CHEMISTRY HIGH SCHOOL

How to know if two elements will form a covalent bond

Answers

Answer 1

Answer:

Answer:

If they are both non-metals

Explanation:

covalent = non-metal + non-metal

ionic = metal +non-metal

metallic = metal +metal

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Balance the following oxidation-reduction reaction: Fe(s)+Na+(aq)→Fe2+(aq)+Na(s) Express the coefficients as integers separated by commas (e.g., 4,1,3,2, where 1 indicates the absence of a coefficient).

Answers

Answer:

The answer to your question is: 1, 2, 1, 2

Explanation:

1 Fe(s) + 2 Na⁺(aq) → 1 Fe²⁺(aq) + 2 Na(s)

Fe⁰ - 2e⁻ ⇒ Fe⁺² Oxidases

Na⁺ + 1 e⁻ ⇒ Na⁰ Reduces

1 x ( 1 Fe⁰ ⇒ 1 Fe⁺²) Interchange number of

2 x ( 2Na⁺ ⇒ 2 Na⁰ ) electrons

Final answer:

To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), follow these steps: balance atoms other than hydrogen and oxygen, balance hydrogen atoms, balance oxygen atoms, verify charges

Explanation:

To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), we need to balance the number of atoms for each element and the total charge on both sides of the reaction. Here's the step-by-step process:

First, balance the atoms other than hydrogen and oxygen. There is only one atom of Fe on each side, so this is already balanced.
Next, balance the hydrogen atoms. We have no hydrogen on the left side and one hydrogen on the right side, so we need to add a coefficient of 2 in front of Na(s): 2Na(s).
Now, balance the oxygen atoms. We have no oxygen on the left side and one oxygen in Fe2+(aq), so we need to add a coefficient of 2 in front of Fe2+(aq): 2Fe2+(aq).
Finally, verify that the charges are balanced. The charge on the left side is 1+ (from Na+) and the charge on the right side is 0 (from Na). To balance the charges, we need to add a coefficient of 2 in front of Na+: 2Na+(aq).

So, the balanced oxidation-reduction reaction is: Fe(s) + 2Na+(aq) → 2Fe2+(aq) + Na(s).

Learn more about Balancing oxidation-reduction reactions here:

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How many electrons are in Al3+?

Answers

atomic number of aluminium = 13
so the number of electrons=13
aluminium cation, has 3 positive charge which it attains after losing 3 electrons (protons are not lost, there remain in the nucleus of the atom
electrons in Al3+ = 13 - 3 = 10

A solution of methanol and water has a mole fraction of water of 0.312 and a total vapor pressure of 211 torr at 39.9 ∘C. The vapor pressures of pure methan ol and pure water at this temperature are 256 torr and 55.3 torr, respectively. ls the solution ideal? If not, what can you say about the relative strengths of the solute-solvent interactions compared to the solute-solute and solvent-solvent interactions?

Answers

Answer:

Weaker

Explanation:

The strategy here is to use Raoult´s law to calculate the theoretical vapor pressure for the concentrations given and compare it with the experimental value of 211 torr.

Raoult´s law tell us that for a binary solution

P total = partial pressure A + partial pressure B = Xa PºA + Xb PºB

where Xa and Xb are the mol fractions, and PºA and PºB are the vapor pressures of pure A and pure B, respectively

For the solution in question we have

Ptotal = 0.312 x 55.3 torr + ( 1- 0.312 ) x 256 torr ( XA + XB = 1 )

Ptotal = 193 torr

Since experimentally, the total vapor pressure is 211 and our theoretical value is smaller ( 193 torr ), we can conclude the interactions solute-solvent are weaker compared to the solute-solute and solvent-solvent interactions.

Which is the best tool to find the volume of the base that she needs to neutralize the acid

Answers

The best tool to find the volume of the base taht she needs to neutralize the acid is M1V1 = M2V2. an example is given below.

Given:

12.0 M HCl

2.0 liters of a 3.0 M HCl

Required:

volume of concentrated hydrochloric acid

Solution:

M1V1 = M2V2

(12.0 M HCl)V1 = (3.0 M HCl)( 2.0 liters)

V1 = (3.0 M HCl)( 2.0 liters)/ (12.0 M HCl)

V1 = 0.5 liters

What is the order, from simplest to most complex, for the classification of matter

Answers

B) element, molecule, compound, mixture is the answer just took the test ;) good luck : P

What volume of carbon dioxide is produced when 0.489 mol of calcium carbonate reacts completely according to the following reaction at 0°C and 1 atm? calcium carbonate ( s ) calcium oxide ( s ) + carbon dioxide ( g )