MATHEMATICS COLLEGE

A manufacturing company has two retail outlets. It is known that 40% of all potentialcustomers buy products from outlet 1 alone, 35% buy from outlet 2 alone, and 10% buy fromboth 1 and 2. LetAdenote the event that a potential customer, randomly chosen, buys fromoutlet 1, and letBdenote the event that the customer buys from outlet 2. Suppose a potentialcustomer is chosen at random. For each of the following events, represent the eventsymbolically and then find its probability.Required:
a. The customer buys from outlet 1.
b. The customer does not buy from outlet 2.
c. The customer does not buy from outlet 1 or does not buy from outlet 2.
d. The customer does not buy from outlet 1 and does not buy from outlet 2.

Answers

Answer 1

Answer:

Answer:

$P(A) = 0.50$

$P(B') = 0.55$

$P(A' U B') = 0.775$

$P(A'B') = 0.275$

Step-by-step explanation:

Given

$P(A\bar B) = 40\%$ --- From outlet 1 alone

$P(\bar A B) = 35\%$ --- From outlet 2 alone

$P(AB) = 10\%$ --- From both

Solving (a): Buys from outlet 1;

This is represented as: P(A) and the solution is:

$P(A) = P(A\bar B) + P(A B)$

$P(A) = 40\% + 10\%$

$P(A) = 50\%$

$P(A) = 0.50$

Solving (b): Does not buy from outlet 2;

This is represented as: P(B'):

First, calculate the probability that the customer buys from 2

$P(B) = P(\bar AB) + P(A B)$

$P(B) = 35\% + 10\%$

$P(B) = 45\%$

$P(B) = 0.45$

Using the complement rule, we have:

$P(B') = 1 - P(B)$

$P(B') = 1 - 0.45$

$P(B') = 0.55$

Solving (c): Does not buy from 1 or does not buy from 2

This is represented as: $P(A' U B')$

And the solution is:

$P(A' U B') = P(A') + P(B') - P(A'B')$

$P(A' U B') = P(A') + P(B') - P(A') * P(B')$

Using complement rule:

$P(A') = 1 - P(A)$

$P(A') = 1 - 0.50$

$P(A') = 0.50$

The equation becomes:

$P(A' U B') = 0.50 + 0.55 - 0.50 * 0.55$

$P(A' U B') = 0.775$

Solving (d): Does not buy from 1 or does not buy from 2

This is represented as:

$P(A'B')$

And it is calculated as:

$P(A'B') = P(A') * P(B)'$

$P(A'B') = 0.50 * 0.55$

$P(A'B') = 0.275$

Related Questions

The orange shape is a dilation of the black shape. What is the scale factor of the dilation?1/10 1/2 10 2
What are the zeros of the function below? Check all that apply
In figure, MN : NP = 9:1. If MP = 2. Find the distance from M to point K that is 1/4 the distance from M to N?(A) 1 (B) 1 1/3 (C) 9/20 (D) 1 8/10
For which value of k does the system has no solutions?Equation:3x + y = 4kx + y = −2Answers:A: -3B: -2C: 3D: 4
Enter the sum of numbers as a product of their GCF. 45 + 30

En una baraja de 52 cartas, donde hay 13 cartas de trébol. 13 cartas decorazones, 13 cartas de espadas y 13 cartas de rombos. Si sacamos dos
cartas con reemplazo. ¿Cuál es la probabilidad de que sean de
corazones?

Answers

Ya no clue sorry bro

An ANOVA procedure is used for data obtained from four populations. Four samples, each comprised of 30 observations, were taken from the four populations. The numerator and denominator (respectively) degrees of freedom for the critical value of F are _____.

Answers

Answer:

Step-by-step explanation:

Given that an ANOVA procedure is used for data obtained from four populations. Four samples, each comprised of 30 observations, were taken from the four populations.

Hence total observations are 30*4 =120

No of groups = 3

Hence numerator df = 3-1 =2

Now total degrees of freedom = 120-1 =119

So denominator degrees of freedom = 119-2 = 117

Thus F statistic will have numerator as 2 degrees of freedom and denominator as 117 degrees of freedom.

Choose the two rectangular prisms that have a volume of 36 cm”.= 1 cm3
A.
D.
B.
E.
C.

Answers

Answer:

B & D

Step-by-step explanation:

Volume is calculated as:

$Volume = Length * Width * Height$

For (a):

$Length = 3cm$

$Width = 4cm$

$Height = 5cm$

$Volume = 3cm * 4cm * 5cm$

$Volume = 60cm^3$

For (b):

$Length = 3cm$

$Width = 4cm$

$Height = 3cm$

$Volume = 3cm * 4cm * 3cm$

$Volume = 36cm^3$

For (c):

$Length = 4cm$

$Width = 2cm$

$Height = 2cm$

$Volume = 4cm * 2cm * 2cm$

$Volume = 16cm^3$

For (d):

$Length = 2cm$

$Width = 3cm$

$Height = 6cm$

$Volume = 2cm * 3cm * 6cm$

$Volume = 36cm^3$

There's no need to check for (e)

Option b and d answers the question

Using the volumeof a rectangularprismto examine the volumesof the prism,the two prisms with a volumeof 36cm³are Band D

Recall:

Volumeofarectanglularprism=Length×width×Height

PrismA:

Length=3cm;Height=5cm;Width=4cm

Volume = 3cm × 5cm × 4cm = 60cm³

Prism B :

Length = 3cm ; Height = 3cm ; Width = 4cm

Volume = 3cm × 3cm × 4cm = 36 cm³

Prism C :

Length = 4cm ; Height = 3cm ; Width = 2cm

Volume = 4cm × 3cm × 2cm = 24 cm³

Prism D :

Length = 2cm ; Height = 6cm ; Width = 3cm

Volume = 2cm × 6cm × 3cm = 36 cm³

Prism E :

Length = 3cm ; Height = 5cm ; Width = 4cm

Volume = 4cm × 2cm × 2cm = 16 cm³

Hence, the two rectangularprismswith a volumeof 36cm³are Band D.

Learn more : brainly.com/question/25608731

10x - 8y =4-5x + 3y = -9

Please solve with elimination i really need the help!!
please show work

Answers

Answer:

x = 6

y = 7

Step-by-step explanation:

Here, (10x - 8y = 4) and (- 5x + 3y = - 9) are two given equation

Now, Name the equation

10x - 8y = 4

take 2 as common we get

2(5x - 4y = 2)

5x - 4y = 2 ...(1)

- 5x + 3y = - 9 ...(2)

Now, Subtract (1) from (2)

5x - 4y = 2

- 5x + 3y = - 9

————————

- y = - 7

y = 7

Now,Put the value of y in equation (1) we get

5x - 4y = 2

5x - 4(7) = 2

5x - 28 = 2

5x = 28 + 2

5x = 30

x = 30÷5

x = 6

Thus,The value of xis6and yis7

FORVERIFICATIONONLY:

5x - 4y = 2

5(6) - 4(7) = 2

30 - 28 = 2

2 = 2

- 5x + 3y = - 9

- 5(6) + 3(7) = - 9

- 30 + 21 = - 9

-9=-9

Hence,L.H.S = R.H.S

-TheUnknownScientist

Celia bought a bag of 121212 goldfish for \$3$3dollar sign, 3.What is the cost of 111 goldfish?

Answers

Answer: $0.25

Step-by-step explanation:

We are given that the cost of 12 goldfish = $3

To find the cost of one goldfish we use division operator and divide the cost of 12 gold fishes by 12.

Then , the cost of one gold fish = $\$3/ 12$

⇒ Cost of 1 gold fish $=(\$3)/(12)$

⇒ Cost of 1 gold fish $=(\$1)/(4)$ [Divide numerator and denominator by 3.]

⇒ Cost of 1 gold fish $=\$0.25$ [Simplify by dividing 1 by 4]

Therefore , the cost of 1 goldfish = $0.25

Answer:

0.25

Step-by-step explanation:

Ty stacked some large wooden blocks. Each block is 1/3 ft tall. His stack of blocks measures 5 ft. How many blocks are in Ty's stack?

Answers

5 / (1/3) = 15

Ty’s stack has 15 blocks.

Other Questions

How do I write 4.18 as a mixed number

Please help. Dont put a random answer plz.

Determine whether the value is from a discrete or continuous data set. Area of a park is 9.5 acres Is the value from a discrete or continuous data set? Discrete Continuous O

Q #...10 somebody help me