Can someone pls help indicate the number of significant figures with these numbers: 34g, 564 l, 19.3 mm, 23.45 mg, 101 km, and 3400 g

Answers

Answer 1

Answer:

The concept of significant figures are mainly used by scientist and engineer to know the significance of digits in a measurement. Therefore, significant figures gives an idea about the digits that are necessary to indicate the experimental value.

What is significant figures?

Significant figures are the figures that indicate the degree of accuracy of a value. It tells about the precision of a value.

Rules for counting significant figures are:

Number between 1 to 9 is always significant

Zeroes after a number has got no significance

Zeroes before a number has got no significance

Zeroes between number has got significance

34g 2significant figures

564l 3significant figures

19.3mm 3significant figures

23.45 mg 3significant figures

101 km 3significant figures

3400 g 2 significant figures

Therefore, significant figures gives an idea about the digits that are necessary to indicate the experimental value.

To learn more about Significant figures, here:

brainly.com/question/12656148?

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Answer 2

Answer: The significant figures is two because that is the least amount of spaces before the decimal out of those numbers

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Which process results in the release of energy stored in the products of photosynthesis?A. polymer synthesis

B. depolymerization

C. digestion

D. cellular respiration

Answers

Answer: Cellular Respiration

Explanation:

The cellular respiration can be defined as the biological process by which the organism get energy to do work or to perform the various metabolic processes of the body.

The glucose produced by the plants is utilized in the process of cellular respiration where the glucose is broken down in pressence of oxygen to provide energy for various body functions.

The correct answer would be the letter D, Cellular respiration.

Cellular respiration allows the production of ATP through the breakdown of glucose assisted by oxygen. We talk about aerobic metabolism. This metabolism is to oppose the fermentation which is done without oxygen (anaerobic) and that we detail in another file. Cellular respiration is divided into two phases, one cytoplasmic and the other mitochondrial.

If 10.3 g of Mg3N2 is treated with water, what volume of gas would be collected at STP

Answers

Use the ideal gas law: PV=nRtTo find volume, move to V=(nRt)/PN=# of moles (to find, 10.3 g/100.929g)=.102 molesR=ideal gas constant(this value is 0.082056(Liters*atmospheres)/(Kelvin*mol)T= temp which at stp is 273 KelvinP= 1 atmosphereV=((.102 moles)(0.082056 Latm/Kmol)(273 K))/1 atm

Mg3N2 +6H2O → 3Mg(OH)2 +2 NH3
relative weight of Mg3N2 = (3x24)+(2x14) = 100 g/mole
mole of Mg3N2 = 10,3 g/100 g/mole = 0,103 mole
mole of NH3(g) = 2/1 x 0,103 mole = 0,206 mole
volume NH3(g) which collected at STP = mole NH3(g) x 22,4 litre/mole = 0,206 mole x 22,4 litre/mole = 4,6144 litre.

There are moles of carbon in 6.64 moles of CCl2F2

Answers

Answer:

6.64 moles of carbon.

Explanation:

Given data:

Number of moles of C = ?

Number of moles of CCl₂F₂ = 6.64 mol

Solution:

In one mole ofCCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.

In 6.6 moles of CCl₂F₂ :

Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.

Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine

Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine

Answer: 6.64 moles

Explanation:

Number of moles of C = ?

number of moles of CCl₂F₂ = 6.64 mol

In one mole of CCl₂F₂ there is one mole of carbon two moles of chlorine and two moles of fluorine are present.

In 6.6 moles of CCl₂F₂ :

Moles of carbon = 6.64 × 1 = 6.64 moles of carbon.

Moles of chlorine = 6.64× 2 = 13.28 moles of chlorine

Moles of fluorine = 6.64× 2 = 13.28 moles of fluorine

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