How many moles are represented by 250g of platinum?

Answers

Answer 1

Answer: You take the atomic mass of Pt and that equals how many grams are in a Mole. Divide that number by 250 and that will be the amount of Moles you have

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What volume of silver metal will weigh exactly 10 kg. The density of silver is 10.5g/cm^3

Answers

Answer:

V=952.380952381 cm3cap V equals 952.380952381

What produces hydrogen ions as The only positive ions in aqueous solution

Answers

Mostly acids produces H+ ions. Acids dissociates into ions when in aqueous form resulting to hydronium or hydrogen ions and the other ion which has a negative charge. For instance, hydrochloric acid, it dissociates into H+ and Cl-.

One hundred students were surveyed about who they would vote for. What isthe best way to display the results? Explain your answer.

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Hey hope this helps ⬇️

Reaction 2 occurs when an excess of 6 M HCI(aq) solution is added to 100. mL of NaOCl(aą) of unknown concentration. If the reaction goes to completion and 0.010 mol of Cl2(g) is produced, then what was the molarity of the NaOCl(aq) solution? (A) 0.0010 M
(B) 0.010 M
(C) 0.10 M
(D) 1.0 M

Answers

The molarity of the NaOCl solution is 0.10M

The correct answer to the question is Option C. 0.10 M

We'll begin by calculating the number of mole of NaOCl required to produce 0.010 mole of Cl₂.This can be obtained as follow:

NaOCl + 2HCl —> Cl₂ + NaCl + H₂O

From the balanced equation above,

1 mole of NaOCl reacted to produce 1 mole of Cl₂.

Therefore

0.010 mole of NaOCl will also react to produce 0.010 mole of Cl₂.

Finally,we shall determine the molarity of the NaOCl solution.

Mole of NaOCl = 0.01 mole

Volume = 100 mL = 100 / 1000 = 0.1 L

Molarity of NaOCl =?

Molarity = mole / Volume

Molarity of NaOCl = 0.01 / 0.1

Molarity of NaOCl = 0.1 M

Therefore, the molarity of the NaOCl solution is 0.1 M

Learn more: brainly.com/question/12755239

Answer:

Option C 0.10 M

Explanation:

you are not providing the reaction, but luckily we have data to write the equation. We know that we are taking HCl and NaOCl to produce Cl2, the reaction is as follow:

NaOCl + 2HCl ---------> Cl₂ + NaCl + H₂O

From this reaction, we know that we have excess of acid that is added to 100 mL (0.1 L) of NaOCl, and this produces 0.010 moles of Chlorine.

All we have to do here, is apply stechiometry. We already know that the acid is in excess, so the moles produced would be the moles of the limiting reactant, in this case, the NaOCl.

According to the reaction NaOCl and Cl2 has a mole ratio of 1:1, so the moles of Cl2 would be the same moles that NaOCl lost so:

moles Cl2 = moles NaOCl = 0.010 moles

Then the concentration:

M = 0.010 / 0.1

M = 0.10 M

This is the molarity of NaOCl

What is the net ionic equation for the reaction of solid iron with aqueous copper sulfate? (Hint: First use the activity series to write the formula unit equation!)

Answers

For the answer to the question above,
The reaction of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction which exchanges only the cations of the element and the compound. In this case, the equation is

Fe (s) + CuSO4 (aq) = FeSO4 + Cu (s)

Answer:

The net ionic equation for the reaction of solid iron with aqueous copper sulfate:

$Fe(s)+Cu^(2+)(aq)\rightarrow Fe^(2+)+(aq)+Cu(s)$

Explanation:

Solid iron = Fe

Copper sulfate = $CuSO_4$

$Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)$

In an aqueous solution of copper sulfate we have copper (II) ions and sulfate ions.

$CuSO_4(aq)\rightarrow Cu^(2+)(aq)+SO_4^(2-)(aq)$

In an aqueous solution of ferrous sulfate we have ion (II) ions and sulfate ions.

$FeSO_4(aq)\rightarrow Fe^(2+)+(aq)+SO_4^(2-)(aq)$

$Fe(s)+Cu^(2+)(aq)+SO_4^(2-)(aq)\rightarrow Fe^(2+)+(aq)+SO_4^(2-)(aq)+Fe^(2+)+(aq)$

Cancelling out the common ions from both sides, we get the net ionic equation:

$Fe(s)+Cu^(2+)(aq)\rightarrow Fe^(2+)+(aq)+Cu(s)$

Carbon forms molecular compounds with some elements from Group 16. Two of these compounds are carbon dioxide, CO2, and carbon disulfide, CS2.Carbon dioxide is a colorless, odorless gas at room temperature. At standard temperature and pressure, CO2(s) changes directly to CO2(g).

Carbon disulfide is formed by a direct reaction of carbon and sulfur. At room temperature, CS2 is a colorless liquid with an offensive odor. Carbon disulfide vapors are flammable.

59 Identify one physical property and one chemical property of CS2. [1]

Answers

Answer: Physical property of $CS_2$ is state of matter (liquid) and it is a chemical compound.

Explanation:

Chemical property is defined as the property of a substance which is observed during a reaction where the chemical composition identity of the substance gets changed.

Physical property is defined as the property which can be measured and whose value describes the state of physical system. For Example: State, density etc.

Carbon disulfide $(CS_2)$ is the compound which is formed by the chemical combination of carbon and sulfur atoms. The equation for this follows:

$C+2S\rightarrow CS_2$

The chemical property of carbon disulfide is different from that of carbon and sulfur. Thus, this is a chemical compound.

It is given, that this compound is a colorless liquid, which means that the state of this compound is liquid state.

Hence, physical property of $CS_2$ is state of matter (liquid) and it is a chemical compound.

The physical property of carbon disulfide is that at room temperature, CS2 is a colorless liquid with an offensive odor. The chemical property of carbon disulfide is that it is formed by a direct reaction of carbon and sulfur.

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