When an ion‑selective electrode for X+ was immersed in 0.0482 M XCl, the measured potential was 0.0460 V . What is the concentration of X+ when the potential is 0.0610 V ? Assume that the electrode follows the Nernst equation, the temperature is at 25 °C, and that the activity coefficient of X+ is 1.

Answers

Answer 1
Answer:

Final answer:

To find the concentration of X+ at a potential of 0.0610V, use the Nernst equation which describes the electrochemical potential of a system. Given the initial concentration of X+ and its potential, rearrange the equation to solve for the concentration of X+ at the new potential.

Explanation:

The problem given can be solved using the Nernst equation, which relates the reduction potential of an electrochemicalreaction (half-cell or full cell reaction) to the standard electrode potential, temperature, and the activities of the chemical species undergoing the reduction.

The Nernst equation at 25 °C can be simplified as:

E = E° - (0.059/n) log [Cl^- /[X^+]

Where E is the electrode potential, E° is the standard electrode potential, n is the number of electron transferred and [Cl^- /[X^+] is the ratio of ion activities. Since the ion's activity coefficient is 1, we can treat [X^+] as the concentration of X^+.

If you apply this equation, using the given potentials and known initial concentration of X^+, you can solve for the concentration of X^+ when the potential is 0.0610V.

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Answer 2
Answer:

Final answer:

The concentration of X+ can be calculated using the Nernst equation by substituting the initial and final potentials. By solving the equation, you can find the concentration of X+.

Explanation:

The concentration of X+ can be calculated using the Nernst equation. The Nernst equation relates the potential of a cell to the concentration of the ions involved.

The Nernst equation is given by:

E = Eº - (0.0592/n)log(Q)

Where E is the potential, Eº is the standard electrode potential, n is the number of electrons transferred, and Q is the reaction quotient.

In this case, the initial potential is 0.0460 V and the final potential is 0.0610 V. By substituting these values into the Nernst equation, you can solve for the concentration of X+.

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Answers

Answer:

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Explanation:

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Answers

Answer:

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Explanation:

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Answer:

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Explanation:

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Answers

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Explanation

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Answers

Answer: The concentration of KOH solution is 1.215 M

Explanation:

For the given chemical equation:

2KOH(aq.)+H_2SO_4(aq.)\rightarrow K_2SO_4(aq.)+2H_2O(l)

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

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n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\nM_1=1.50M\nV_1=16.2mL\nn_2=1\nM_2=?M\nV_2=40.0mL

Putting values in above equation, we get:

2* 1.50* 16.2=1* M_2* 40.0\n\nM_2=(2* 1.50* 16.2)/(1* 40.00)=1.215M

Hence, the concentration of KOH solution is 1.215 M

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Answers

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Answers

Answer:

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Explanation:

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