CHEMISTRY COLLEGE

How do you figure out the # of
neutrons?

Answers

Answer 1
Answer:

Answer:

Subtracting the number of protons from the atomic mass.
Answer 2
Answer:

Answer:

Subtract Protons

Explanation:

Since the vast majority of atom's mass is found it's protons and neutrons, Subtracting the Number of Protons ( i.e. the atomic number ) from the atomic mass will give you the calculated number of neutrons in a atom,

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What is the mass of ammonium nitrate in 250 mL of a 75% by mass solution (density = 1.725 g/mL)?
In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)
When calcium carbonate reacts with hydrogen chloride, if the reaction occurs with 78.5% yield, what mass of carbon dioxide will be collected if 19.88g of CaCO3 is added to sufficient hydrogen chloride?

Calculate the solubility of CuX (Ksp=[Cu2+][X2−]=1.27×10−36) in a solution that is 0.200 M in NaCN.I have already tried to square root the Ksp value to get the answer but it was wrong.

Answers

Answer:

Solubility= 1.08×10-12

Explanation:

Take the cube root of 1.27×10-36

Answer:

The solubility of CuX is 1.425x10⁻⁷M

Explanation:

Given:

initial concentration of NaCN=0.2M

Ksp=1.27x10⁻³⁶

The reaction are:

CuX → Cu²⁺ + X²⁺, Ksp=1.27x10⁻³⁶

Cu²⁺ + 4CN⁻ → (Cu(CN)₄)²⁻, Kf=1x10²⁵

The overall reaction is:

CuX + 4CN⁻ → (Cu(CN)₄)²⁻ + X²⁺

The equilibrium constant is:

K=Ksp*Kf=1.27x10⁻³⁶*1x10²⁵=1.27x10⁻¹¹

              CuX      +        4CN⁻      →       (Cu(CN)₄)²⁻ +        X²⁺

I              -                      0.2                    0                         0

C            -                       -4                     +x                        +x

E             -                      0.2-4                x                          x

The equation for equilibrium is:

K=([Cu(CN)4]^(2) [X])/([CN]^(4) ) \n1.27x10^(-11) =(x^(2) )/((0.2-x)^(4) )

Here, solving for x:

x=1.425x10⁻⁷M=CuX

Find the mass of oxygen in grams produced by the decomposition of 100.0 g of CO2

Answers

The balanced chemical equation is :

2CO_2->2CO+O_2\n\n

Moles of CO_2 ,

n = (100\ g)/(44.01\ g/mol)\n\nn=2.27\ mol

Now, by given chemical equation , we can see 2 mole of CO_2 react with 1 mole of O_2.

So , 2.27 mole react with :

N=(2.27)/(2)\ mol\n\nN=1.135\ mol

Mass of oxygen is :

M = N * 16\n\nM=1.135* 16\ g\n\nM =18.16\ g

Therefore, mass of oxygen in grams produced is 18.16 g.

Hence, this is the required solution.

What two processes are occurring in this picture A.erosion and deposition
B.weathering and deposition
C.weathering and erosion

Answers

Answer:

C. weathering and erosion

Explanation:

Need help asap please! This is for a very important test. Giving brainliest to best answerTwo different atoms have four protons each and the same mass. However, one has a negative charge while the other is neutral. Describe what each atomic structure could be, listing the possible number and location of all subatomic particles.

Answers

Answer:

The three subatomic particles are the particles contained in the iota. They are protons, neutrons, and electrons. Protons and electrons convey a positive and negative charge, individually, while neutrons don't convey any change

Explanation:

A fruit fly is considered a consumer rather than a producer why

Answers

In an ecosystem, the only true producers are autotrophic organisms like plants and bacteria. These organisms produce energy by converting the energy from the sun into simple sugars.
All of the other organisms in the food chain, like the fruit fly, are simply consuming the energy produced by the plants/bacteria and not actually making/producing energy from a new source.

Structure and function of cellulose?

Answers

Answer:

Cellulose is a major component of tough cell walls that surround plant cells, and it's what makes plant stems, leaves, and branches so strong. ... This forms long, cable-like structures, which combine with other cellulose molecules and is what produces such a strong support structure.

Explanation:

Answer:

Cellulose, a tough, fibrous, and water-insoluble polysaccharide, plays an integral role in keeping the structure of plant cell walls stable.

Explanation:

Cellulose chains are arranged in microfibrils or bundles of polysaccharide that are arranged in fibrils (bundles of microfibrils), which in turn make up the plant cell wall.
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