MATHEMATICS COLLEGE

Simplify the expression 7(1 +5v) =

Answers

Answer 1

Answer: the answer is 7 + 35v

Answer 2

Answer:

Answer:

7 + 35v

Step-by-step explanation:

7 × 1 + 5v × 7

7 + 35v

Hope this helps and have a nice life d:

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WHAT IS THE SLOPE OF THE LINE
6X + 3Y = 18?

Answers

Answer:

−2

Step-by-step explanation:

Using the slope-intercept form, the slope is −2 .

It’s -2 and the y intercept is (0,6)

ComeQuestion 14
8.0 x105 +6.0 x107 =
A
14,000,000,000,000
B
140,000,000
с
60,800,000
D
68,000,000

Answers

Answer:

с 60,800,000

Step-by-step explanation:

Any scientific or graphing calculator can evaluate this expression for you.

When adding numbers in scientific notation, they need to have the same multiplier exponent. Here, it is convenient to use 10^6:

8.0×10^5 = 0.8×10^6

6.0×10^7 = 60×10^6

Then the sum is ...

(0.8 +60)×10^6 = 60.8×10^6 = 60,800,000

Which statement best describes the relationship between the graphs of the two linear equations below?3
y=-2 +4
2
3x - 2y = -8
The lines are
parallel
5
The lines intersect
and are
perpendicular
The lines intersect
and are not
perpendicular
The lines are the
same

Answers

Answer:

Step-by-step explanation:

Question 3 (1 point) If the following is a rhombus, find the missing measures. Find PQ. PQ=

Answers

Answer:

Step-by-step explanation:

PQ*PQ=PQ²=(5x+16)²=25x²+160x+256

At a farm, there are two huge pits for storing hay. 90 tons of hay is stored in the first pit, 75 tons in the second pit. Then, three times as much hay was removed from the first pit as was removed from the second pit. After that, there was half as much hay in the first pit as there was now in the second pit. How many tons of hay was taken from the first pit?

Answers

Answer:

63 tons

Step-by-step explanation:

The problem statement asks for the tons of hay removed from the first pit. It is convenient to let a variable (x) represent that amount. This is said to be 3 times the amount removed from the second pit, so that amount must be x/3.

The amount remaining in the first pit is 90-x.

The amount remaining in the second pit is 75 -x/3.

Since the first pit remaining amount is half the second pit remaining amount, we can write the equation ...

... 90 -x = (1/2)(75 -x/3)

... 180 -2x = 75 -x/3 . . . . multiply by 2

... 105 - 2x = -x/3 . . . . . . subtract 75

... 315 -6x = -x . . . . . . . . multiply by 3

... 315 = 5x . . . . . . . . . . . add 6x

... 63 = x . . . . . . . . . . . . . divide by 5

63 tons of hay were taken from the first pit.

_____

Check

After removing 63 tons from the first pit, there are 27 tons remaining. After removing 63/3 = 21 tons from the second pit, there are 54 tons remaining. 27 is half of 54, so the answer checks OK.

Help please! I’ll give brainliest!