CHEMISTRY COLLEGE

If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is

Answers

Answer 1

Answer:

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a

compound.

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

Mn O

% composition 72.1 27.9

Divide by mass number 54.94 16

1.31 1.74

Divide by the smallest number 1.31 1.31

1 1.3

The resulting ratio is 1:1

Hence the Empirical formula is MnO, Manganese oxide

Related Questions

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Which of the following forces causes comets to regularly return to the inner solar system after being gone for many years?A. friction
B. magnetism
C. electromagnetic force
D. gravity

Answers

Answer is D. Gravity

Answer:

✨Gravity✨ hope this helps

Explanation:

How many s’mores can you make from the following combinations? What is the limiting reagent?

Answers

The limiting reagent and the number of S'mores produced for each of the reactions is given below:

Reaction 1. The limiting reagent is Cp; 1.6 S'mores are produced.

Reaction 2. The limiting reagent is M;2 S'mores are produced.

Reaction 3. The limiting reagent is Gc; 2.5 S'mores are produced.

Reaction 4. The limiting reagent is M;1 S'more is produced.

Stoichoimetry

Stoichiometry is the process of measuring quantitatively the mass and quantity relationships among reactants and products in a given reaction.

The equation of the reaction shows the stoichiometry between reactants and products.

For the given reaction, the equation of reaction is as follows:

1M + 2Gc + 3Cp ----> 1Gc2MCp3

where:

Gc = Graham Cracker
M = Marshmallow
Cp = Chocolate pieces
S’more = Gc2MCp3

From the equation of reaction:

1 marshmallow, 2 Graham cracker and 3 chocolate pieces are required to make 1 S'more

Calculating the number of S'mores and the limiting reactant of the given reaction

The stoichiometric equation is: 2Gc + 1M + 3Cp ----> 1Gc2MCp3

The ratio of Gc to M to Cp is 2 : 1 : 3

Reaction 1. 4 Gc + 2M + 5 Cp

The ratio of Gc to M to Cp in the reaction above is 2 : 1 : 2.5

Therefore the limiting reagent is Cp

3 Cp makes 1 S'more

5 Cp will make 5 * 1/3 S'more = 1.6 S'mores

Therefore, 1.6 S'mores are produced.

Reaction 2. 6 Gc + 2M + 9 Cp

The ratio of Gc to M to Cp in the reaction above is 3 : 1 : 4.5

Therefore the limiting reagent is M

1 M makes 1 S'more

2 Cp will make 2 * 1/1 S'more = 2 S'mores

Therefore, 2 S'mores are produced.

Reaction 3. 5 Gc + 3M + 9 Cp

The ratio of Gc to M to Cp in the reaction above is 1.6 : 1 : 3

Therefore the limiting reagent is Gc

2 Gc makes 1 S'more

5 Gc will make 5 * 1/2 S'more = 2.5 S'mores

Therefore, 2.5 S'mores are produced.

Reaction 4. 7 Gc + 1M + 6 Cp

The ratio of Gc to M to Cp in the reaction above is 7 : 1 : 6

Therefore the limiting reagent is M

1 M makes 1 S'more

Therefore, 1 S'more is produced.

The limiting reagent and the number of S'mores produced for each of the reactions is given below:

1. The limiting reagent is Cp; 1.6 S'mores are produced.

2. The limiting reagent is M;2 S'mores are produced.

3. The limiting reagent is Gc; 2.5 S'mores are produced.

4. The limiting reagent is M;1 S'more is produced.

Learn more about Stoichiometry and limiting reagents at: brainly.com/question/14222359

Draw the Lewis structure for BrCl3. What are the approximate bond angles about the central atom?a. 60°.
b. 90°.
c. 109°.
d. 120°.
e. 180°.

Answers

Answer:

Explanation:

BrCl₃ is an interhalogen compound with a hybridization of sp³d. The approximate bond angles can be predicted from the structure (attached below). Although, the lewis structure might be predicted to be trigonal bipyramidal from the structure, it is however a T-shaped geometry because of it's two lone pairs.

Also, from the structure attached, it can be predicted that the approximate bond angles about the central atom is 120° (360 ÷ 3) since each of the three chlorine atoms is equally spaced about the central atom.

The Lewis structure for BrCl₃ is attached to the image below. The bond angles around the central atom, bromine (Br), are 90 degrees between the bromine and each chlorine atom. Therefore, option B is correct.

A Lewis structure, also known as an electron-dot structure or Lewis dot structure is a diagram that represents the valence electrons of an atom or molecule.

Bromine (Br) is in Group 7A and has 7 valence electrons, while each chlorine (Cl) atom in Group 7A also has 7 valence electrons.

Br: 1 atom × 7 valence electrons = 7 valence electrons

Cl: 3 atoms × 7 valence electrons = 21 valence electrons

Total valence electrons = 7 + 21 = 28

To learn more about the bond angle, follow the link:

brainly.com/question/31324226

#SPJ6

Whats the difference between china and Europe

Answers

Answer:

the difference is they arnt close

Explanation:

Answer:

China is communist, Europe isn't.

Explanation:

A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74 atm. When the experiment is repeated using 0.020 mol of ethanoic acid instead of methyl methanoate, the measured pressure is lower than 0.74 atm. The lower pressure for ethanoic acid is due to the following reversible reaction.CH3COOH(g)+CH3COOH(g) ⇋ (CH3COOH)2(g)+Assume that when equilibrium has been reached, 50 percent of the ethanoic acid molecules have reacted.i. Calculate the total pressure in the vessel at equilibrium at 450 K.ii. Calculate the value of the equilibrium constant, Kp, for the reaction at 450 K

Answers

Explanation:

Starting moles of ethanol acid = 0.020 mol

At the equilibrium 50 % of the ethanol acid molecules reacted

∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %

= 0.010 mol

Moles of ethanol acid remain = 0.020 mol + 0.010 mol = 0.010 mol

Moles of the product $(CH3COOH)^(2)$ gas formed are calculated as

0.010 mol CH3COOH * 1 mol $(CH3COOH)^(2)$ / 2 mol CH3COOH

= 0.005 mol $(CH3COOH)^(2)$

Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol $(CH3COOH)^(2)$

That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol

Now Calculate the pressure :

0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas

P1/n1 = P2/n2

P2 = P1*n2 / n1

= 0.74 atm * 0.015 mol / 0.020 mol

= 0.555 atm

A water wave has a frequency of 10 Hz and a wavelength of 150 m. What is the wave speed? *Equation to use: wave speed (m/s) = frequency (Hz) x wavelength (m)*