
Answer: 6.64 moles
Explanation:
Number of moles of C = ?
number of moles of CCl₂F₂ = 6.64 mol
In one mole of CCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.
In 6.6 moles of CCl₂F₂ :
Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.
Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine
Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine