ENGINEERING COLLEGE

Q/For the circuit showm bellow:a) find the mathematical expression for the transient behavior of ve and ic after closing the switeh,
b) sketch vc and ic.
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Answers

Answer 1
Answer:

Answer:

hello your question is incomplete attached is the complete question

A) Vc =  15 ( 1 -e^(-t/0.15s) ) ,   ic = 1.5 mAe^(-t/0.15s)

B) attached is the relevant sketch

Explanation:

applying Thevenin's theorem to find the mathematical expression for the transient behavior of Vc and ic after closing the switch

R_(th) = 8 k ohms || 24 k ohms = 6 k ohms

E_(th) = (20 k ohms(20 v))/(24 k ohms + 8 k ohms)  =  15 v

t = RC = (10 k ohms( 15 uF) = 0.15 s

Also; Vc = E( 1 - e^(-t/t) )

hence Vc = 15 ( 1 - e^(-t/0.15) )

ic = (E)/(R) e^(-t/t) = (15)/(10) e^(-t/t) = 1.5 mAe^(-t/0.15s)

attached

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What are two advantages of forging when compared to machining a part from a billet?

Answers

Answer:

Less material waste and time.

Explanation:

Two advantages of forging vs machining would be that with forging there is much less waste of material. With machining you remove a large amount of material turning into not so valuable chips.

There is also a time factor, as machining can be very time intensive. This depends on the speed of the machining, newer machines tend to be very fast, and forging requires a lengthy heating, but for large parts the machining can be excessively long.

The larger the Bi number, the more accurate the lumped system analysis. a)-True b)- False

Answers

Answer:

b). False

Explanation:

Lumped body analysis :

Lumped body analysis states that some bodies during heat transfer process remains uniform at all times. The temperature of these bodies is a function of temperature only. Therefor the heat transfer analysis based on such idea is called lumped body analysis.

                      Biot number is a dimensionless number which governs the heat transfer rate for a lumped body. Biot number is defined as the ratio of the convection transfer at the surface of the body to the conduction inside the body. the temperature difference will be uniform only when the Biot number is nearly equal to zero.  

                      The lumped body analysis assumes that there exists a uniform temperature distribution within the body. This means that the  conduction heat resistance should be zero. Thus the lumped body analysis is exact when biot number is zero.

In general it is assume that for a lumped body analysis, Biot number \leq 0.1

Therefore, the smaller the Biot number, the more exact is the lumped system analysis.

1. The presentation of data is becoming more and more important in today's Internet. Some people argue that the TCP/IP protocol suite needs to add a new layer to take care of the presentation of data. If this new layer is added in the future, where should its position be in the suite?

Answers

Answer:

It is important to add presentation layer after the physical layer, so that the data along with it's headers can be translated, when the receiver machine is applying a set of different characters.

Data compression is also required to reduce the space that is occupied by data during transmission, now once the presentation is added to the physical layer, data from the physical layer can be compressed at the presentation layer and sent by improving the throughput.

Explanation:

Solution

The presentation of data involves the following as shown below:

Presentation of data comprises of the task like translating between receiver and sender devices so that machines with different capabilities sets can communicate with one another.

It involves encoding  and decoding of data to provide data security that is been transmitted by different machines.

Data sometimes needs to compressed for efficiency improvement  for transmission.

The physical layer of the TCP/IP protocol suite is responsible or refers to the transmission of physical data over a physical medium

It is good or important to add presentation layer after the physical layer, so that the data along with it's headers can be translated, when the receiver machine is applying a set of different characters.

Data encryption at this stage is good for security instead of encrypting the data at upper/higher layers.

Hence, it is advisable to add presentation layer after the physical layer in the TCP/IP suite.

Answer:

 

The layer ought to be embedded between Layer 2 and 3.

Explanation:

Applications often communicate with each other. This cannot be successful if they don't see data the same way. The Presentation Layer in the Open Systems Interconnection defines how data is presented and is often processed in the TCP/IP applications.

While the Presentation Layer does not exist as a different layer in the TCP/IP protocol order of arrangement, it is important to note that the Network Layer is also known referred to as the TCP/IP’s Network Layer.

Therefore, if the presentation of the data layer will be separated, it should be between layer 2 and 3.  

Cheers!

A Coca Cola can with diameter 62 mm and wall thickness 300 um has an internal pressure of 100 kPa. Calculate the principal stresses at a point on the cylindrical surface of the can far from its ends.

Answers

Answer:

\sigma _1=10.33MPa

\sigma _2=5.16MPa

Explanation:

Given that

Diameter(d)=62 mm

Thickness(t)= 300 μm=0.3 mm

Internal pressure(P)=100 KPa

Actually there is no any shear stress so normal stress will become principle stress.This is the case of thin cylinder.The stress in thin cylinder are hoop stress and longitudinal stress .

The hoop stress

\sigma _h=(Pd)/(2t)

Longitudinal stress

\sigma _l=(Pd)/(4t)

Now by putting the values

\sigma _h=(Pd)/(2t)

\sigma _h=(100* 62)/(2* 0.3)

\sigma _h=10.33MPa

\sigma _l=5.16MPa

So the principle stress are

\sigma _1=10.33MPa

\sigma _2=5.16MPa

Indicate whether the following statements are true or false for an isothermal process: (A) Q=T(∆S). (B) ∆U=0.(C) The entropy change of the system is always zero. (D) The total entropy change of the system and the surroundings is always zero. (E) The entropy change of the surroundings is negative. (F) Q=W.

Answers

Answer:

A=False

B=False

C=False

D=False

E=False

F=False

Explanation:

A. In an isothermal process, only the reversibly heat transfer is 0, Q_(rev)=T (\Delta S)

B. Consider the phase change of boiling water. Here, the temperature remains constant but the internal energy of the system increases.

C. This is not true even in reversible process, as can be inferred from the equation in part A.

D. This is only true in reversible processes, but not in all isothermal processes.

E. Consider the phase change of freezing water. Here, the surroundings are increasing their entropy, as they are taking in heat from the system.

F. This is not true if (\Delta U)\neq 0, like in answer B. One case where this is true is in the reversible isothermal expansion (or compression) of an ideal gas.

What is the difference between absolute and gage pressure?

Answers

Explanation:

Step1

Absolute pressure is the pressure above zero level of the pressure. Absolute pressure is considering atmospheric pressure in it. Absolute pressure is always positive. There is no negative absolute pressure.

The expression for absolute pressure is given as follows:

P_(ab)=P_(g)+P_(atm)

Here, P_(ab) is absolute pressure, P_(g) is gauge pressure andP_(atm) is atmospheric pressure.

Step2

Gauge pressure is the pressure that measure above atmospheric pressure. It is not considering atmospheric pressure. It can be negative called vacuum or negative gauge pressure. Gauge pressure used to simplify the pressure equation for fluid analysis.  
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