Answers
Answer:
To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN
Explanation:
Dilution is the reduction of the concentration of a chemical in a solution and consists simply of adding more solvent.
In a dilution the amount of solute does not vary. But as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
In a solution it is fulfilled:
Ci* Vi = Cf* Vf
where:
- Ci: initial concentration
- Vi: initial volume
- Cf: final concentration
- Vf: final volume
In this case:
- Ci= 1.40 M
- Vi= 20 mL
- Cf= 0.088 M
- Vf= ?
Replacing:
1.40 M* 20 mL= 0.088 M* Vf
Solving:
Vf= 318.18 mL
To 318.18 mL would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a 0.0880 M solution of LiCN
Final answer:
To make a 0.0880 M solution of LiCN, you would need to dilute 20.0 mL of the 1.40 M solution to a final volume of 318.18 mL.
Explanation:
To dilute a solution, you can use the formula:
M1V1 = M2V2
where M1 and V1 are the initial molarity and volume, and M2 and V2 are the final molarity and volume. Rearranging the formula, we can solve for V2:
V2 = (M1 · V1) / M2
Plugging in the values given:
V2 = (1.40 M · 20.0 mL) / 0.0880 M = 318.18 mL
To make a 0.0880 M solution of LiCN, you would need to dilute 20.0 mL of the 1.40 M solution to a final volume of 318.18 mL.
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Answers
A- Each Compound contains only one element.
B- Compound can be classified as either heterogenous or homogenous.
C- A Compound has a defined ratio by mass of the elements that it contains
D- Compounds Vary in chemical composition depending on the sample size.
Answers
The following statements about compounds is true that a compound has a defined ratio by mass of the elements that it contains. Option C is correct.
A compound is a substance that is made up of two or more elements that are chemically bonded together. The elements in a compound are always present in a fixed ratio by mass. This means that no matter how much of the compound you have, the ratio of the elements will always be the same.
For example, water is a compound that is made up of hydrogen and oxygen. The ratio of hydrogen to oxygen in water is always 2:1 by mass. This means that no matter how much water you have, there will always be twice as much hydrogen as oxygen.
A compound can be classified as either homogeneous or heterogeneous, but not both. Homogeneous compounds have a uniform composition throughout, while heterogeneous compounds have different compositions in different parts of the sample. Compounds do not vary in chemical composition depending on the sample size. The chemical composition of a compound is always the same, regardless of how much of the compound you have. Option C is correct.
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Explanation:
A and D is the answer
Hope the answer is right
Answers
Answer:
Option (A) saturated and is at equilibrium with the solid KCl
Explanation:
A saturated solution is a solution which can not dissolve more solute in the solution.
From the question given above, we can see that the solution is saturated as it can not further dissolve any more KCl as some KCl is still visible in the flask.
Equilibrium is attained in a chemical reaction when there is no observable change in the reaction system with time. Now, observing the question given we can see that there is no change in flask as some KCl is still visible even after thorough shaking. This simply implies that the solution is in equilibrium with the KCl solid as no further dissolution occurs.
A. X will react in water, but only if the temperature is low enough
B. Y will form oxides of X, but only indirectly
C. X will replace ions of Y in a solution
D. Y will replace ions of X in a solution
Answers
Answer:
D. Y will replace ions of X in a solution
Explanation:
If metal X is lower than metal Y on the activity series, then Y will replace ions of X in a solution.
This is the crux of single displacement reactions.
- In a single displacement reaction, a metallic ion in solution is replaced by a metal higher in the activity series than the metal in solution.
- On the activity series, metals higher are more reactive and will displace the lower and less reactive ones.
- Reactivity increases up the group.
3.3 x 10^-25 atoms
1.01 x 10^-3 moles
Answers
Given:
n = 0.20 mol
Required:
N
Solution:
N = n × 6.02 × 10²³ atoms/mol
N = 0.2 mol × 6.02 × 10²³ atoms/mol
N = 1.20 × 10²³ atoms
Therefore, there are 1.20 × 10²³ gold atoms in 0.2 mol of a gold sample.
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1.01 x 10^-3 moles
Answers
The percent yield of the reaction : 89.14%
Further explanation
Reaction of Ammonia and Oxygen in a lab :
4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)
mass NH₃ = 80 g
mol NH₃ (MW=17 g/mol):
mass O₂ = 120 g
mol O₂(MW=32 g/mol) :
Mol ratio of reactants(to find limiting reatants) :
mol of H₂O based on O₂ as limiting reactants :
mol H₂O :
mass H₂O :
4.5 x 18 g/mol = 81 g
The percent yield :