Line AB has a length of 5 cm. The line segment is dilated to produce line A'B', which has a length of 2 cm. Find the scale factor of the dilation. A. k = 2/5
B. k = 1/2
C. k = 5/2
D. k = 2
Thank you in advance for your help!
Answers
Answer:
Option A is correct
k = 2/5
Step-by-step explanation:
The rule of dilation with scale factor k is given by:
As per the statement:
Line AB has a length of 5 cm. The line segment is dilated to produce line A'B', which has a length of 2 cm.
⇒original Length (AB)= 5 cm
and
Image length (A'B') = 2 cm
Apply the rule of dilation we have;
Substitute the given values;
Therefore, the scale factor of the dilation is, 2/5
Related Questions
A roofing company sells roofing material for $12 per aquare yards. How many square yards of roofing material can be purchased for$900.
I need all these answered please-1) 6i-i 2) (12+3i)-(2+6i) 3) 5i(1+2i) 4) 8+4i divided by 4
How many faces does a right rectangular prism have if it has 8 vertices and 12 edges
(2x raised to fourth power) raised to the negative fourth power
Answers
Answer:
Option 1
Step-by-step explanation:
58.0kg +0.2kg = 58.2kg
Answers
100-26=84
26%+84%=100%
Answers
hope that helped :)
Answers
Answer:
x=1
Step-by-step explanation:
9+4x=15-2x
9+6x=15 Add two to both sides
6x=6 divide by 6
x=1
Answer:
-12
Step-by-step explanation:
I set it up as an equation based on the word problem you gave me
So
2n - 15 = 4n + 9
Combine like terms
-2n = 24
Isolate the variable n
-2n/-2 = 24/-2
n = -12
To check your work replace the n with -12
2(-12) - 15 = 4(-12) + 9
-24 - 15 = -48 + 9
-39 = -39
A.
35.25 × 100
B.
35.25 ÷ 1,000
C.
35.25 ÷ 100
D.
35.25 × 1,000
Answers
Answer:
i think its B hope i helped
Answers
Final answer:
The least common multiples for the given sets of numbers are found. Then, these least common multiples are matched with their corresponding numbers in another column. The correct matchings are:
i. 504 -> b. 9, 8, 7
ii. 288 -> f. 32, 24, 18
iii. 84 -> e. 14, 12
iv. 44 -> a. 22 and 4
v. 200 -> d. 25, 8
vi. 108 -> c. 27, 12, 36
Explanation:
This question is asking for the least common multiple (LCM) of different sets of numbers. The LCM is the smallest number that is a multiple of each of the numbers in a set. We will find the LCM for each set in Column II and match it to the corresponding number in Column I.
a. For 22 and 4, the LCM is 44.
b. For 9, 8, and 7, the LCM is 504.
c. For 27, 12, and 36, the LCM is 108.
d. For 25 and 8, the LCM is 200.
e. For 14 and 12, the LCM is 84.
f. For 32, 24, and 18, the LCM is 288.
So, the correct matchings are:
i. 504 -> b. 9, 8, 7
ii. 288 -> f. 32, 24, 18
iii. 84 -> e. 14, 12
iv. 44 -> a. 22 and 4
v. 200 -> d. 25, 8
vi. 108 -> c. 27, 12, 36
Learn more about Least Common Multiple here:
#SPJ2
The complete question is given below:
Match each set of numbers with their least common multiple.
In column I, the numbers are:
i. 504
ii. 288
iii. 84
iv. 44
v. 200
vi. 108
In column II, the numbers are:
a. 22 and 4=
b. 9, 8, 7=
c. 27, 12,,36=
d. 25 , 8=
e. 14 ,12=
f. 32, 24 18=
27, 12, and 36 = 108
22 and 4 = 44
14 and 12 = 84
25 and 8 =200
9, 8, and 7 = 504
32, 24, and 18 = 288