ENGINEERING COLLEGE

"Given a nodal delay of 84.1ms when there is no traffic on the network (i.e. usage = 0%), what is the effective delay when network usage = 39.3% ? (Give answer is miliseconds, rounded to one decimal place, without units. So for an answer of 0.10423 seconds you would enter "104.2" without the qu"

Answers

Answer 1
Answer:

Answer:

Explanation:

effective delay = delay when no traffic x (100)/(100- network\r usage)

effective delay = 84.1 * (100)/(100-39.3)=138.55024711697ms

Related Questions

8. Removing damage by tapping it out with a hammerand dolly is often referred to as(A) contouring(B) roughing out(C) forming(D) tapping out
What is the difference between absolute and gage pressure?
You are analyzing an open-return wind tunnel that intakes air at 20 m/s and 320K. When the flow exits the wind tunnel it is moving at a speed of 250 m/s. What is the temperature of the flow exiting that wind tunnel
If the total energy change of an system during a process is 15.5 kJ, its change in kinetic energy is -3.5 kJ, and its potential energy is unchanged, calculate its change in specificinternal energy if its mass is 5.4 kg. Report your answer in kJ/kg to one decimal place.
Which of these factors would help the environment?a. Betty drinks only bottled water instead of soda.b. Greg changes all of the light bulbs in the office to energy efficient bulbs.c. John keeps his off topic conversations down to 10 minutes a day.d. Doug turns the air conditioning down to cool the office during the hot summer months.Please select the best alswer from the choices providedABD

The safety risks are the same for technicians who work on hybrid electric vehicles (HEVs) or EVs as those who work on conventional gasoline vehicles.

Answers

The safety risks are the same for technicians who work on hybrid electric vehicles (HEVs) or EVs as those who work on conventional gasoline vehicles: False.

Safety risks can be defined as an assessment of the risks and occupational hazards associated with the use, operation or maintenance of an equipment or automobile vehicle that is capable of leading to the;

  • Harm of a worker (technician).
  • Injury of a worker (technician).
  • Illness of a worker (technician).
  • Death of a worker (technician).

Hybrid electric vehicles (HEVs) or EVs are typically designed and developed with parts or components that operates through the use of high voltageelectrical systems ranging from 100 Volts to 600 Volts. Also, these type of vehicles have an in-built HEV batteries which are typically encased in sealed shells so as to mitigate potential hazards to a technician.

On the other hand, conventional gasoline vehicles are typically designed and developed with parts or components that operates on hydrocarbon such as fuel and motor engine oil. Also, conventional gasoline vehicles do not require the use of high voltage electrical systems and as such poses less threat to technicians, which is in contrast with hybrid electric vehicles (HEVs) or EVs.

This ultimately implies that, the safety risks for technicians who work on hybrid electric vehicles (HEVs) or EVs are different from those who work on conventional gasoline vehicles due to high voltage electrical systems that are being used in the former.

In conclusion, technicians who work on hybrid electric vehicles (HEVs) or EVs are susceptible (vulnerable) to being electrocuted to death when safety risks are not properly adhered to unlike technicians working on conventional gasoline vehicles.

Find more information: brainly.com/question/2878752

Answer:

Batteries are safe when handled properly.

Explanation:

Just like the battery in your phone, the battery in some variant of an electric car is just as safe. If you puncture/smash just about any common kind of charged battery, it will combust. As long as you don't plan on doing anything extreme with the battery (or messing with high voltage) you should be fine.

What are two advantages of forging when compared to machining a part from a billet?

Answers

Answer:

Less material waste and time.

Explanation:

Two advantages of forging vs machining would be that with forging there is much less waste of material. With machining you remove a large amount of material turning into not so valuable chips.

There is also a time factor, as machining can be very time intensive. This depends on the speed of the machining, newer machines tend to be very fast, and forging requires a lengthy heating, but for large parts the machining can be excessively long.

Indicate whether the following statements are true or false for an isothermal process: (A) Q=T(∆S). (B) ∆U=0.(C) The entropy change of the system is always zero. (D) The total entropy change of the system and the surroundings is always zero. (E) The entropy change of the surroundings is negative. (F) Q=W.

Answers

Answer:

A=False

B=False

C=False

D=False

E=False

F=False

Explanation:

A. In an isothermal process, only the reversibly heat transfer is 0, Q_(rev)=T (\Delta S)

B. Consider the phase change of boiling water. Here, the temperature remains constant but the internal energy of the system increases.

C. This is not true even in reversible process, as can be inferred from the equation in part A.

D. This is only true in reversible processes, but not in all isothermal processes.

E. Consider the phase change of freezing water. Here, the surroundings are increasing their entropy, as they are taking in heat from the system.

F. This is not true if (\Delta U)\neq 0, like in answer B. One case where this is true is in the reversible isothermal expansion (or compression) of an ideal gas.

What is the primary function of NCEES?

Answers

Answer:

A primary function of NCEES is to prepare standardized, confidential examinations that are used by the state and territorial boards to help determine the competency of individuals seeking to become licensed to practice as professional engineers and land surveyors.

Explanation:

i looked it up

can i have a brainliest plzz

Clothing made of several thin layers of fabric with trapped air in between, often called ski clothing, is commonly used in cold climates because it is light, fashionable, and a very effective thermal insulator. So, it is no surprise that such clothing has largely replaced thick and heavy old-fashioned coats. Consider a jacket made up of six layers of 0.1 mm thick synthetic fabric (k = 0.026W/m.K) with 1.2 mm thick air space (k = 0.026 W/m.K) between the fabric layers. Assuming the inner surface temperature of the jacket to be 25˚C and the surface area to be 1.25 m2 , determine the heat loss through the jacket when the temperature of the outdoors is -5˚C and the heat transfer co-efficient of outer surface is 25 W/m2 .K. What would be the thickness of a wool fabric (k = 0.035W/m.K) if the person has to achieve the same level of thermal comfort wearing a thick wool coat instead of a jacket. (30 points)

Answers

Answer:

Q=127.66W

L=9.2mm

Explanation:

Heat transfer consists of the propagation of energy in the form of heat in different ways, these can be convection if it is through a fluid, radiation through electromagnetic waves and conduction through solid solids.

To solve any problem related to heat transfer, the general equation is used

Q = delta / R

Where

Q = heat

Delta = the temperature difference

R = is the thermal resistance by conduction, convection and radiation

to solve this problem we propose the previous equation

Q = delta / R

later we find R

R=[tex]r=(6L1)/(AK1) +(5L2)/(AK2)+(1)/(Ah)

R=(6(0.0001))/((1.25)(0.026)) +(5(0.012))/((1.25)(0.026))+(1)/((25)(1.25)) =0.235 K/w

Q=(25-(-5))/0.235=127.66W

part b

we use the same ecuation with Q=127.66

Q = delta / R

ΔR=(L)/(KA) +(1)/(hA) \nR=(L)/((0.035)(1.25)) +(1)/((25)(1.25))\n R=22.85L+0.032\nQ=(T1-T2)/R\n\n127.66=(25-(-5))/(22.85L+0.032)\nsolving for L\nL=9.2mm

A furnace is shaped like a long equilateral triangular duct where the width of each side is 2 m. Heat is supplied from the base surface, whose emissivity is ε1 = 0.8, at a rate of 800 W/m2 while the side surfaces, whose emissivities are 0.5, are maintained at 500 K. Neglecting the end effects, determine the temperature of the base surface. Can you treat this geometry as a two-surface enclosure?

Answers

Answer:

The geometry is treated as a two surface enclosure because the two surfaces have the same properties.

Let's take the base surface to be surface 1, while the side surfaces are surface 2.

Let's take the heat transfer expression:

Q_1_2 = (\sigma[(T_1)^4 - (T_2)^4])/((1 - E_1)/(A_1 E_1) + (1)/(A_1 F_1_2) + (1-E_2)/(A_2 E_2))

Where,

\sigma = Boltmanz constant = 5.68*10^-^8

T_1 = base temperature

T_2 = surface 2 temperature = 500K

E_1 = emissivity of surface 1 = 0.8

E_2 = emissivity of surface 2 = 0.5

A = Area

F_1_2 = shape factor

Substituting figures in the equation, we have:

800= (5.67*10^-^8[(T_1)^4 - (500)^4])/((1 - 0.8)/(2*0.8) + (1)/(2*1) + (1-0.5)/(4*0.5))

[(T_1)^4 - (500)^4] = (700)/(5.67*10^-^8)

(T_1)^4 = 1.234*10^1^0 + 6.25*10^1^0

T_1 = (7.484*10^1^0)^0^.^2^5

T_1 = 523.038 K

The base temperature is 523.038 k
Other Questions
Imagine you have been asked to find the following object pictured on the left in the accompanying array on the right.RED AND WHITE SQUARES ALL LOOK SIMILARWhat type of search do you think this would be?
for a rankine cycle with one stage of reheat between turbines, there are how many relevant pressures?
Logical variables: Running late? Complete the tunction RunningLate such that the logical variable on Time is true if no Traffic is true and gasEmpty is false. Ex >> n°Traffic = true ; >> gasEmpty-false; >onTime - Runninglate(noTraffic,gasEmpty) logical Your Function B Save C Reset EE MATLAB Documentation 1 function onTime - RunningLate (noTraffic,gasEmpty) 2 % complete the logical expression to the right of . using the variables n°Traffic and gasEmpty 4 onTime - 6 end Code to call your function C Reset 1 noTraffic true; gasEmpty true; 2 onTime-Runninglate(noTraffic, gasEmpty)
FILLIN THE BLANK Buffering is an important op amp application because it solves _____ that can't easily be solved with purely resistive circuits.Group of answer choices