The combustion of ethane (C 2 H 6 ) produces carbon dioxide and steam. 2C 2 H 6 (g)+7O 2 (g) 4CO 2 (g)+6H 2 O(g)

How many moles of CO 2 are produced when 5.95 mol of ethane is burned in an excess of oxygen?

Answer:it’s 828292atoms

Explanation

Answer

Naphthalene is a non electrolyte

If the unknown compound is an electrolyte it gives 2 or more ions in solution

( NaCl >> Na+ + Cl- => 2 ions

Ca(NO3)2 >> Ca2+ + 2 NO3- => 3 ions)

the f.p. lowering is directly proportional to the molal concentration of dissolved ions in the solution )

For naphthalene

delta T = 1.86 x m

for a salt that gives 2 ions

delta T = 1.86 x m x 2

hence the lowering in freezion point of unkown is greater then napthalene

Answer:

0.4590

Explanation:

How the refractive index of the hexane + toluene mixture varies linearly with mole fraction, it means that the mole fraction is the fraction that each pure index contribute for the mixture index, so, calling xh the mole fraction of hexane and xt the mole fraction of toluene:

1.375xh + 1.497xt = 1.441

And, xh + xt = 1 (because there are only hexane and toluene in the mixture), so xt = 1- xh

1.375xh + 1.497(1-xh) = 1.441

1.375xh + 1.497 - 1.497xh = 1.441

-0.122xh = -0.056

xh = -0.056/(-0.122)

xh = 0.4590

Answer:

a. 5.39 atm

Explanation:

Pressure = ?

Volume = 1 L

Temperature = 298 K

Mass = 9.70g

The formular relating these variables is the ideal gas equation;

PV = nRT

where R = gas constant = 0.082057 L.atm.K-1.mol-1

n can be obtained from the formular below;

n = mass / molar mass = 9.70 / 44

n = 0.2205 mol

P = nRT / V

P = 0.2205 * 0.082057 * 298 / 1

P = 5.392 atm

The correct option is option A.

Answer:

2.57 × 10²⁴ molecules

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.27 × 6.02 × 10²³

We have the final answer as

2.57 × 10²⁴ molecules

Hope this helps you