In the formation of a macromolecule, what type of bond would join two amino acid subunits? A)           ionic bond
                B)            phosphodiester bond
                C)            hydrogen bond
                D)           peptide bond

Answers

Answer 1

Answer: I think its an Ionic bond although i am not sure about

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In a reaction, chlorine accepts an electron to form Cl-. What is true about the atomic size of the chlorine ion?
Freezing requiresa. the removal of energy. b. the absorption of energy. c. no energy change.

Which statement defines the temperature of a sample of matter?1) Temperature is a measure of the total electromagnetic energy of the particles.
2) Temperature is a measure of the total thermal energy of the particles.
3) Temperature is a measure of the average potential energy of the particles.
4) Temperature is a measure of the average kinetic energy of the particles.

Can someone help me with this?

Answers

The correct answer is D.

It is known with definition of temperature.
Temperature of a system is average energy of microscopic motions of a single particle.
It's average kinetic energy.

3. 56 g of N₂ reacts 9 g of H₂ in a closed vessel to form NH3. Which reactant is left in excess and how 2207 much? 1) N₂, 10. g +3th = 2013/ (3) N₂, 14 g (2) H₂, 4 g (4) H₂,3 g N₂- to d A

Answers

Answer: the reactant left in excess is H₂, and the amount of excess H₂ is 4.5 moles - 3 moles = 1.5 moles.

Explanation: Moles of N₂ = mass of N₂ / molar mass of N₂

Moles of N₂ = 56 g / 28 g/mol = 2 moles

Moles of H₂ = mass of H₂ / molar mass of H₂

Moles of H₂ = 9 g / 2 g/mol = 4.5 moles

Cuantas moléculas de oxigeno se producen por la descomposición de 28.5 g de H2O2 (masa molecular = 34.0g/mol) de acuerdo a la ecuación 2H2O2(l) → 2H2O(l)+O2(g)

Answers

The question is as follows: How many oxygen molecules are produced by the decomposition of 28.5 g of H2O2 (molecular mass = 34.0g / mol) according to the equation

2H2O2 (l) → 2H2O (l) + O2 (g)

Answer: There are $2.52 * 10^(23)$ molecules are produced by the decomposition of 28.5 g of $H_(2)O_(2)$ according to the equation $2H_(2)O(l) \rightarrow 2H_(2)O(l) + O_(2)(g)$ .

Explanation:

Given: Mass of $H_(2)O_(2)$ = 28.5 g

As moles is the mass of a substance divided by its molar mass. Hence, moles of $H_(2)O_(2)$ is calculated as follow.

$Moles = (mass)/(molarmass)\n= (28.5 g)/(34.0 g/mol)\n= 0.838 mol$

According to the given equation, 2 moles of $H_(2)O_(2)$ gives 1 mole of $O_(2)$ . So, moles of $O_(2)$ produced by 0.838 moles of $H_(2)O_(2)$ will be calculated as follows.

$Moles of O_(2) = (0.838 mol)/(2)\n= 0.419 mol$

This means that moles of $O_(2)$ produced is 0.419 mol.

As per the mole concept, 1 mole of every substance has $6.022 * 10^(23)$ molecules.

So, molecules of $O_(2)$ present in 0.419 mole are as follows.

$0.419 * 6.022 * 10^(23)\n= 2.52 * 10^(23)$

Thus, we can conclude that there are $2.52 * 10^(23)$ molecules are produced by the decomposition of 28.5 g of $H_(2)O_(2)$ according to the equation $2H_(2)O(l) \rightarrow 2H_(2)O(l) + O_(2)(g)$ .

Within a particular compound, an atom gives up two electrons. This atom is A. part of a covalent compound.
B. positively charged.
C. negatively charged.
D. not part of an electrolyte.

Answers

Answer:

The correct answer is option B. positively charged.

Explanation:

Hello!

Let's solve this!

When an atom yields its electrons, it yields part of its negative charge. Therefore, it immediately transforms into a positively charged ion.

This positively charged ion is called cation.

We conclude that the correct answer is option B. positively charged.

Positively charged due to donating two electrons and becoming an ion.

Rank standard molar entropy without a data table? Without referring to a data table, rank the following compounds by standard molar entropy (highest to lowest). I can do it with a data table but not sure how to proceed without. Thank you for your help. N2(g) H2(g) C2H4(g)

Answers

I think the correct order from most entropy to least entropy is C2H4, N2, and H2. My reasoning is that C2H4 has the biggest number of microstates which means that it will have the most entropy since it. I then based N2 and H2 from there weights (which indicates size) since the larger something is the more microstates it is likely to have. I hope that helps. Let me know if anything is unclear or if you want me to add more detail.

What does the pH of a solution have to be in order to be a base?