The barrel of a bicycle tire pump becomes quite warm during use. Explain the mechanisms responsible for the temperature increase.

Answers

Answer 1

Answer:

Answer:

The air heats up when being compressed and transefers heat to the barrel.

Explanation:

When a gas is compressed it raises in temperature. Assuming that the compression happens fast and is done before a significant amount of heat can be transferred to the barrel, we could say it is an adiabatic compression. This isn't exactly true, it is an approximation.

In an adiabatic transformation:

$P^(1-k) * T^k = constant$

For air k = 1.4

$P0^(-0.4) * T0^(1.4) = P1^(-0.4) * T1^(1.4)$

$T1^(1.4) = (P1^(0.4) * T0^(1.4))/(P0^(0.4))$

$T1^(1.4) = (P1)/(P0)^(0.4) * T0^(1.4)$

$T1 = T0 * (P1)/(P0)^(0.4/1.4)$

$T1 = T0 * (P1)/(P0)^(0.28)$

SInce it is compressing, the fraction P1/P0 will always be greater than one, and raised to a positive fraction it will always yield a number greater than one, so the final temperature will be greater than the initial temperature.

After it was compressed the hot air will exchange heat with the barrel heating it up.

Related Questions

In a refrigerator, heat is transferred from a lower-temperature medium (the refrigerated space) to a higher-temperature one (the kitchen air). Is this a violation of the second law of thermodynamics
If you are pouring a large concrete slab and wish to avoid random cracks caused by shrinkage, you would likely provideA. expansion jointsB. isolation jointsC. control jointsD. construction joints
Automobiles must be able to sustain a frontal impact. Specifically, the design must allow low speed impacts with little damage, while allowing the vehicle front end structure to deform and absorb impact energy at higher speeds. Consider a frontal impact test of a vehicle with a mass of 1000 kg. a. For a low speed test (v = 2.5 m/s), compute the energy in the vehicle just prior to impact. If the bumper is a pure elastic element, what is the effective design stiffness required to limit the bumper maximum deflection during impact to 4 cm? b. At a higher speed impact of v = 25 m/s, considerable deformation occurs. To absorb the energy, the front end of a vehicle is designed to deform while providing a nearly constant force. For this condition, what is the amount of energy that must be absorbed by the deformation [neglecting the energy stored in the elastic deformation in (a)? If it is desired to limit the deformation to 10 cm, what level of resistance force is required? What is the deacceleration of the vehicle in this condition?
Air is compressed in a piston-cylinder device. List three examples of irreversibilities that could occur
The dam cross section is an equilateral triangle, with a side length, L, of 50 m. Its width into the paper, b, is 100 m. The dam material has a specific gravity, SG, of 3.1. You may assume that the dam is loosely attached to the ground at its base, though there is significant friction to keep it from sliding.Is the weight of the dam sufficient to prevent it from tipping around its lower right corner?

A bathroom scale uses four internal strain gauges to measure the displacement of its diaphragm as a means for determining load. Four active gauges are used in a bridge circuit. The gauge factor is 2, and the gauge resistance is 120 Ω for each gauge. If an applied load to the diaphragm causes a tensile strain on R1 and R4 of 40 x 10-6, while gauges R2 and R3 experience a compressive strain of 40 x 10-6, estimate the bridge deflection voltage. The supply voltage is 5 V. a,b,c or d? a.400 x 10-6 V

b.600x10-6V

c.800x10-6V

d.1000 x 10-6 V

Answers

Answer:

a.400 x 10-6 V

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

Logical variables: Running late? Complete the tunction RunningLate such that the logical variable on Time is true if no Traffic is true and gasEmpty is false. Ex >> n°Traffic = true ; >> gasEmpty-false; >onTime - Runninglate(noTraffic,gasEmpty) logical Your Function B Save C Reset EE MATLAB Documentation 1 function onTime - RunningLate (noTraffic,gasEmpty) 2 % complete the logical expression to the right of . using the variables n°Traffic and gasEmpty 4 onTime - 6 end Code to call your function C Reset 1 noTraffic true; gasEmpty true; 2 onTime-Runninglate(noTraffic, gasEmpty)

Answers

The program was written in MATLAB. The program source file has an incomplete function, that needs to be completed.

Complete the function with the following code segment

function onTime = RunningLate (noTraffic, gasEmpty)

onTime = ((noTraffic) & not(gasEmpty))

end

The following, should be noted about the above code segment

The first line declares/defines the function; The function name is RunningLate, and it receives noTraffic and gasEmpty as its parameters
On the second line; If noTraffic is true and gasEmpty is false, the function will return true
If otherwise, it will return false.

I've added the image of the complete question (in a more presentable format), as an attachment.

As stated above;

After running the complete program; onTime will be true if noTraffic and gasEmpty are true and false, respectively.

Answers

Answer:

Viscoelastic stress relaxation

Viscoelastic creep

Explanation:

Viscoelastic stress refers to the reduction of tensile stress with the relaxation time that occurs when the body is kept at a certain length under tensile stress. The purpose of this study was to demonstrate viscoelastic stress relaxation
Therefore, when the viscous tension stress occurs, the pressure decreases due to the steady-state stress of the phases.
When under constant pressure, the viscoelastic material experiences a time-dependent increase in pressure. This phenomenon is called viscoelastic creep.
Therefore the phase constant pressure decreases when there is relaxation in the viscoelastic stress

Peter the postman became bored one night and, to break the monotony of the night shift, he carried out the following experiment with a row of mailboxes in the post office. These mailboxes were numbered 1 through 150, and beginning with mailbox 2, he opened the doors of all the even-numbered mailboxes, leaving the others closed. Next, beginning with mailbox 3, he went to every third mail box, opening its door if it were closed, and closing it if it were open. Then he repeated this procedure with every fourth mailbox, then every fifth mailbox, and so on. When he finished, he was surprised at the distribution of closed mailboxes. Write a program to determine which mailboxes these were.

Answers

Answer:

//This Program is written in C++

// Comments are used for explanatory purpose

#include <iostream>

using namespace std;

enum mailbox{open, close};

int box[149];

void closeAllBoxes();

void OpenClose();

void printAll();

int main()

{

closeAllBoxes();

OpenClose();

printAll();

return 0;

}

void closeAllBoxes()

{

for (int i = 0; i < 150; i++) //Iterate through from 0 to 149 which literarily means 1 to 150

{

box[i] = close; //Close all boxes

}

void OpenClose()

{

for(int i = 2; i < 150; i++) {

for(int j = i; j < 150; j += i) {

if (box[j] == close) //Open box if box is closed

box[j] = open;

else

box[j] = close; // Close box if box is opened

}

// At the end of this test, all boxes would be closed

}

void printAll()

{

for (int x = 0; x < 150; x++) //use this to test

{

if (box[x] = 1)

{

cout << "Mailbox #" << x+1 << " is closed" << endl;

// Print all close boxes

}

Explanation:

A test bottle containing just seeded dilution water has its DO level drop by 0.8 mg/L in a 5-day test. A 300 mL BOD bottle filled with 30 mL of wastewater and the rest with seeded dilution water experiences a drop of 7.3 mg/L in the same period (5-day). Calculate the BOD5 of the wastewater.

Answers

Answer:

BOD_5 = =65.8 mg/l

Explanation:

dilution water DO level = 0.8 m/l

BOD level drop to 7.3 mg/l

we know that BOD at 5th day can be clculated by using following relation $BOD_5 = ((D_1 -D_2) -(B_1-B_2)(1-P))/(P)$

$D_1 -D_2$ - DO drop in BOD bottle

$B_1-B_2$ - dilution water drop

P= 30/300 = 0.1

$BOD_5 = ((7.3) -(0.8)(1-0.1))/(0.1)$

$BOD_5 = =65.8 mg/l$

A refrigeration system was checked for leaks. The system temperature and surroundings were 75°F when the system was charged with nitrogen to 100 psig. The temperature then dropped to 50°F. What should the pressure be if no nitrogen has escaped?A) 9 psig
B) 94 psig
C) 100 psig
D) 90 psig

Answers

The temperature and pressure of an ideal gas are directly proportional

The pressure of the system should be in the range B) 94 psig

The given refrigerator parameters are;

The temperature of the system and the surrounding, T₁ = 75 °F = 237.0389 K

The pressure to which the system was charged with nitrogen, P₁ = 100 psig

The temperature to which the system dropped, T₂ = 50 °F = 283.15 K

The required parameter;

The pressure, P₂, of the system at 50°F

Method:

The relationship between pressure and temperature is given by Gay-Lussac's law as follows;

At constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin

Mathematically, we have;

$(P_1)/(T_1) = \mathbf{(P_2)/(T_2)}$

Plugging in the values of the variables gives;

$\mathbf{(100 \ psig)/(297.0389)} = (P_2)/(283.15)$

Therefore;

$P_2 = \mathbf{283.15 \, ^(\circ)F * (100 \ psig)/(297.0389\ ^(\circ)F) \approx 95.3 \, ^(\circ)F}$

The closest option to the above pressure is option B) 94 psig

Learn more about Gay-Lussac's law here;

brainly.com/question/16302261

B 94 psig because the temperature dropped too

Other Questions

A 15. μF capacitor is connected to a 50. V battery and becomes fully charged. The battery is removed and a slab of dielectric that completely fills the space between the plates is inserted. If the dielectric has a dielectric constant of 5.0, what is the voltage across the capacitor's plates after the slab is inserted?

Write a Python program that does the following. Create a string that is a long series of words separated by spaces. The string is your own creative choice. It can be names, favorite foods, animals, anything. Just make it up yourself. Do not copy the string from another source. Turn the string into a list of words using split. Delete three words from the list, but delete each one using a different kind of Python operation. Sort the list. Add new words to the list (three or more) using three different kinds of Python operation. Turn the list of words back into a single string using join. Print the string.

A multipurpose transformer has a secondary coil with several points at which a voltage can be extracted, giving outputs of 5.60, 12.0, and 480 V. (a) The input voltage is 220 V to a primary coil of 230 turns. What are the numbers of turns in the parts of the secondary used to produce the output voltages

8. Removing damage by tapping it out with a hammerand dolly is often referred to as(A) contouring(B) roughing out(C) forming(D) tapping out