CHEMISTRY COLLEGE

What are four properties of water?

Answers

Answer 1
Answer:

Answer:

Polarity

Cohesion  

Adhesion

High Specific Heat

Explanation:

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Which one of the following combinations cannot function as a buffer solution?A) HCN and KCN
B) NH3 and (NH4)2SO4
C) HNO3 and NaNO3
D) HF and NAF
E) HNO2 and NaNO2

Answers

Answer:

it is B

; )

Which one of the following combinations cannot function as a buffer solution?

A) HCN and KCN

B) NH3 and (NH4)2SO4

C) HNO3 and NaNO3

D) HF and NAF

E) HNO2 and NaNO2

Find the mole ratio of H2SO4 and H20 in the equation Fe2O3 + H2SO4 → Fe2(SO4)3 + H20.

Answers

Explanation:

Fe2O3 +3 H2SO4 → Fe2(SO4)3 + 3H20.

Therefore the ratio is 3:3

LAST ATTEMPT IM MARKING AS BRAINLIEST!! (What is this compound ? )

Answers

Answer:

its water h²O

Explanation:

Hopeitshelp

In the equilibrium system described by: PO43-(aq) + H2O(1) = HPO42-(aq) + OH-(aq) Brønsted-Lowry theory would designate: A) PO43- and H20 as the bases B) H20 and OH as a conjugate pair C) HPO42- and OH"" as the acids D) HPO42- and H20 as a conjugate pair E) PO43-as amphiprotic

Answers

Answer:

The correct option is:  B) H₂0 and OH⁻ as a conjugate pair

Explanation:

According to Brønsted-Lowry theory, theacids are the chemical substances that form a conjugate base by donating a proton and bases are the chemical substances that form conjugate acid by accepting a proton.

In the given chemical reaction: PO₄³⁻(aq) + H₂O(l) ⇄ HPO₄²⁻(aq) + OH⁻(aq)

According to Brønsted-Lowry theory, PO₄³⁻ and OH⁻ are bases. Whereas, H₂O and HPO₄²⁻ are acids.

Also, PO₄³⁻ and HPO₄²⁻ are the conjugate acid-base pair; and H₂O and OH⁻ are the conjugate acid-base pair.

7. A change of state is a(n)_process.
a. Irreversible
b. Reversible

Answers

Answer: b

A change of state is a reversible process.

B that’s the answer

Good luck

I have a cup of hot coffee at 140 oC but I want to cool it to 110 oC. My cup holds about 0.3 kg of coffee. Fortunately, I have a bunch of aluminum cubes in the freezer that I can drop into my hot coffee to cool it down. If each aluminum cube has a mass of 1 g (not 1 kg!) and my freezer keeps its contents at a temperature of –10 oC, how many cubes do I have to drop into my coffee? The specific heat of water is around 4000 joules/kg/oC and aluminum is about 900 joules/kg/oC. (Pick the answer closest to the true value and ignore any thermal losses to surroundings.)

A. 200
B. 330
C. 400
D. 110
E. 88

Answers

Answer:

The correct answer is option B.

Explanation:

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1* c_1* (T_f-T_1)=-m_2* c_2* (T_f-T_2)

where,

C_1 = specific heat of metal = 900 J/kg^oC

C_2 = specific heat of coffee= 4000 J/kg^oC

m_1 = mass of metal = x

m_2 = mass of coffee = 0.3 kg

T_f = final temperature of aluminum metal= 110^oC

T_1 = initial temperature of aluminum metal = -10^oC

T_2 = initial temperature of coffee= 140^oC

Now put all the given values in the above formula, we get

x* 900 J/kg^oC* (110-(-10))^oC=-(0.3 kg* 4000 J/kg^oC* (110-140)^oC

x=0.333 kg

Mass of aluminum cubes = 0.3333 kg = 333.3 g

If mass of 1 cube is 1 gram, then numbers of cubes in 333.3 grams will be:

=(333.3 g)/(1 g)=333.3\approx 330

330 cubes of aluminum cubes will be required.
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I will give Brainliest and 30 points to whoever answers first!
Ammonium nitrate dissociates in water according to the following equation:43() = 4+()+03−()When a student mixes 5.00 g of NH4NO3 with 50.0 mL of water in a coffee-cup calorimeter, the temperature of the resultant solution decreases from 22.0 °C to 16.5 °C. Assume the density of water is 1.00 g/ml and the specific heat capacity of the resultant solution is 4.18 J/g·°C.1) Calculate q for the reaction. You must show your work.2) Calculate the number of moles of NH4NO3(s) which reacted. You must show your work.3) Calculate ΔH for the reaction in kJ/mol. You must show your work.