2. The speed of truck is 39 m/s. How long does it take for the truck to travel 9,000 m?

Answers

Answer 1
Answer:

Answer:

\boxed {\tt 230.769231 \ seconds}

Explanation:

Time can be found by dividing the distance by the speed.

t=(d)/(s)

The distance is 9,000 meters and the speed is 39 meters per second.

d= 9,000 \ s\ns=39 \ m/s

Substitute the values into the formula.

t=(9,000 \ m)/(39 \ m/s)

Divide. Note that the meters, or "m" will cancel out.

t=(9,000)/(39 \ s)

t=230.769231 \ s

It takes 230.769231 seconds for the truck to travel 9,000 meters at 39 meters per second.


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An object has a mass of 20,000kg and a density of 4000kg/m? What is its
volume?​

Answers

The answer is 20000kg

How much work is required to move3.0 coulombs of electric charge a distance of
0.010 meter through a potential difference of
9.0 volts?
(1) 2.7 × 10^3 J (3) 3.0 J
(2) 27 J (4) 3.0 × 10^−2 J

Answers

So we want to know how much work is needed to move a charge Q=3C for a distance r=0.01m trough a potencial difference U=9V. Work of electric potential is defined as W=Q*U and we can now simply put in the numbers. We get: W=3C*9V=27J. So the correct answer is (2) 27J.

Earth's gravity acts upon objects with a steady force of __________.a. 8.9 meters per second
b. 9.8 meters per minute
c. 8.9 meters per minute squared
d. 9.8 meters per second squared

Answers

None of the choices is a force. 'a' and 'b' are speeds. 'C' and 'd' are accelerations. ... The steady force of gravity is 9.8 newtons PER KILOGRAM of mass. ... The question is written by someonewho very much wants to discourage anyone interested in Physics.

Answer:

9.8 meters per second squared

Explanation:

A stone is thrown with an initial velocity of 20 meters per second straight upward from the edge of a cliff 100 meters above a canyon floor. The stone just misses the cliff'a edge on its way down. (Neglect friction) Calculate the time required for the stone to reach its maximum height.
Calculate the maximum height of the stone above the edge of the cliff.

Answers

The time taken by the stone to reach the maximum height above the cliff is \boxed{2.04\text{ s}} and the maximum height reached by the stone above the cliff is \boxed{20.4\text{ m}}.

Explanation:

Given:

The initial velocity of the stone is 20\text{ m/s}.

The height of the cliff is 100\text{ m}.

Concept:

As the stone is thrown upward from the top of the cliff, the stone will move under the action of the acceleration due to gravity. The speed of the stone will decrease as it moves up because the acceleration on the stone is acting in the direction opposite to its motion.

The speed of the stone at its maximum height will be zero where is comes to rest for a moment.

The time taken by the stone to reach the maximum height is given by:

\boxed{v_f=v_i-gt}

Here, v_f is the final velocity, v_i is the initial velocity, g is the acceleration and t is the time taken by the stone.

Substitute the values in above expression.

\begin{aligned}0&=20-(9.81)t\nt&=(20)/(9.81)\text{ s}\n&=2.04\text{ s}\end{aligned}

The distance covered by the stone in reaching the maximum height is given by:

\boxed{v_f^2=v_i^2-2gS}

Here, S is the distance covered by the stone.

Substitute the values in above expression.

\begin{aligned}(0)^2&=(20)^2-2(9.81)S\nS&=(400)/(19.62)\text{ m}\n&=20.4\text{ m}\end{aligned}

Thus, The time taken by the stone to reach the maximum height above the cliff is \boxed{2.04\text{ s}} and the maximum height reached by the stone above the cliff is \boxed{20.4\text{ m}}.

Learn More:

1. Compare the three types of friction brainly.com/question/1800116

2. The scale reading if the cable breaks suddenly brainly.com/question/4852539

3. The height of bridge above water brainly.com/question/10664397

Answer Details:

Grade: Senior School

Subject: Physics

Chapter: Kinematics

Keywords:

stone, initial velocity, final, thrown, cliff, canyon floor, maximum height, zero, acceleration, gravity, time taken, distance.


I thought you were going to ask how long it takes for the stone to hit
the canyon floor at the bottom of the cliff.  But you're not asking for
anything after the stone barely misses the edge of the cliff on its way
down, and you're only asking about things that happen above the
edge of the cliff. So we don't need to know anything about the cliff,
or its height above anything else.  The thrower might just as well be
standing in his front yard when he throws the stone straight up.

-- Gravity robs 9.8 m/s from the stone's upward speed every second.
So the stone reaches its maximum height, runs out of upward gas, and
starts falling, in  (20 / 9.8) = 2.04 seconds after the toss.

-- Its average speed during that time is (1/2) (20 + 0) = 10 m/s .
In 2.04 seconds at that average speed, it rises (2.04 x 10) = 20.4 meters .


Paula spots a glider located at an angle of elevation of 42 degrees. the distance between the glider and paula is 3280 feet. to the nearest foot, what is the height of the glider h from the ground?

Answers

This situation represents triangle with one angle of 90 degrees. That angle is directly below glider. That means that we can you basic trigonometry functions.

sin42 = h/3280

Now we express h.
h = 3280* sin42 
h = 2195 feet

The answer is 2195 feet.

distance = 3280 feet. This is the triangle's hypotenuse.

The distance from the ground is the opposite side as it is opposite the angle 42˚


Sin = Opposite/Hypotenuse

Sin(42) = Opposite/3280   Answer: 2195 feet

Cross multiply

Opposite = sin(42) x 3280

Opposite = 2194.7 feet


APAKAH VOLUME 5 KG ES SAMA DENGAN VOLUME 5KG AIR APA YG MEMBEDAKAN KEDUA ZAT TERSEBUT

Answers

Answer:c

Explanation:ganglandd