Which of the following chemical equations violates the law of conservation of mass? (1 point) Li2SO4 + 2Ca(NO3)2 yields 2LiNO3 + 2CaSO4 Ti + 2Cl2 yields TiCl4 2C2H2 + 5O2 yields 4CO2 + 2H2O MgSO4 + 2NaOH yields Mg(OH)2 + Na2SO4

Answers

Answer 1

Answer: i hope it hepls.......

Answer 2

Answer:

Answer: Li2SO4 + 2Ca(NO3)2 —> 2LiNO3 + 2CaSO4

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What is the correct equilibrium constant expression for the following reaction? 3A2 = 2B3 when the reaction started with the initial concentrations of A2 = 3 M and B3 = 2 M and continued until the equilibrium concentrations of A2 = 2.5 M and B3 = 2.5 M

Answers

Answer:

Kc = [B₃]²/[A₂]³ = 0.40

Explanation:

3A₂ ⇄ 2B₃

Given at equilibrium => [A₂] =2.5 and [B₃] = 2.5

Kc = [B₃]²/[A₂]³ = (2.5)²/(2.5)³ = (2.5)⁻¹ = 0.40

Describe how you would make 250 ml of a 3 M solution of sodium acetate (NaOAc = 82.03 g/mol). First figure out how much sodium acetate you would need, then describe how you would make the solution if you were given a bottle of solid sodium acetate, a volumetric flask, and DI water.

Answers

Answer:

You need to do the following conversion to pass from 3M in 250 mL to g of sodium acetate

$3 M (mol/L)*(1L/1000 mL)*(250 mL)*(82.03 g/1 mol)=61.52 g$

Explanation:

First, you need to dissolve 61.52 g of solid sodium acetate (MW 82.03 g/mol) in 200 ml of DI water. Then, using a volumetric flask add water to bring the total volume of the solution to 250 mL.

Group 17 elements form A. +1 ion B. -1 ion C. +7 ion D. -7 ion

Answers

Answer:

Explanation:

Use your periodic table to find out the charge on a Fl ion if your periodic table is constructed that way. In any event, the charge on Fl when it becomes an ion is -1. I don't think it has any other charge. So all of the elements in column 17 will have at least -1 in common.

Final answer:

Group 17 elements, also known as halogens, have seven valence electrons and tend to gain one electron to become stable, forming a -1 ion.

Explanation:

The elements in Group 17 on the periodic table are also known as halogens. These elements, which include fluorine, chlorine, bromine, iodine, and astatine, have seven valence electrons. Hence, they tend to gain one electron to achieve a stable electron configuration, forming a -1 ion. Therefore, the correct answer to your question is B. -1 ion.

Learn more about Group 17 elements here:

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The figure below represents a reaction.What type of reaction is shown?SO3+ H2SO4 →→ HSO4
synthesis
decomposition
single displacement
double displacement

Answers

SO₃+ H₂SO₄ → H₂SO₄ This reaction is synthesis type of reaction, because that would be combination (synthesis) A + B → AB. Therefore, option A is correct.

What are the types of reaction ?

There are five basic types of chemical reactions are combination, decomposition, single-replacement, double-replacement, and combustion.

Biochemical reactions are chemical reactions that occur within living things. Metabolism refers to the sum of all biochemical reactions in an organism. Exothermic and endothermic chemical reactions are both part of metabolism.

Hydration is the process of combining water molecules with another substance to form a single, new compound. SO3 is an acidic oxide that reacts with and dissolves in water to form sulfuric acid, H2SO4.

Thus, option A is correct.

To learn more about the chemical reaction, follow the link;

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Are you sure it isn’t SO3+H2O = H2SO4 because that would be combination (synthesis) A+ B=AB

Or SO3 + H2SO4 = H2S2O7
Because that would also be synthesis

The balanced combustion reaction for C 6 H 6 C6H6 is 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ 12 CO 2 ( g ) + 6 H 2 O ( l ) + 6542 kJ 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 7.300 g C 6 H 6 7.300 g C6H6 is burned and the heat produced from the burning is added to 5691 g 5691 g of water at 21 ∘ 21 ∘ C, what is the final temperature of the water?

Answers

Answer: The final temperature of the water is $33.85^(o)C$ .

Explanation:

We know that molar mass of $C_(6)H_(6)$ is 78 g/mol. And, the amount of heat produced when 2 mol of $C_(2)H_(6)$ burns is 6542 KJ.

This means that,

$78 * 2$ = 156 g of $C_(2)H_(6)$ burns, heat produced is 6542 kJ.

Therefore, heat produced (Q) by burning 7.3 g of $C_(6)H_(6)$ is as follows.

$(6542 * 7.3 g)/(156 g)$

= 306.13 kJ

or, = 306130 J (as 1 KJ = 1000 J)

For water, mass is given as 5691 g and specific heat capacity of water is 4.186 $J/g^(o)C$ .

So, we will calculate the value of final temperature as follows.

Q = $m * C * (T_(f) - T_(i))$

306130 J = $5691 g * 4.186 J/g^(o)C * (T_(f) - 21)^(o)C$

$(T_(f) - 21)^(o)C = (306130 J)/(23822.53 J/^(o)C)$

$T_(f)$ = 12.85 + 21

= $33.85^(o)C$

Thus, we can conclude that the final temperature of the water is $33.85^(o)C$ .

Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C. How are these numbers affected by the addition of 0.1 mol/dm3 of KCL? At what distance from the particle surface (r) has the potential decayed to 1% of its initial value?