PHYSICS HIGH SCHOOL

A fixed mass of gas has a volume of gas of 25cm3. the pressure of the gas is 100kPA. the volume of the gas is slowly decreased by 15cm3 at a constant temperature. what is the change in the pressure of the gas?a) 67kPA
b) 150kPA
c) 170kPA
d) 250kPA
give reasons

Answers

Answer 1
Answer:

A fixed mass of gas has a volume of 25 cm^3, the pressure of the gas is 100 kPa, the volume of the gas is slowly decreased by 15 cm^3 at a constant temperature, and the change in pressure of the gas is 150 kPa, which is option b.

What is the calculation of the change in pressure?

PV = nRT (P= pressure of the gas, V =volume, n = number of moles of gas, R = gas constant, and T =temperature of the gas in kelvin)

Suppose the gas is an ideal gas and that the temperature is constant,

P1V1 = P2V2

Here P1 = 100 kPa, V1 = 25 cm^3, V2 = 10 cm^3,

100 kPa x 25 cm^3 = P2 x 10 cm^3

P2 = (100 kPa x 25 cm^3) / 10 cm^3

P2 = 250 kPa

the change in pressure of the gas is,

ΔP = P2 - P1 = 250 kPa - 100 kPa = 150 kPa

The reason is that when the volume of a fixed mass of gas is decreased, the pressure of the gas increases proportionally, so here assuming that the temperature is constant it is calculated.

Hence, the volume of the gas is slowly decreased by 15 cm^3 at a constant temperature, and the change in pressure of the gas is 150 kPa, which is option b.

Learn more about the calculation of the change in pressure here.

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Answers

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90° should have been provided in the problem. I encountered similar problem before. 

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https://lco.global/spacebook/planets-and-how-they-formed/



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