How many moles of argon are in 4.80x10^24 atoms of argon

Answers

Answer 1

Answer:

Answer:

7.97 mol Ar

Explanation:

Use Avogadro's number to convert atoms to moles. This number is the number of atoms in one mole. There are 6.022 × 10²³ atoms in one mole.

Divide the number of atoms given by Avogadro's number.

(4.80 × 10²⁴)/(6.022 × 10²³) = 7.97 mol

There are 7.97 moles of argon.

Answer 2

Answer:

Answer:

3.0 moles (A P E X)

Explanation:

Related Questions

What is the mass in grams of H₂ that can be formed from 54.6 grams of NH₃ in the following reaction?2 NH₃(g) → 3 H₂(g) + N₂(g)

Answers

9.6 grams of H₂ can be formed from 54.6 grams of NH₃ in the following reaction: 2NH₃(g) → 3H₂(g) + N₂(g).

According to this question, the following balanced equation is given: 2NH₃(g) → 3H₂(g) + N₂(g).

First, we convert the mass of ammonia (NH3) to moles as follows:

moles of NH3 = 54.6g ÷ 17g/mol

moles of NH3 = 3.2mol.

If 2 moles of NH3 produces 3 moles of H2.
3.2 moles of NH3 will produce 4.8 moles of H2.

Next, we convert 4.8moles of H2 to mass as follows:

mass of H2 = 4.8 × 2

mass of H2 = 9.6g of H2.

Therefore, 9.6 grams of H₂ can be formed from 54.6 grams of NH₃ in the following reaction: 2NH₃(g) → 3H₂(g) + N₂(g).

Learn more at: brainly.com/question/8732513?referrer=searchResults

Answer : The mass of $H_2$ is, 9.64 grams.

Explanation : Given,

Mass of $NH_3$ = 54.6 g

Molar mass of $NH_3$ = 17 g/mol

Molar mass of $H_2$ = 2 g/mol

First we have to calculate the moles of $NH_3$ .

$\text{Moles of }NH_3=\frac{\text{Given mass }NH_3}{\text{Molar mass }NH_3}$

$\text{Moles of }NH_3=(54.6g)/(17g/mol)=3.21mol$

Now we have to calculate the moles of $H_2$

The balanced chemical equation is:

$2NH_3(g)\rightarrow 3H_2(g)+N_2(g)$

From the balanced reaction we conclude that

As, 2 mole of $NH_3$ react to give 3 moles of $H_2$

So, 3.21 mole of $NH_3$ react to give $(3)/(2)* 3.21=4.82$ mole of $H_2$

Now we have to calculate the mass of $H_2$

$\text{ Mass of }H_2=\text{ Moles of }H_2* \text{ Molar mass of }H_2$

$\text{ Mass of }H_2=(4.82moles)* (2g/mole)=9.64g$

Therefore, the mass of $H_2$ is, 9.64 grams.

The element oxygen has valence electrons

Answers

Answer:

it’s electron configuration is 1s^2 2s^2 2p^4. To determine valence electrons, add the outermost s and p orbitals. In an oxygen atom, 8 electrons are present. Electron present in the first shell (n=1) 2n^2=2 (1)^2=2 (1)=2.

A single replacement reaction is a reaction in which one element replaces a similar element within a compound. TRUE OR FALSE

Answers

Answer:

true

Explanation:

Molecular compounds result from covalent bonding which are called _______.This is for high school physical science

Answers

Answer:

Diatomic Molecule

Explanation:

When baking soda (sodium bicarbonate or sodium hydrogen carbonate, NaHCO3) is heated, it releases carbon dioxide gas, which is responsible for the rising of cookies, doughnuts, and bread. a) Write a balanced equation for the decomposition of the compound (one of the products is Na2CO3).
b) Calculate the mass of NaHCO3 required to produce 20.5 g of CO2.

Answers

Answer:

a. NaHCO₃ + HCl → NaCl + H₂O + CO₂

b. 39.14 g is the mass of NaHCO₃ required to produce 20.5 moles of CO₂

Explanation:

A possible reaction for NaHCO₃ to make dioxide is this one, when it reacts with hydrochloric to produce the mentioned gas.

NaHCO₃ + HCl → NaCl + H₂O + CO₂

Ratio in this reaction is 1:1

So 1 mol of baking soda, produce 1 mol of CO₂

Let's calculate the moles

20.5 g CO₂ / 44 g/m = 0.466 moles

This moles of gas came from the same moles of salt.

Molar mass baking soda = 84 g/m

Molar mass . moles = mass

84 g/m . 0.466 moles = 39.14 g

For your sink at home, the flow rate in is 5000 units/hr. Accumulation is 2500 units. What is the accumulation rate if the out flow is 60 units/min? multiple choicea) 2400 units/hr b) 400 units/hr c)100 units/hr d) 1400 units/hr e) 3400 units/hr

f) other ____________________