A wall in a house contains a single window. The window consists of a single pane of glass whose area is 0.15 m2 and whose thickness is 5 mm. Treat the wall as a slab of the insulating material Styrofoam whose area and thickness are 10 m2 and 0.15 m, respectively. Heat is lost via conduction through the wall and the window. The temperature difference between the inside and outside is the same for the wall and the window. Of the total heat lost by the wall and the window, what is the percentage lost by the window

Answers

Answer 1
Answer:

Answer:

The percentage loss of the window is  E  = 97.3%

Explanation:

From the question we are told that

      The area of pane of glass is  A = 0.15 m^2

      The thickness is d = 5mm = (5)/(1000) = 0.005m

       The thickness of the wall is  D = 0.15m

       The area of the wall is  a = 10m^2

Generally the heat lost as a result of conduction of the window is  

              Q_(window) = (j_(glass) * A * (\Delta T) )/(d)

Where j_(glass) is the thermal conductivity of glass which has a constant value of

          j_(glass) = 0.80 J/(s \cdot m \cdot  C^o)

 Substituting values

                 Q_(window) = ( 0.80  * 0.15  * (\Delta T) )/(0.005)

                 Q_(window) = 24 \Delta T

Generally the heat lost as a result of conduction of the wall is  

              Q_(wall) = (j_(styrofoam) * A * (\Delta T) )/(d)

j_(styrofoam) s the thermal conductivity of Styrofoam which has a constant value of  j_(styrofoam) = 0.010J / (s \cdot m \cdot C^o)

       Substituting values

                 Q_(wall) = ( 0.010  * 10  * (\Delta T) )/(0.15)

                 Q_(wall) = 0.667 \  \Delta T

Now the net loss of heat is

         Q_(net) = Q_(window) +  Q_(wall)

  Substituting values

         Q_(net) = 24 + 0.667

         Q_(net) =  24.667

Now the percentage loss by the window is  

            E  = (Q_(window) )/(Q_(net))  * 100

  Substituting value  

           E  = (24)/(24 .667)  * 100

           E  = 97.3%


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1.19. A gas is confined in a 0.47 m diameter cylinder by a piston, on which rests a weight. The mass of the piston and weight together is 150 kg. The local acceleration of gravity is 9.813 m·s−2, and atmospheric pressure is 101.57 kPa. (a) What is the force in newtons exerted on the gas by the atmosphere, the piston, and the weight, assuming no friction between the piston and cylinder? (b) What is the pressure of the gas in kPa? (c) If the gas in the cylinder is heated, it expands, pushing the piston and weight upward. If the piston and weight are raised 0.83 m, what is the work done by the gas in kJ? What is the change in potential energy of the piston and weight?\

Answers

In this exercise we have to use the knowledge of force to calculate the required energies, so we have to:

a) 19094 N

b) 110.055 kPa

c) 1222 J

What is the concept of force?

In the field of physics, force is a physical action that causes deformation or that changes the state of rest or movement of a given object.

a) Knowing that the force formula is defined by:

F = P + p * A\nF = m * g + p *\pi /4 * d^2\nF = 150 * 9.813 + 101570 * \pi /4 * 0.47^2 = 19094 N

b) Knowing that the force exerted by an area is equal to the pressure in that area, we have:

p_1 = F / A\np_1 = F / (\pi /4 * d^2)\np_1 = 19094 / (\pi /4 * 0.47^2) = 110055 Pa = 110.055 kPa

c)So calculating the potential energy we have:

\Delta E_p = m * g * \Delta h\n\Delta E_p = 150 * 9.813 * 0.83 = 1222 J

See more about force at brainly.com/question/26115859

Answer:

a) 19094 N

b) 110.055 kPa

c) 1222 J

Explanation:

The force on the gas is the weight plus the atmospheric pressure multiplied by the piston area

F = P + p * A

F = m * g + p * π/4 * d^2

F = 150 * 9.813 + 101570 * π/4 * 0.47^2 = 19094 N

The pressure is the force divided by the area of the piston

p1 = F / A

p1 = F / (π/4 * d^2)

p1 = 19094 / (π/4 * 0.47^2) = 110055 Pa = 110.055 kPa

variation of gravitational potential energy is defined as

ΔEp = m * g * Δh

ΔEp = 150 * 9.813 * 0.83 = 1222 J

For some transformation having kinetics that obey the Avrami equation (Equation 10.17), the parameter n is known to have a value of 2.1. If, after 146 s, the reaction is 50% complete, how long (total time) will it take the transformation to go to 86% completion?

Answers

Answer:

t = 25.10 sec

Explanation:

we know that Avrami equation

Y = 1 - e^(-kt^n)

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t  is duration of reaction = 146 sec

so,

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taking natural log on both side

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for 86 % completion

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Answers

Answer:

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Answers

Answer:

The correct answer is C) Trimetric

Explanation:

The most suitable answer is a trimetric projection because, in this type of projection, we see that the projection of the three angles between the axes are not equal. Therefore, to generate a trimetric projection of an object, it is necessary to have three separate scales.

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Answers

Answer:

a)-Bin stock items free issue

Explanation:

Bin stock items free issue items are similar to the free issue items, but their access is limited.

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Answers

Answer:

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Explanation:

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