A crane raises a 150 N weight to a height of 2.0 m in in 5.0 s. The crane does work at a rate of

Answers

Answer 1

Answer: The work done is (force) x (distance) = (150N) x (2m) = 300 joules.

The crane does the work at the rate of (300 J) / (5 sec) = 60 joules per second.

That rate ... (work done) / (time to do the work) ... is called power.

That 60 joules per second is called 60 watts .

Answer 2

Answer:

Answer:

60. W

Explanation:

60 Watts

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How many cars can fit in a football field?

Answers

5211.6 Car can fit in a football field.

What is the dimension of football pitch?

The recommended dimensions of a football pitch are 105m x 68m, which is 7,140 sq meters.

The average length of a car is around 14.7 feet.

i.e. 1.37 sq meters

By dividing the football pitch by length of car,

= 7140/ 1.37

= 5211.6 Car

With no gaps of course.

Therefore,

In a football field 5211.6 cars can be fit without no gap.

Learn more about Football pitch here:

brainly.com/question/20346808

#SPJ2

100 cars can fit into a football field

Explain the relationship between heat and physical state of a substance.

Answers

Answer:

When thermal energy is added to a substance, its temperature increases, which can change its state from solid to liquid (melting), liquid to gas (vaporization), or solid to gas (sublimation).

15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?show step by step

Answers

We know that there is a formula velocity = frequency x wavelength for all types of waves.

If we assume one complete oscillation of a pendulum to be wavelength we can apply the above formula for the pendulum too.

So as v = fλ and f = v/λ we can just plug in the values to get our answer of frequency.

So frequency = 30/0.35 which is equal to 85.17 Hertz (Hz).

I think you're trying to take the formulas for speed, wavelength, and
frequency of a wave, and apply them to a pendulum. You can't do that.
It doesn't work.

A pendulum is moving in 'simple harmonic motion', not wave motion.
It's speed is continuously changing, from zero at both ends of its swing,
to maximum as it passes through the 'rest' position at the bottom. And
there's no wavelength defined for a pendulum ... if you're thinking that
it could be the distance from end to end of its swing, or maybe half of
that, you should know that the frequency of an ideal simple pendulum
is not related to that distance at all.

Finally, in the real world, the numbers in this question really kind of
don't make any sense. You have a structure where some part of it is
roughly a foot long (0.35m = 13.8 inches), and at least at some point
during its swing, something is moving at 30 m/s ... about 67 mph !
If something like that could even stay on the table, and IF its frequency
were (speed/wavelength) ... like a wave's frequency is ... then its frequency
would be (30 / 0.35) = 85.7 Hz ! ! The thing would be wiggling back and
forth every 0.017 second ! It would need to be operated only inside
a bomb shelter, with all personnel withdrawn beyond a safe perimeter
before it flies apart and scatters shrapnel everywhere.

A train traveling at 82.8 kilometers per hour is blowing its horn as it approaches you. The horn has a frequency of 312 Hz. Assume the speed of the sound is 331 m/s. What is the observed frequency of the horn?335 Hz
312 Hz
292 Hz
412 Hz

Answers

The answer is 335 Hz.

To calculate this, we will use the following formula:
f₀ = f × v ÷ (v - v₁)
where:
f₀ - frequency heard
f - actual frequency
v - speed of sound
v₁ - speed of source

We know:
f = 312 Hz
v = 331 m/s
v₁ = 82.8 km/h = 23 m/s

We need:
f₀ = ?

f₀ = f × v ÷ (v - v₁)
⇒ f₀ = 312 Hz x 331 m/s ÷ (331 m/s - 23 m/s)
⇒ f₀ = 312 Hz × 331 m/s ÷ 308 m/s
⇒ f₀ = 335.3 Hz ≈ 335 Hz

Thus, the frequency of the horn is 335 Hz.

Answer:

335 Hz

Explanation:

100%

A cyclist rides in a circle with speed 8.1 m/s. What is his centripetal acceleration if the circle has a radius of 27 m? A. 3.3 m/s^2 B. 2.4 m/s^2 C. 0.3 m/s^2 D. 1.8 m/s^2

Answers

The answer would be B. 2.4

You're welcome.

Answer:

Answer is B. Just took it!

Explanation:

Which statement is true about how objects appear to bend that are partially submerged in water?They appear to bend at the surface due to reflection.
They appear to bend at the surface due to refraction.
They appear to bend at the surface due to diffraction.
They appear to bend at the surface due to interference

Answers

The correct answer to the question is: B) They appear to bend at the surface due to refraction.

EXPLANATION:

When light moves from optical rarer medium to optical denser medium, the light rays are bent towards the normal at the point of incidence on the refracting surface. If the order is changed, then the way will be away from the normal.

This property of light is known as refraction which is due to the fact that light has different velocities in different media.

As per the question, the object appears to be bent when it is submerged in water. Actually the object is not bent. Its the light from object which is bent at the air-water interference.

Hence, the correct answer of this question is refraction.

Answer:

answer is b

Explanation:

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