Assume that the speed of light in a vacuum has the hypothetical value of 18.0 m/s. A car is moving at a constant speed of 14.0 m/s along a straight road. A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s. How much time does the driver of the car measure for his trip between the poles?

Answers

Answer 1
Answer:

Answer:

Observed time, t = 5.58 s  

Explanation:

Given that,

Speed of light in a vacuum has the hypothetical value of, c = 18 m/s

Speed of car, v = 14 m/s along a straight road.

A home owner sitting on his porch sees the car pass between two telephone poles in 8.89 s.

We need to find the time the driver of the car measure for his trip between the poles. The relation between real and observed time is given by :

T=\frac{t}{\sqrt{1-(v^2)/(c^2)} }

t is observed time.

t=T* \sqrt{1-(v^2)/(c^2)} \n\nt=8.89* \sqrt{1-(14^2)/(18^2)} \n\nt=5.58\ s

So, the time observed by the driver of the car measure for his trip between the poles is 5.58 seconds.


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A student and his lab partner create a single slit by carefully aligning two razor blades to a separation of 0.530 mm. When a helium–neon laser at 543 nm illuminates the slit, a diffraction pattern is observed on a screen 1.55 m beyond the slit. Calculate the angle θdark to the first minimum in the diffraction pattern and the width of the central maximum.

Answers

Answer:

angle = 0.058699 degree

width of central maximum  is 3.170566 × 10^(-3) )  m</strong></p><p><strong>Explanation:</strong></p><p>Given data </p><p>separation d = 0.530 mm = 0.530×[tex]10^(-3) m

distance D =  1.55 m

wavelength w = 543 nm = 543× 10^(-9) m

to find out

angle θ and width of the central maximum

solution

we know according to first condition first dark that mean

wavelength = dsinθ

so put value and find θ

543× 10^(-9) = 0.530×10^(-3) ×sinθ

sinθ  =  543× 10^(-9) / 0.530×10^(-3)

sinθ   =  1.02452 × [tex]10^{-3}

θ = 0.058699 degree

and

we can say

tanθ = y/D

here y is width of central maximum Y = 2y

put all value we get  y

so y = D tanθ

y = 1.55 (tan0.0586)

y = 1.58528 × [tex]10^{-3} m =

so Y = 2 ( 1.58528 × [tex]10^{-3} )

so width of central maximum  is 3.170566 × [tex]10^{-3} )  m

A conducting loop of radius r=0.1 m, carrying a current I=2 A has a magnetic moment \vec{\mu} μ ​ that is entirely in the j-hat direction. The loop is immersed in a magnetic field \vec{B} B = [3 i-hat + 4 j-hat] T. What is the potential energy of the loop in this configuration?

Answers

Answer:

Explanation:

Magnetic moment of current carrying loop

= current x area

= 2 x π x .1²

M  = .0628 unit . it is in j direction so vecor form of it

M = .0628 j

Magnetic field   B = 3i + 4 j

Energy

=  -  M.B

-  .0628 j . ( 3i + 4 j )

= - .2512 J

Energy is the capacity to do work, but not to produce heat

Answers

Energy and Work Energy is the capacity to do work or to produce heat. Internal energy is the sum of kinetic energy and the potential energy. ... The KE would increase because heating something causes an increase in temperature.

Final answer:

Energy is the capacity to do work but not to produce heat. In physics, energy can exist in various forms, including mechanical and thermal energy.

Explanation:

Energy is the capacity to do work and is an important concept in physics. In the context of this question, it is stated that energy is the capacity to do work but not to produce heat. This highlights the distinction between the two forms of energy. For example, mechanical energy can be used to perform work on an object and cause it to move, while thermal energy is associated with heat and not directly related to work. However, it's important to note that energy can be converted from one form to another, such as converting mechanical energy to thermal energy in a friction process.

Learn more about Energy here:

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A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth's surface. What is this satellite's speed

Answers

Answer:

6779.7m/s

Explanation:

Using

GMm/(Re +h)² = mv²/ (Re+h)

So making v subject we have

V= √GM/Re+h

So

V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3

V= 6779.7m/s

Note h = height of satellite

Re= radius of the earth

M = mass of the earth

A physicist is creating a computational model of a falling person before and after opening a parachute. What boundary conditions would be important here?the air resistance encountered as the person falls

the speed at which the person falls

the change in kinetic and potential energy

the location where potential energy is zero

Answers

Answer:

the location where potential energy is zero

Explanation:

Answer:

Air resistance

Explanation:

Air resistance encountered as the person falls

a weight is suspended from the ceiling by a spring (k = 20 ln/in) and is connected to the floor by a dashpot producing viscous damping. The damping force is 10 lb when the velocity of the dashpot plunger is 20 in/sec. The weight and plunger have W = 12 lb. What will be the frequency of the damped vibrations?

Answers

Answer:

The frequency of the damped vibrations is 3.82 Hz.

Explanation:

Given that,

Spring constant = 20 lb/in

Damping force = 10 lb

Velocity = 20 in/sec

Weight = 12 lb

We need to calculate the damping constant

Using formula of damping force

b* v=F_(d)

b=(F_(d))/(v)

Put the value into the formula

b =(10)/(20)

b=0.5\ lb-sec/in

b=0.5*12 =6\ lb-sec/ft

We need to calculate the frequency

Using formula of angular frequency

\omga=\sqrt{\omega_(0)^2-((b)/(2m))^2}

\omega=\sqrt{(k)/(m)-((b)/(2m))^2}

Put the value into the formula

\omega=\sqrt{(20*12*32)/(12)-((6*32)/(2*12))^2}

\omega=24\ rad/s

We need to calculate the frequency of the damped vibrations

Using formula of frequency

f=(\omega)/(2\pi)

Put the value into the formula

f=(24)/(2\pi)

f=3.82\ Hz

Hence, The frequency of the damped vibrations is 3.82 Hz.