Ne ( g ) effuses at a rate that is ______ times that of Cl 2 ( g ) under the same conditions.

Answers

Answer 1
Answer:

Answer: 1.88times as that of Cl2

Explanation:

According to Graham law of effusion , the rate of effusion is inversely proportional to the square root of the molar mass

Rate= 1/√M

R1/R2 =√M2/M1

Let the rate of diffusion of Ne= R1

And rate of diffusion of Cl2 = R2

M1 ,molar mass of Ne= 20g/mol

M2,molar mass of Cl2 =71g/mol

R1/R2 = √ (71/20)

R1/R2 = 1.88

R1= 1.88R2

Therefore the Ne effuses at rate that is 1.88times than that of Cl2 at the same condition.


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What is the molecular formula of each of the following compounds? Part A Empirical formula CHO2, molar mass = 180.0 g/mol

Answers

Answer:

C4H4O8

Explanation:

The molecular formula of a compound with empirical formula: CHO2 can be calculated as follows:

(CHO2)n = 180g/mol

{12 + 1 + 16(2)}n = 180

(12+1+32)n = 180

(45)n = 180

n = 180/45

n = 4.

The molecular formula = (CHO2)4

= C4H4O8

Classify each substance based on the intermolecular forces present in that substance.A. Hydrogen bonding, dipole dipole, and dispersion
B. Dipole dipole and dispersion only
C. Dispersion only
1. H2O
2. CH4
3. CO
4. CH2Cl

Answers

               Intermolecular forces

  1. When H2O- Hydrogen bonding, dipole-dipole, and also dispersion
  2. Then CH4- Dispersion only
  3. After that CO- Dispersion only
  4. Then CH2Cl- Dipole-dipole and also dispersion only

Explanation:

  • When Dipole-dipole interactions exist only in molecules that have a dipole moment such as water and also that dichloromethane.
  • After that Water experiences intermolecular hydrogen bonding in addition to dipole-dipole interaction and also that dispersion forces due to the O-H bond in the molecule.
  • Thus, Nonpolar compounds only have dispersion forces acting between their molecules.

Find out more information about dispersion here:

brainly.com/question/3224009

Answer:

H2O- Hydrogen bonding, dipole dipole, and dispersion

CH4- Dispersion only

CO- Dispersion only

CH2Cl- Dipole dipole and dispersion only

Explanation:

Dipole- dipole interactions exist only in molecules that have a dipole moment such as water and dichloromethane. Water experiences intermolecular hydrogen bonding in addition to dipole-dipole interaction and dispersion forces due to the O-H bond in the molecule.

Nonpolar compounds only have dispersion forces acting between its molecules.

Question 16 Unsaved Which of the following diagrams represents the correct cycling of gases?A) Photosynthesis O2 Respiration CO2
B) Respiration O2 photosynthesis CO2
C) Photosynthesis H2 Respiration O2
D) Respiration CO2 photosynthesis H2

Answers

the answer is A:

Photosynthesis release O2 (oxygen)

then animals use oxygen for respiration and release Co2

Final answer:

The correct answer is A) Photosynthesis O2 Respiration CO2. Photosynthesis converts CO2 to O2, which is then used in respiration to be converted back into CO2. Both processes together create a continuous cycle.

Explanation:

The correct diagram that represents the cycling of gases between photosynthesis and respiration is A) Photosynthesis O2 Respiration CO2. Through the process of photosynthesis, plants convert carbon dioxide (CO2) and sunlight into oxygen (O2) and glucose. Organisms, including the plants themselves, then use that oxygen for respiration, during which they convert the oxygen back into carbon dioxide. The glucose is used for energy. This continuous cycling plays a critical role in life on Earth.

Learn more about Cycling of gases here:

brainly.com/question/11267534

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Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---> C2H2(g) ΔH° = ??? kJ Given the following thermochemical equations: C2H2(g) + (5/2)O2(g) ---> 2CO2(g) + H2O(ℓ) ΔH° = -1,123 kJ C(s) + O2(g) ---> CO2(g) ΔH° = -340 kJ H2(g) + (1/2)O2(g) ---> H2O(ℓ) ΔH° = -211 kJ

Answers

Answer:

The enthalpy for given reaction is 232 kilo Joules.

Explanation:

C_2H_2(g) + (5)/(2)O_2(g)\rightarrow 2CO_2(g) + H_2O(l), \Delta H^o_(1) = -1,123 kJ...[1]

C(s) + O_2(g)\rightarrow CO2(g), \Delta H^o_(2) = -340 kJ..[2]

H_2(g) + (1)/(2)O_2(g)\rightarrow H_2O(l) ,\Delta H^o_(3) = -211 kJ..[3]

2C(s) + H_2(g)\rightarrow C_2H_2(g),\Delta H^o_(4) =?..[4]

2 × [2] + [3] - [1] ( Using Hess's law)

\Delta H^o_(4)=2* \Delta H^o_(2)+\Delta H^o_(3) - \Delta H^o_(1)

\Delta H^o_(4)=2* (-340 kJ) + (-211 kJ) - (-1,123 kJ)

\Delta H^o_(4)=232 kJ

The enthalpy for given reaction is 232 kilo Joules.

Write all of the allowed sét of quantum numbers for a 3p orbital

Answers

Answer:

Which of the following is a possible set of quantum numbers for a 3p orbital?

Since you are dealing with a 3p-orbital, your principal and angular momentum quantum numbers will be n=3 and l=1 .

What are four properties of water?

Answers

Answer:

Polarity

Cohesion  

Adhesion

High Specific Heat

Explanation: