When looking at a chain of processes with a low yield (high defective rate), what is a good place to start investigating the source of variation?

Answers

Answer 1

Answer:

The most upstream process with issues would be a good location to start exploring the cause of the variance.

Chain processes

A manufacturing technique would be a specific procedure for generating a commodity.

Throughout manufacturing, a six sigma process has been utilized just to generate a product throughout which 99.99966 percent among all possibilities to produce certain aspects of a part seem to be likely toward being defect-free.

Thus the response above is correct.

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Answer 2

Answer:

Answer: The furthest upstream process that has problems.

A process in manufacturing is a particular method used for producing a product.

A six sigma process is used in processing to produce a product that is 99.99966% of all opportunities to produce some feature of a part are statistically expected to be free of defects.

According to the rules of the six sigma process, when there's a defect, the best thing to do is investigate the furthest upstream process that has problems.

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How much computer memory (in bytes) in minimum would be required to store 10 seconds of a sensor signal sampled by a 12-bit A/D converter operating at a sampling rate of 5 kHz?

Answers

Answer:

73.24 K byte

Explanation:

Assuming that

N = total number of samples

N = 10 * 5kHz

N = 50*10^3

Also, the total number of bits, T

T = 12 * N

T = 12 * 50*10^3

T = 600 * 10^3

And then, finally, the total number of byte,

B = 600*10^(3/8)

B = 75*10^3 byte

75*10^3 byte = 75*10^3/1024 kilo byte

And on converting to decimal, we will have

= 73.24 K byte

Therefore, the memory required = 73.24 K byte

On what single factor does the efficiency of the Otto cycle depend?

Answers

Answer:

Compression ratio(r)

Explanation:

Otto cycle:

Otto cycle is an ideal cycle for all working petrol engine.It have four processes in which two are constant volume process and other two are reversible adiabatic or we can say that isentropic processes.All petrol engine works on Otto cycle.

The efficiency of Otto cycle given as follows

$\eta =1-(1)/(r^(\gamma-1))$

Where r is the compression ratio and γ is heat capacity ratio.

So from above we can say that the efficiency of Otto cycle depends onl;y on compression ratio (r).

Please define the specific heat of material?

Answers

Answer and Explanation:

SPECIFIC HEAT :

Specific heat is denoted by $c_v$
It is the heat required for increasing the temperature of a substance which has mass of 1 kg.
Its SI unit is joule/kelvin
It is physical property
It can be calculated by $c_v=(Q)/(m\Delta T)$ , here Q is heat energy m is mass of gas and $\Delta T$ is change in temperature.

The substance called olivine may have any composition between Mg2SiO4 and Fe2SiO4, i.e. the Mg atoms can be replaced by Fe atoms in any proportion without altering the crystal structure except by expanding it slightly: this is an example of a binary solid solution series. For different compositions, the lines in the powder diffraction patterns are in slightly different positions, because of the cell expansion, but the overall pattern remains basically the same. The spacing of the lattice planes varies linearly with composition, and this can be used in a rapid and non- destructive method of analysis. a. The (062) reflection from olivine is strong and well resolved from other lines. Calculate d062 for an olivine that displays its (062) reflection at a Bragg angle of 37.21° (i.e., a diffraction angle of 74.42°) when x-rays with a wavelength of 0.1790 nm are used. b. The d062 spacing as measured accurately for synthetic materials is 0.14774 nm for Mg2SiO4 and 0.15153 nm for Fe2SiO4. What would be the approximate composition, expressed in mol.% Mg2SiO4, of an olivine material for which do62 has the value obtained in part 2.1 above?

Answers

Answer:

The answer is "0.147 nm and 99.63 mol %"

Explanation:

In point (a):

$\to nk1 = 062$

$\to \text{Bragg angle}$ $\theta =37.21^(\circ)$

$\to \text{diffraction angle}$ $2 \theta = 74.42^(\circ)$

$\to \lambda = 0.1790 nm$

find:

d(062)=?

formula:

$\to nx = 2d \sin \theta$

$\to d(062) = (1 * 0.1790^(\circ))/(2 * \sin 37.21^(\circ))\n$

$= (0.1790^(\circ))/(2 * 0.604738126)\n\n= (0.29599589)/(2)\n\n= 0.147 \n$

In point (b):

$\to Mg_2SiO_4\longleftrightarrow Fe_2SiO_4$

$d= 0.14774 \ \ \ \ \ olivine = 0.147 \ \ \ \ \ 0.15153$

formula:

$\to d=(a)/(√(n^2+k^2+i^2))\n$

that's why the composition value equal to 99.63 %

Write two scnr.nextInt statements to get input values into birthMonth and birthYear. Then write a statement to output the month, a slash, and the year. End with newline. The program will be tested with inputs 1 2000 and then with inputs 5 1950. Ex: If the input is 1 2000, the output is: 1/2000

Answers

Answer:

import java.util.Scanner;

public class InputExample {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int birthMonth;

int birthYear;

birthMonth = scnr.nextInt();

birthYear = scnr.nextInt();

System.out.println(birthMonth+"/"+birthYear);

}

import java.util.Scanner;

public class InputExample {

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int birthMonth;

int birthYear;

// Get input values for birthMonth and birthYear from the user

birthMonth = scnr.nextInt();

birthYear = scnr.nextInt();

// Output the month, a slash, and the year

System.out.println(birthMonth + "/" + birthYear);

}

When the program is tested with inputs 1 2000, the output will be:

1/2000

And when tested with inputs 5 1950, the output will be:

5/1950

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The process in which the system pressure remain constant is called a)-isobaric b)-isochoric c)-isolated d)-isothermal

Answers

Answer:

Isobaric process

Explanation:

The process in which the system pressure remain constant is called is called isobaric process. The word "iso"means same and baric means pressure.

At constant pressure, the work done is given by :

$W=p* \Delta V$

Where

W is the work done by the system

p is the constant pressure

$\Delta V$ is the change in volume

So, the correct option is (c) " isobaric process ".

Other Questions

What is 29.95 inHg in kPa?

Air is contained in a cylinder device fitted with a piston-cylinder. The piston initially rests on a set of stops, and a pressure of 300 kPa is required to move the piston. Initially, the air is at 100 kPa and 27°C and occupies a volume of 0.4 m^3. A) Determine the amount of heat transferred to the air, in kJ, while increasing the temperature to 1200 K. Assume air has constant specific heats evaluated at 300 K.

) A flow is divided into two branches, with the pipe diameter and length the same for each branch. A 1/4-open gate valve is installed in line A, and a 1/3-closed ball valve is installed in line B. The head loss due to friction in each branch is negligible compared with the head loss across the valves. Find the ratio of the velocity in line A to that in line B (include elbow losses for threaded pipe fittings).