Rewrite the expression without using a negative exponent.12x^−4
Simplify your answer as much as possible.

Answers

Answer 1
Answer: 12x^-4 =
12 * x^-4 =
12 * 1/(x^4) = 
12 / (x^4)
Answer 2
Answer: 12x^-4
To make the exponent positive you have to bring the term x^-4 down so your answer would be= 12/x^4

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Carl is balancing his checking account. After comparing the bank statement to his register, he notices an outstanding debit of $58.00.Which shows the correct amount in Carl’s checking account?$51.75$109.75$167.75$221.87
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An advertisement claims that Fasto Stomach Calm will provide relief from indigestion in less than 10 minutes. For a test of the claim, 35 randomly selected individuals were given the product; the average time until relief was 9.25 minutes. From past studies, the standard deviation of the population is known to be 2 minutes. Can you conclude that the claim is justified? Find the P-value and let a = 0.05.

A small regional carrier accepted 19 reservations for a particular flight with 17 seats. 14 reservations went to regular customers who will arrive for the flight. Each of the remaining passengers will arrive for the flight with a 52% chance, independently of each other. (Report answers accurate to 4 decimal places.)1. Find the probability that overbooking occurs.
2. Find the probability that the flight has empty seats.

Answers

Answer:

(a) The probability of overbooking is 0.2135.

(b) The probability that the flight has empty seats is 0.4625.

Step-by-step explanation:

Let the random variable X represent the number of passengers showing up for the flight.

It is provided that a small regional carrier accepted 19 reservations for a particular flight with 17 seats.

Of the 17 seats, 14 reservations went to regular customers who will arrive for the flight.

Number of reservations = 19

Regular customers = 14

Seats available = 17 - 14 = 3

Remaining reservations, n = 19 - 14 = 5

P (A remaining passenger will arrive), p = 0.52

The random variable X thus follows a Binomial distribution with parameters n = 5 and p = 0.52.

(1)

Compute the probability of overbooking  as follows:

P (Overbooking occurs) = P(More than 3 shows up for the flight)

                                        =P(X>3)\n\n={5\choose 4}(0.52)^(4)(1-0.52)^(5-4)+{5\choose 5}(0.52)^(5)(1-0.52)^(5-5)\n\n=0.175478784+0.0380204032\n\n=0.2134991872\n\n\approx 0.2135

Thus, the probability of overbooking is 0.2135.

(2)

Compute the probability that the flight has empty seats as follows:

P (The flight has empty seats) = P (Less than 3 shows up for the flight)

=P(X<3)\n\n1-P(X\geq 3)\n\n=1-[{5\choose 3}(0.52)^(3)(1-0.52)^(5-3)+{5\choose 4}(0.52)^(4)(1-0.52)^(5-4)+{5\choose 5}(0.52)^(5)(1-0.52)^(5-5)]\n\n=1-[0.323960832+0.175478784+0.0380204032]\n\n=0.4625399808\n\n\approx 0.4625

Thus, the probability that the flight has empty seats is 0.4625.

If m∠1 = 3x, m∠3 = 2x + 20 and m∠5 = 30, what is the value of x?

Answers

m∠2 = 180 - m∠1 = 180 - 3x   [supplementary angles]

In a triangle, the three interior angles always add to 180° ⇒
m∠2 + m∠3 + m∠5 = 180
180-3x + 2x+20 + 30 = 180
230 - x = 180
x = 230 - 180
x = 50

lola just received a promotion at work now earns $18 per hour. she writes the equation y=18x to represent her total earnings ,y, when she works x hour

Answers

Answer:

its A just took tha test

Step-by-step explanation:

Final answer:

The question is about representing Lola's total earnings when she works a certain number of hours. It can be answered using the equation y=18x, where y represents her total earnings and x represents the number of hours she works.

Explanation:

The question is about representing Lola's total earnings when she works a certain number of hours. She wrote the equation y=18x, where y represents her total earnings and x represents the number of hours she works.

This equation is similar to the example given about Svetlana's tutoring earnings, which is represented by the equation y=25+15x, where y is the total amount of money Svetlana earns and x is the number of hours she tutors.

Therefore, the subject of this question is Mathematics and it is appropriate for High School level.

Learn more about Representing total earnings with an equation here:

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1. In order to get more female customers, a new clothing store offers free gourmet coffee and pastry to its customers. The average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260. Use this sample information to construct a 95% confidence interval for the average daily revenue. The store manager believes that the coffee and pastry strategy would lead to an average daily revenue of $1,200. Is the manager correct based on the 95% confidence interval?

Answers

Answer:

No, the manager is not correct based on the 95% confidence interval.

Step-by-step explanation:

We are given that the average daily revenue over the past five-week period has been $1,080 with a standard deviation of $260, i.e.; X bar = $1080 and s = $260 and sample size, n = 35 .

The Pivotal quantity for 95% confidence interval is given by;

                (Xbar - \mu)/((s)/(√(n) ) ) ~ t_n_-_1

where, X bar = sample mean = $1080

                s  = sample standard deviation = $260

                 n = sample size = 35 {five-week}

So, 95% confidence interval for average daily revenue, \mu is given by;

P(-2.032 < t_3_4 < 2.032) = 0.95

P(-2.032 < (Xbar - \mu)/((s)/(√(n) ) ) < 2.032) = 0.95

P(-2.032 * {(s)/(√(n) ) < {Xbar - \mu} < 2.032 * {(s)/(√(n) ) ) = 0.95

P(X bar - 2.032 * {(s)/(√(n) ) < \mu < X bar + 2.032 * {(s)/(√(n) ) ) = 0.95

95% confidence interval for \mu = [ X bar - 2.032 * {(s)/(√(n) ) , X bar + 2.032 * {(s)/(√(n) ) ]

                                            = [ 1080 - 2.032 * {(260)/(√(35) ) , 1080 + 2.032 * {(260)/(√(35) ) ]

                                             = [ 990.70 , 1169.30 ]

No, the manager is not correct based on the fact that the coffee and pastry strategy would lead to an average daily revenue of $1,200 because the calculate 95% confidence interval does not include value of $1200.

Therefore, the store manager believe is not correct.

Final answer:

The 95% confidence interval for the store's average daily revenue is calculated to be approximately ($993.97, $1166.03). Since $1200 is outside this interval, the manager's belief that the coffee and pastry strategy will lead to an average daily revenue of $1200 is not backed by this confidence level.

Explanation:

In the field of statistics, a confidence interval (CI) is a type of interval estimate that is used to indicate the reliability of an estimate. The method for calculating a 95% confidence interval for the average daily revenue involves the sample mean, the standard deviation, and the z-score associated with a 95% confidence level, which is approximately 1.96. Let's use the provided data to calculate:

  • Calculate the standard error by dividing the standard deviation by the square root of the sample size. Here, the standard deviation is $260, and the sample size is 5 weeks * 7 days/week = 35 days. So, the standard error is $260 / sqrt(35) = $43.89.
  • Multiply the standard error by the z-score to get the margin of error. So, $43.89 * 1.96 = $86.03.
  • Calculate the lower and upper bounds of the 95% confidence interval by subtracting and adding the margin of error from/to the sample mean. So, ($1080 - $86.03, $1080 + $86.03) = ($993.97, $1166.03).

The range of this 95% confidence interval is from $993.97 to $1166.03. This means we are 95% confident that the true average daily revenue lies within this interval. Since $1200 lies outside this interval, the manager's belief is not supported by this confidence interval.

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I need some help real quick

Answers

V = 3.14 x (4)^2 x 13 = 653.12

a.Find a linear approximation of 4√14 . b. Justify visually whether your approximation is an over- or underestimate.

Answers

Answer:

15

Step-by-step explanation:

Let f(x) be the function

\bf f(x)=√(x)

A linear approximation of f is the Taylor polynomial of degree one:

\bf f(x)\approx f(a)+f'(a)(x-a)

Taking a = 16, and given that

\bf f'(x)=\displaystyle(1)/(2√(x))

we get

\bf f(x)\approx f(16)+f'(16)(x-16)=√(16)+\displaystyle(1)/(2√(16))(x-16)=4+\displaystyle(x-16)/(8)

so

\bf √(14)=f(14)\approx 4+\displaystyle(14-16)/(8)=3.75\Rightarrow\n\n\Rightarrow 4√(14)\approx 4(3.75)=15

Since 16 > 14, we can deduce that this is an overestimate.