Answer:
V=952.380952381 cm3cap V equals 952.380952381
Answer:
1.74845
Explanation:
We have the following reaction:
I2 + H2 => 2 HI
Now, the constant Kc, has the following formula:
Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b
In this case I2 is A, H2 is B and C is HI
We know that the values are:
H2 = 1 × 10 ^ -3 at 448 ° C
I2 = 2 × 10 ^ -3 at 448 ° C
HI = 1.87 × 10 ^ -3 at 448 ° C
Replacing:
Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}
Kc = 1.87 ^ 2/2 * 1
Kc = 1.74845
Which means that at 448 ° C, Kc is equal to 1.74845
Answer:
Explanation:
[H2] = 10^-3
[I2] = 2*10^-3
[HI] = 0
in equilbiirum
[H2] = 10^-3 - x
[I2] = 2*10^-3 -x
[HI] = 0 + 2x
and we know
[HI] = 0 + 2x = 1.87*10^-3
x = ( 1.87*10^-3)/2 = 0.000935
then
[H2] = 10^-3 - 0.000935 = 0.000065
[I2] = 2*10^-3 -0.000935 = 0.001065
H₂ + I ⇄ 2 HI
Initially 1 × 10⁻³ 2 × 10⁻³
Change -9.35 × 10⁻⁴ -9.35 × 10⁻⁴ +1.87 × 10⁻³
At equil 6.5 × 10⁻⁵ 1.06 5 × 10⁻³ 1.87 × 10⁻³
HI increase by 1.87 × 10⁻³M
Answer:
Crushing or grinding increases the surface area of the salt that is exposed to the molecules of water. Stirring increases the speed at which the particles of salt come in contact with the water molecules.
Answer:
Insurance, Protection, and Premium
Explanation:
Answer:insurance protection premium
Explanation trusttt lol
Answer:
80.0
Explanation:
edge 2020
The order of increasing atomic radius for the elements Li, Na, K, and Rb is Li
The arrangement of the following elements in increasing atomic radius: Li, Na, K, and Rb indicates that the atomic radius increases as we move down a group in the periodic table. This group of elements, Li, Na, K, and Rb, are all alkali metals and exhibit similar chemical behaviors. As the atomic number or Z increases, the atomic radius also increases. For example, Lithium (Li) has an atomic number of 3, Sodium (Na) 11, Potassium (K) 19, and Rubidium (Rb) 37. As we move down the group from Li to Rb, both Z and the atomic radius increase.
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