How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?

Answers

Answer 1

Answer: Answer: Force = 81.6 N

Explanation:
According to Newton's Second law:
F = ma --- (1)

Where F = Force = ?
m = Mass = 68 kg
a = Acceleration = 1.2 m/s^2

Plug in the values in (1):
(1) => F = 68 * 1.2
F = 81.6 N (The force needed to accelerate the skier at a rate of 1.2 m/s^2)

Answer 2

Answer:

Answer:

The force needed to accelerate a 68 kilogram-skier at a rate of 1.2ms2 is 81.6 Net forces

Explanation:

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A 2.50 × 105 W motor is used for 26.4 s to pull a boat straight toward shore. How far does the boat move toward shore if a force of 4.20 × 104 N is applied by the motor?

Answers

The power of the motor is
2.50x10⁵ W
or
2.50x10⁵ N m/s

The time it takes to pull the boat is
26.4 s

The force applied is
4.20x10⁴ N

The distance traveled by the boat is
2.50x10⁵ N m /s (26.4 s) / (4.20x10⁴ N)
= 157.14 m

Answer:

157 m

Explanation:

right on ed2020

Which describes the characteristics of a liquid?a. It has no fixed volume or shape.
b. It has a fixed volume and shape.
c. It has high energy and expands to fill the container.
d. It has a fixed volume and varied shape.

Answers

What happens when you pour water in a glass? It takes the shape of the glass. This means that water can't have a fixed shape or volume

An object has one force acting on it. it is a 33-newton force pointing downward. to create a net force of zero on the object, which force must be applied to it?

Answers

For this case, the first thing we are going to do is define a reference system.

We define the vertical axis of the reference system, pointing upwards.

Therefore, doing summation of forces in vertical direction we have:

Then, since we want the net force to be equal to zero, then:

From here, we clear the force that we must apply on the object:

The positive sign means that the force points upwards.

Answer:

to create a net force of zero on the object you must apply:

33 Newton upwards.

to get a net force of zero you need 33 newton force pointing upwards.

Why does it make sense that a 9 Liter pot of boiling water has more heat than a 1.5 L pot of boiling water?

Answers

Explanation:

because 9 is more than 1.5 and the more water, the more heat

Determine the volume at the equivalence point if a 0.100 M NaOH(aq) solution is used to titrate the following acidic solutions: (a) 50.0 mL of 0.200 M HBr(aq) (b) 30.0 mL of 0.150 M HNO3(aq)

Answers

Answer:

a) NaOH volume at the equivalence point is 100 ml.

b) NaOH volume at the equivalence point is 45 ml.

Explanation:

To calculate the concentration of acid, we use the equation given y neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base

a) If a 0.100 M NaOH (aq) solution is used to titrated with 50.0 mL of 0.200 M HBr(aq).

We are given:

$n_1=1\nM_1=0.200M\nV_1=50.0mL\nn_2=1\nM_2=0.100M\nV_2=?mL$

Putting values in above equation, we get:

$1* 0.200M* 50.0 mL=1* 0.100 M* V_2\n\nV_2=100 mL$

b) If a 0.100 M NaOH (aq) solution is used to titrated with 30.0 mL of 0.150 M $HNO_3$ (aq).

We are given:

$n_1=1\nM_1=0.150M\nV_1=30.0mL\nn_2=1\nM_2=0.100M\nV_2=?mL$

Putting values in above equation, we get:

$1* 0.150M* 30.0 mL=1* 0.100 M* V_2\n\nV_2=45 mL$

What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge?

Answers

In an electric field force,F= q₁q₂/4πε₀ r² (coulomb's law) as we know,F=qE E=F/q
E=q/4πε₀ r²
here,r= 0.0075 m
q= 0.0035 C
1/4πε₀ = 9×10⁹
E= 9×10⁹× 0.0035/(0.0075)²
=5.6 ×10¹¹ N/C

Answer:

5.6x1011 N

Explanation:

I just got the wrong answer so here's the right one

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