The radius of an atom of gold (Au) is about 1.35 Å.How many gold atoms would have to be lined up to span 5.5 mm ?

Answers

Answer 1

Answer:

The number of gold atoms that would be needed to span this distance is 20,370.4 atoms.

How many gold atoms would have to be lined up?

To calculate how many gold atoms would need to be lined up to span a given distance, we will us the following method.

The number of gold atoms that would be needed to span this distance:

Distance = Diameter of a gold atom

Distance = 2 x Radius

Distance = 2 x 1.35 Å

Number of gold atoms = Total distance / Distance spanned by a single atom

Number of gold atoms = (5.5 x 10⁻⁴ cm) / (2 x 1.35 Å)

1 Å = 10⁻⁸ cm.

Number of gold atoms = (5.5 x 10⁻⁴ cm) / (2 x 1.35 x 10⁻⁸ cm)

Number of gold atoms = 20,370.4 atoms

Learn more about number of atoms here: brainly.com/question/6258301

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Answer 2

Answer: depends how many sig figs you are rounding to so I won't round to tenth or hundredth but the answer is 2.037 * 10^7

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If 4.0 mol aluminum and 7.0 mol hydrogen bromide react according to the following equation, how many moles of hydrogen are formed and what is the limiting reactant?

Answers

Answer:

Moles of hydrogen formed = 3.5 moles

Explanation:

Given that:-

Moles of aluminium= 4.0 mol

Moles of hydrogen bromide = 7.0 mol

According to the reaction:-

$2Al_((s))+6HBr_((aq))\rightarrow 2AlBr_3_((aq))+3H_2_((g))$

2 moles of aluminum react with 6 moles of hydrogen bromide

1 mole of aluminum react with 6/2 moles of hydrogen bromide

4 moles of aluminum react with (6/2)*4 moles of hydrogen bromide

Moles of hydrogen bromide = 12 moles

Available moles of hydrogen bromide = 7.0 moles

Limiting reagent is the one which is present in small amount. Thus, hydrogen bromide is limiting reagent. (7.0 < 12)

The formation of the product is governed by the limiting reagent. So,

6 moles of hydrogen bromide on reaction forms 3 moles of hydrogen

1 moles of hydrogen bromide on reaction forms 3/6 moles of hydrogen

7 moles of hydrogen bromide on reaction forms (3/6)*7 moles of hydrogen

Moles of hydrogen formed = 3.5 moles

Answer:

3.5 mol H2, HBr (limiting reactant)

Explanation:

4.0 mol Al × 3 mol H2/ 2 mol Al = 6.0 mol H2

7.0 mol HB ×3 mol H2/ 6mol HBr = 3.5 mol H2

Since 7.0mol of HBr will produce less H2 than 4.0mol of Al, HBr will be the limiting reactant, and the reaction will produce 3.5mol of H2.

What will the pressure of the gas be if the temperature rises to 87°C?A. 60 kPa
B. 161 kPa
C. 16 kPa
D. 41 kPa

Answers

Answer:

A. 60 kPa

Explanation:

P2 = p1 times t2 / t1

Which hybridization scheme occurs about phosphorus when nitrogen forms a triple bond?

Answers

Jun 21, 2015 · 3 posts · 1 author

Most of the time when nitrogen forms a double bond it will be sp2 hybridised. permalink; embed; save.

(b) Liquid hexane burns in oxygen gas to form carbon dioxide gas and water vapor.
True/False

Answers

Answer:

True

Explanation:

Liquid hexane burns in oxygen gas to form carbon dioxide gas and water vapor.TRUE.

This is the complete combustion reaction of hexane, which proceeds according to the following equation.

C₆H₁₄(l) + 9.5 O₂(g) → 6 CO₂(g) + 7 H₂O(g)

If the combustion were incomplete, instead of carbon dioxide, the product would be carbon monoxide or carbon.

An X-ray photon with a wavelength of 0.954 nm strikes a surface. The emitted electron has a kinetic energy of 959 eV.Part A:

What is the binding energy of the electron in kJ/mol? [Note that KE = = mv2 and 1 electron volt (eV) = 1.602 x 10-19 J.]

Answers

Answer:

An X-ray photon of wave length 0.989 nm strikes a surface. The emitted electron has a kinetic energy of 969 eV. What is the binding energy of the electron in kJ/mol? [KE=

mv2;1 electron volt (eV)=1.602×10−19J][KE=

;1 electron volt (eV)=1.602

Final answer:

The photoelectric effect equation is used to find the binding energy of an electron when an X-ray photon with a specific wavelength strikes a surface, taking into account the kinetic energy of the ejected electron and the energy of the photon.

Explanation:

To calculate the binding energy of an electron when an X-ray photon with a given wavelength strikes a surface, you use the photoelectric effect equation which connects the energy of the photon (E = hc/λ) with the kinetic energy (KE) of the ejected electron and the binding energy (BE) that keeps the electron attached to the atom.

The equation is: KE + BE = hc/λ, where h is Planck's constant (6.626 x 10-34 J s), c is the speed of light (3.00 x 108 m/s), and λ is the wavelength of the photon.

The given kinetic energy of the electron is 959 eV, which can be converted to joules (1 eV = 1.602 x 10-19 J). The energy of the photon can be calculated using the wavelength. Binding energy is then found by subtracting the electron's kinetic energy from the energy of the photon.

To find the binding energy per mole, you can use Avogadro's number (6.022 x 1023 mol-1) to calculate the total binding energy in a mole of such electrons and then convert it to kilojoules.