Answers
Answer:
The freezing point of a solution is lowered compared to the freezing point of the pure solvent. The amount of depression of the freezing point is proportional to the molality of the solute. The greater the molality of a solution, the lower its freezing point. To compare the freezing points of these solutions, we need to determine which one has the highest molality.
First, we need to determine the number of particles that each solute will produce in solution, as this affects the amount of depression of the freezing point.
KNO3 dissociates into two ions: K+ and NO3-, so it will produce two particles per formula unit.
BaCl2 dissociates into three ions: Ba2+ and two Cl-, so it will produce three particles per formula unit.
Ethylene glycol does not dissociate in solution, so it will produce one particle per molecule.
Na3PO4 dissociates into four ions: three Na+ and one PO43-, so it will produce four particles per formula unit.
Now, we can calculate the molality (moles of solute per kilogram of solvent) for each solution:
For 0.10 m KNO3: molality = 0.10 mol / 1 kg = 0.10 m
For 0.10 m BaCl2: molality = 0.10 mol x 3 particles / 1 kg = 0.30 m
For 0.10 m ethylene glycol: molality = 0.10 mol / 1 kg = 0.10 m
For 0.10 m Na3PO4: molality = 0.10 mol x 4 particles / 1 kg = 0.40 m
So, the solutions in order of decreasing freezing points are:
0.10 m Na3PO4 (highest molality)
0.10 m BaCl2
0.10 m KNO3 and 0.10 m ethylene glycol (same molality, but KNO3 has a smaller van't Hoff factor than ethylene glycol, so it will have a slightly higher freezing point)
Explanation:
Related Questions
An aerosol is a colloidal _____ suspended in a _____. A.liquid B.solid C.gas
Choose all the answers that apply.Ionic compounds _____.-do not dissolve in water-have high melting points-have low melting points-dissolve easily in water-conduct electricity when melted
Consider an element Z that has two naturally occurring isotopes with the following percent abundances: the isotope with a mass number of 19.0 is 55.0% abundant; the isotope with a mass number of 21.0 is 45.0% abundant. What is the average atomic mass for element Z?Average atomic mass of Z = [mass]
Be sure to answer all parts. Styrene is produced by catalytic dehydrogenation of ethylbenzene at high temperature in the presence of superheated steam. (a) Given these data, find ΔH o rxn , ΔG o rxn , and ΔS o rxn at 298 K: ΔH o f (kJ/mol) ΔG o f (kJ/mol) S o (J/mol·K) Ethylbenzene, C6H5−CH2CH3 −12.5 119.7 255 Styrene, C6H5−CH=CH2 103.8 202.5 238 ΔH o rxn ΔG o rxn ΔS o rxn kJ kJ J/K (b) At what temperature is the reaction spontaneous? °C (c) What are ΔG o rxn and K at 600.°C? ΔG o rxn K kJ/mol × 10 Enter your answer in scientific notation.
Answers
Speed of the car =
Given time = 37.0 s
Converting time from seconds to hours:
1 hr= 60 min; 1 min = 60 s
Calculating distance from speed and time:
Converting distance from km to m:
So the distance traveled by the car in 37.0 s is 894 m.
b. Isotope 48Ti Abundance 10.000% Mass(amu) 47.94795
c. Isotope 50Ti Abundance 19.100% Mass(amu) 49.94479
d. What is the average atomic mass of titanium on that planet?
e. I got 46.9 amu but it is wrong.
Answers
Answer:
Average atomic mass = 46.91466 amu
Explanation:
Step 1: Data given
Isotopes of titanium
46Ti = 70.900% ⇒ 45.95263 amu
48Ti = 10.000 % ⇒ 47.94795 amu
50Ti = 19.100 % ⇒ 49.94479 amu
Step 2: Calculate the average atomic mass of titanium
Average atomic mass = 0.7090 * 45.95263 + 0.10 * 47.94795 + 0.1910 * 49.94479
Average atomic mass = 46.91466 amu
Answers
Answer:
The climate was wet and cold
Explanation:
Answer:
The large tree rings allow you to conclude that the climate was either very warm or wet during those growing seasons, because greater than normal growth occurred.
Explanation: It is the edge sample response
B. 0.288 g
C. 0.392 g
D. 0.450 g
E. 0.341 g
Answers
Answer: The correct option is E.
Explanation: The reaction between aspirin (also known as acetylsalicylic acid) and sodium hydroxide is known as acid-base titration reaction.
By applying Unitary method, we get:
15.50mL of NaOH dissolves = 0.325 g of aspirin
So, 16.25 mL of NaOH will dissolve = = 0.341 g
Hence, the correct option is E.
A reaction mixture initially contains a Br2 partial pressure of 751 torr and a Cl2 partial pressure of 737 torr at 150 K.
Calculate the equilibrium partial pressure of BrCl.
Answers
Answer:
the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Explanation:
Since
Br₂(g) + Cl₂(g) ⇌ 2BrCl(g) , Kp=1.112 at 150 K
denoting BC as BrCl , B as Br₂ , C as Cl₂, p as partial pressure , then
Kp = pBC²/[pB*pC]
solving for pBC
pBC = √(Kp*pB*pC)
replacing values
pBC = √(Kp*pB*pC) = √(1.112*751 torr*737 torr) = 784.52 torr
pBC = 784.52 torr
then the equilibrium partial pressure of BrCl is pBC = 784.52 torr
Final answer:
To calculate the equilibrium partial pressure of BrCl, use the equilibrium constant expression and substitute the given partial pressures of Br2 and Cl2. The equilibrium partial pressure of BrCl is approximately 0.0375 atm.
Explanation:
To calculate the equilibrium partial pressure of BrCl, we need to use the equilibrium constant expression:
Kp = ([BrCl]^2) / ([Br2] * [Cl2])
Given that the equilibrium partial pressures of Br2 and Cl2 are 0.450 atm and 0.115 atm, respectively, we can substitute these values into the expression:
1.112 = ([BrCl]^2) / (0.450 * 0.115)
Simplifying the expression, we find that the equilibrium partial pressure of BrCl is approximately 0.0375 atm.
Learn more about Equilibrium partial pressure of BrCl here:
#SPJ12
Answers
Answer:
General Characteristics of Acids:
Sour taste (though you should never use this characteristic to identify an acid in the lab) Reacts with a metal to form hydrogen gas. Increases the H+ concentration in water. Donates H+ ions. Turns blue litmus indicator red.
also turns blue litmus red