PHYSICS HIGH SCHOOL

If you travel at 3 m/s for 12 seconds, how far did you travel?

Answers

Answer 1

Answer:

Answer:

$\boxed {\tt 36 \ meters }$

Explanation:

We want to find how far was traveled, or the distance.

The formula for distance is:

$d=s*t$

where $s$ is the speed and $t$ is the time.

The speed is 3 meters per second and the time is 12 seconds.

$s= 3 \ m/s \nt= 12 \ s$

Substitute the values into the formula.

$d= 3 \ m/s * 12 \ s$

Multiply. Note that when multiply, the seconds, or $s$ will cancel.

$d= 3 \ m * 12$

$d= 36 \ m$

$d= 36 \ meters$

The distance traveled was 36 meters.

Answer 2

Answer:

V=3 m/s

t=12 seconds

S=?

S=V×t

S=3×12

S=36meters

So distance you travel is 36meters.

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A car maintains a constant velocity of 100 km/hr for 10 seconds. During this interval its acceleration is A) zero.
B) 10 km/hr.
C) 110 km/hr.
D) 1000 km/hr.

Answers

A.) acceleration is to increase or decrease in speed the only time your not accelerating is when your not moving or your going a constant speed

Which type of star has the widest range in brightness and surface temperature?a. giant
b. white dwarf
c. neutron
d. main sequence

Answers

Answer:

the best answer is Giant.

Explanation:

I believe It's...

d. main sequence

Why are some consolation visible to New York State observers at midnight during April , but not visible at midnight during October

Answers

"Midnight" means looking away from the Sun. But in 6 months from April to October the earth goes halfway around the Sun. So midnight in April and midnight in October are exactly opposite directions.

An "E" tuning fork with a frequency of 329 Hz is used to test the "E" note of a piano. Four beats are heard. This means _____.The piano key is in tune.
The piano key is out of tune and has a frequency of 333 Hz.
The piano key is out of tune and has a frequency of 325 Hz.
The piano key is out of tune and has a frequency of either 325 or 333 Hz

Answers

The correct choice is

The piano key is out of tune and has a frequency of either 325 or 333 Hz

Beat frequency has been given as 4 Hz. hence the frequency must be above or below the given frequency of 329 Hz by 4 Hz. To get the upper level of frequency we add the beat frequency to the given frequency. To get the lower level, we subtract the beat frequency from the given frequency

f' = 329 + 4 = 333 Hz

and

f'' = 329 - 4 = 325 Hz

The piano key is out of tune and has a frequency of either 325 or 333 Hz

Which item is not considered electromagnetic energy?

Answers

Sound waves are known to be the one that's not considered as a type of electromagnetic energy. As for microwaves and x-rays, they tend to share the same frequencies that can be considered as electromagnetic, and sound waves have a different frequency than them.

NASA decides to put a 128 kg satellite into orbit over the planet Venus because they want to take pictures. The satellite is 37,000,000 m above the surface of venus. Calculate the gravitational field at that altitude. m/s2
how do you calculate this

Answers

1). Look up the acceleration of gravity on the surface of Venus. It's 8.87 m/s².
(That's about 10% less than on Earth.)

2). Look up the radius of Venus. It's 6051.8 km.
(That's about 5% less than Earth's.)

3). Remember that the gravitational field (acceleration, force) changes
opposite to the square of the distance from the planet ... or the distance
between any two masses that are gravitating.

Now we have enough information to do the calculating. Notice that the question
only asks for the planet's "gravitational field" (acceleration) way out there. That
has nothing to do with the satellite's mass, or whatever you decide to put out there,
or even if there's nothing out there at all. It's just a characteristic of Venus at that
distance from it.

The distances we need to compare are the distances from the center of Venus.

On the surface (distance from the center is the radius of Venus), it's 6,051,800 m.
In the orbit, it's 37,000,000 m.

The ratio is (37,000,000 / 6,051,800) = about 6.1 .

The gravity way out in the orbit is less than on the surface, and by the
same amount as the square of the distance ratio.

Surface gravity = 8.87

Gravity out at the orbit = 8.87 divided by (the distance ratio)²

Gravity = 8.87 / (6.1)²

Better way: Gravity = 8.87 x (6,051,800/37,000,000)² = 0.2373 m/sec²

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