A voltaic cell with an aqueous electrolyte is based on the reaction between Cd2 (aq) and Mg(s), producing Cd(s) and Mg2 (aq). Write half-reactions for the anode and cathode and then write a balanced cell reaction. Please include the states of matter in the equations.

Answers

Answer 1
Answer:

Answer:

Cd²⁺(aq) + 2 e⁻ → Cd(s)

Mg(s) → Mg²⁺(aq) + 2 e⁻

Cd²⁺(aq) + Mg(s) → Cd(s) + Mg²⁺(aq)

Explanation:

A voltaic cell is composed of two half-reactions:

Reduction (cathode): Cd²⁺(aq) + 2 e⁻ → Cd(s)

Oxidation (anode): Mg(s) → Mg²⁺(aq) + 2 e⁻

Cd²⁺ reduces to Cd (the oxidation number decreases from 2 to 0), whereas Mg oxidizes to Mg²⁺ (the oxidation number increases from 0 to 2). We can get the overall cell reaction by adding both half-reactions:

Cd²⁺(aq) + 2 e⁻ + Mg(s) → Cd(s) + Mg²⁺(aq) + 2 e⁻

Cd²⁺(aq) + Mg(s) → Cd(s) + Mg²⁺(aq)


Related Questions

Consider an element Z that has two naturally occurring isotopes with the following percent abundances: the isotope with a mass number of 19.0 is 55.0% abundant; the isotope with a mass number of 21.0 is 45.0% abundant. What is the average atomic mass for element Z?Average atomic mass of Z = [mass]
A reaction will be spontaneous only at low temperatures if both ΔH and ΔS are negative. For a reaction in which ΔH = −320.1 kJ/mol and ΔS = −86.00 J/K · mol. Determine the temperature (in °C) below which the reaction is spontaneous.
What makes physical change a physical change and a chemical change a chemical change
What two processes are occurring in this picture A.erosion and deposition B.weathering and deposition C.weathering and erosion
At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. What partial pressure of He would give a solubility of 0.730 M

What are the two formulas for the ions that's make up AgC2H3O2 bromide?

Answers

Answer:

KCI+AgC2H3O2

Explanation:

How many unpaid electrons are in 1s2 2s2 2p6 3s2 3p6

Answers

Answer:

As we can see, the first shell has its 2 electrons

the second shell has its 8 electrons

we know that the third shell also needs 8 electrons and we can see that the third shell also has 8 electrons.

Therefore, all the shells of this atom are filled and this atom is stable

So we can say that there are no unpaired electrons

Kindly mark Brainliest, thanks

Answer:

No unpaired electrons

Explanation:

This is because it is diamagnetic. Hope that helps:)

Identify the sample and analyte in each of the scenarios.(a) Determination of the lead content in paint. lead paint
(b) Analysis of the nitrate content of soil near a local water source. soil nitrate
(c) Measurement of the citric acid found in a lime.

Identify the following as either sample or analyte.
(1) lead
(2) paint chips
(3) soil
(4) nitrate
(5) lime wedge
(6) citric acid

Answers

Answer:

a) Analyte: lead. Sample: paint.

b) Analyte: nitrate. Sample: soil.

c) Analyte: citric acid. Sample: Lime

1) Lead: Analyte.

2) Paint chips: Sample.

3) Soil: Sample.

4) Nitrate: Analyte.

5) Lime wedge: Sample.

6) Citric acid: Analyte.

Explanation:

A sample is a portion of material selected from a larger quantity of material while an analyte is the chemical of the system that will be analysed.

Thus:

a) Analyte is lead while you must take a sample of paint to analyze this lead.

b) Analyte is the nitrate while sample must be soil.

c) Analyte is citric acid and lime is the sample

1) Lead: Analyte.

2) Paint chips: Sample.

3) Soil: Sample.

4) Nitrate: Analyte.

5) Lime wedge: Sample.

6) Citric acid: Analyte.

Calculate the mass of a sample of lead (cPb = 0.16 J/g℃) when it loses 200 J cooling from 75.0℃ to 42.0℃.

Answers

looses 299 please collins 75.0

4. define a tsunami

Answers

Answer:

A high wave caused by either an earthquake, submarine landslide, or other disturbance that occurs.

Explanation:

Answer:

a Big Big wave

Explanation:

A tsunami is a Big Big wave

Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0.6160959 kg, 3.225 mg, and 5480.7 g. The total mass of the samples should be reported as?

Answers

Answer:

6.1 kg

Explanation:

To obtain the total mass of the sample, we must first express each mass of the sample in the same unit of measurement.

Since the SI unit of mass is kilogram (kg), we shall express the total mass of the samples in kilogram (kg).

This is illustrated below:

Mass of the samples are:

M1 = 0.6160959 kg

M2 = 3.225 mg

M3 = 5480.7 g.

Conversion of 3.225 mg to kg

1 mg = 1×10¯⁶ kg

Therefore,

3.225 mg = 3.225 × 1×10¯⁶

3.225 mg = 3.225×10¯⁶ kg

Conversion of 5480.7 g to kg

1000 g = 1 kg

Therefore,

5480.7 g = 5480.7 /1000

5480.7 g = 5.4807 kg

Thus, we can obtain the total mass of the samples as follow:

M1 = 0.6160959 kg

M2 = 3.225×10¯⁶ kg

M3 = 5.4807 kg

Total mass =?

Total mass = M1 + M2 + M3

Total mass = 0.6160959 + 3.225×10¯⁶ + 5.4807

Total mass = 6.096799125 ≈ 6.1 kg

Therefore, the total mass of the samples is approximately 6.1 kg.