PHYSICS COLLEGE

A^^\-> points in the -x direction with a magnitude of 21. What is the y component of A^^\->

Answers

Answer 1

Answer:

Answer:

$A_y=-36.37^(\circ)$

Explanation:

Given that,

Vector A points in the -x direction with a magnitude of 21.

Let the x component is making an angle of 60 degrees with negative x axis. The x component of a vector is given by :

$A_x=A\ cos\theta$

$-21=A\ cos(60)$

$A=(-21)/(cos(60))$

A = -42 units

The y component of a vector is given by :

$A_y=A\ sin\theta$

$A_y=-42\ sin(60)$

$A_y=-36.37^(\circ)$

So, the y component of vector A is (-36.37) degrees. Hence, this is the required solution.

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A heavy object and a light object are dropped from the same height. If we neglect air resistance, which will hit the ground first?

Answers

Answer:

None, both objects will hit ground at the same time.

Explanation:

Assuming no air resistance present, and that both objects start from rest, we can apply the following kinematic equation for the vertical displacement:

$\Delta h = (1)/(2)*g*t^(2) (1)$

As the left side in (1) is the same for both objects, the right side will be the same also.
Since g is constant close to the surface of the Earth, it's also the same for both objects.
So, the time t must be the same for both objects also.

A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processes are generating, its temperature will drop. If the drop is severe, it can be life-threatening. Suppose that a person is unclothed and energy is being lost via radiation from a body surface area of 1.36 m2, which has a temperature of 34° C and an emissivity of 0.700. Also suppose that metabolic processes are producing energy at a rate of 122 J/s. What is the temperature of the coldest room in which this person could stand and not experience a drop in body temperature

Answers

To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzman law that is responsible for calculating radioactive energy.

Mathematically this expression can be given as

$P = \sigma Ae\Delta T^4$

Where

A = Surface area of the Object

$\sigma =$ Stefan-Boltzmann constant

e = Emissivity

T = Temperature (Kelvin)

Our values are given as

$A = 1.36m^2$

$\Delta T^4 = T_2^4 -T_1^4 = 307^4-T_1^4$

$\sigma = 5.67*10^(-8) J/(s m^2 K^4)$

$P = 122J/s$

$e = 0.7$

Replacing at our equation and solving to find the temperature 1 we have,

$P = \sigma Ae\Delta T^4$

$P = \sigma Ae (T_2^4 -T_1^4)$

$122 = (5.67*10^(-8))(1.36)(0.7)(307^4-T_1^4)$

$T_1 = 285.272K = 12.122\°C$

Therefore the the temperature of the coldest room in which this person could stand and not experience a drop in body temperature is 12°C

A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change the period to 2.07 s?

Answers

Answer:

The add mass = 5.465 kg

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.

Substituting into equation 4

m₂ = (2.07)²(0.5)/(1.18)²

m₂ = 4.285(1.392)

m₂ = 5.965 kg.

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

Thus the add mass = 5.465 kg

A 600W toaster, 1200W iron and a 100W bulb are all connected to household 120V circuit. a) find the current drawn by each applianceb) the resistance of the heating element in the iron
c) the total cost of running all of the appliances non-stop for 5 days if the electricity rate is $0.1 per KW-Hr.

Answers

Answer:

(a) %a, 10 A, 0.833 A

(b) 12 ohm

Explanation:

Power of toaster, P1 = 600 W

Power of iron, P2 = 1200 W

Power of bulb, P3 = 100 W

V = 120 V

As they are in household circuit, so they are connected in parallel, so the voltage is same for all.

(a) Use the formula P = V x i

Current in toaster, i1 = P1 / V = 600 / 120 = 5 A

Current in iron, i2 = P2 / V = 1200 / 120 = 10 A

Current in bulb, i3 = P3 / V = 100 / 120 = 0.833 A

(b) Resistance of heating element of iron is R2.

V = i2 x R2

120 = 10 x R2

R2 = 12 ohm

= (600 + 1200 + 100) x 24 x 5 = 228000 Wh = 228 KWh

Cost of 1 KWh = $0.1

Cost of 228 KWh = 0.1 x 228 = $22.8

_______________________________

Answer:

(a). Toaster = 5A

Iron = 10A

Bulb = 0.833A

(b). R2 = 12Ω

(c). $ 22.8

_______________________________

Explanation:

Given,

Power of Toaster, P1 = 600W

Power of Iron, P2 = 1200W

Power of Bulb, P3 = 100W

Potential difference = 120V

They all are connected in parallel combination because they all are household circuits so that the voltage is same for all appliances in the circuit.

★Solution of(a)

By using the formula of powerwe can find out the current.

P=V×I

Here, power is directly proportional to the potential difference and electric current flowing through the circuit.

[.°.I=P/V]

Here,electriccurrent is inversely proportional to the potential differenceandelectric currentisdirectly proportional topower.

Current in Toaster, I1 = P1/V = 600/120 = 5A

Current in Iron, I2 = P1/V = 1200/120 = 10A

Current in Bulb, I3 = P1/V = 100/120 = 0.833A

★Solutionof(b)

Resistance of Heating coil of Iron

By using theformula of Ohm's Law we can find out the resistance of heatingcoil of iron.

V=I×R

Here, the potential difference is directly proportional to the current carrying wire and potential difference is directly proportional to the resistance off the wire present in the Iron.

[.°.R=V/I]

Here, resistance is directly proportional to the potential difference and resistance is inversely proportional to the electric current.

R=V/I

=> R = 120/10

.°. R = 12Ω

★Solutionof(c)

Total consumption of Energy in 24 hours for 5 days = (600W + 1200W + 100W) × 24 hours × 5 days

= 228000Wh

= 228kWh

When the cost of 1kWh = $ 0.1

So,

The cost of 228 kWh = $ 0.1 × 228 = $ 22.8

_______________________________

What two statements are true about energy transformations

Answers

Answer:

First statement:

Energy can neither be created nor destroyed.

Second statement:

Energy can be converted from one form to another.

Explanation:

According to the law of conservation of energy:energy can neither be created nor destroyed but can be converted from one form to another

A truck traveling with an initial velocity of 44.1 m/s comes to a stop in 15.91 secs. What is theacceleration of the truck?

Answers

Answer:

a=-2.77 m/s^2

Explanation:

Assuming constant acceleration,

v=at + v_0

where v_0 is the initial velocity.

At rest, v=0, so

0=at+v_0

So solving the equation for a:

a=(-v_0)/t

Inserting the numbers yields

a=-2.77 m/s^2

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