Which step would help a student find the molecular formula of a compound from the empirical formula?

Answers

Answer 1

Answer: First, you need to be given the gram formula mass of this molecular or related conditions that can calculate this. Then you need the empirical formula and calculate the gram formula mass of empirical formula. Then use them to get the ratio. Finally you can get the molecular formula.

Answer 2

Answer:

Final answer:

To find the molecular formula from the empirical formula, first calculate the empirical formula mass. Then, divide the molecular or molar mass by the empirical formula mass to find the number of empirical formula units per molecule. Finally, multiply the subscript of each element in the empirical formula by this number to get the molecular formula.

Explanation:

The process of finding the molecular formula from the empirical formula involves a few steps. First, you need to determine the empirical formula of a compound, which is the simplest positive integer ratio of atoms present in a compound. After you have the empirical formula, you can calculate the empirical formula mass by summing up the average atomic masses of all the atoms in the empirical formula.

Next, compare the compound's molecular or molar mass (which you should know or have been given) to the empirical formula mass. This comparison is done by dividing the molecular or molar mass by the empirical formula mass. This will give you the number of empirical formula units, denoted as n, per molecule of the compound.

The final step is to take the empirical formula and multiply the subscript of each element in it by n. This will give you the molecular formula of the compound.

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Liquids and solids are left out of the equilibrium constant expression because their concentrations remain constant during reactions. What is the molarity concentration of liquid water at 25.0 LaTeX: ^\circ ∘C given that its density is 0.997 g/mL at that temperature? a.23.5 M
b.0.997 M
c.0.180 M
d.0.156 M
e.55.3 M

Answers

Answer:

55.3 M

Explanation:

Given temperature = 25°C

Density = 0.997 g/mL

Based on density the mass of water per L = 997 grams

The molar mass of water = 18

The moles of water = $(mass)/(molarmass)=(997)/(18)=55.3$

The molarity is defined as the moles of water per litre.

The moles = 55.3

Volume = 1 L

So molarity = 55.3 /1 = 55.3 M

This is responsible for the relatively high boiling point of watera. hydrogen bonding
b. ionic bonding
c. metallic bonding
d. nonpolar covalent bonding
e. polar covalent

Answers

The bonding of hydrogen

Hydrogen bonding as it requires a lot of energy in the form of heat to break the bonds between the H and the O atoms

Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction. ____HNO3 + ____S ---> ____NO + ____H2SO4

Answers

Explanation:

An equation that contains equal number of atoms on both reactant and product side is known as a balanced chemical equation.

Whereas when there will be increase in oxidation number of the atom then it is known as oxidation. When there is decrease in oxidation number of the atom then it is known as reduction.

For example, $4HNO_(3) + S \rightarrow NO + H_(2)SO_(4) + H_(2)O$

Oxidation half reaction : $S \rightarrow H_(2)SO_(4) + 6e^(-)$

Reduction half reaction : $HNO_(3) + 3e^(-) \rightarrow NO$

Therefore, we can conclude that sulfur atom has undergone oxidation and nitrogen atom has undergone reduction.

The following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction.
2HNO3 + S ---> 2NO + H2SO4

Which quantity can vary among atoms of the same element?A) mass number
B) atomic number
C) number of protons
D) number of electrons

Answers

there is this thing called isotopes
it means that atoms of the same element can have a different number of neutrons.
if there is a change in the no. of neutrons, there will definitely be a change in the mass number.

so the answer is A) mass number

Final answer:

The quantity that can vary among atoms of the same element is the mass number, which represents the sum of the number of protons and neutrons in an atom.

Explanation:

The quantity that can vary among atoms of the same element is the mass number. The mass number represents the sum of the number of protons and neutrons in an atom. While the atomic number (which represents the number of protons) remains constant for atoms of the same element, the number of neutrons can vary, resulting in different mass numbers for atoms of the same element.

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How many grams of the molecule (C2H4O2) would be required to make 1 L of a 0.5 M solution of the molecule? (Carbon = 12, Oxygen = 16, Hydrogen = 1)(A) 16
(B) 100
(C) 15
(D) 25
(E) 30

Answers

MC₂H₄O₂ = 2 * 12 g/mol + 4 * 1 g/mol + 2 * 16 g/mol = 60 g/mol

c = 0.5 mol/L

V = 1 L

n = c * V

n = 0.5 mol/L * 1 L = 0.5 mol

m = n * M

m = 0.5 mol * 60 g/mol = 30 g/mol

answer E

(-_-(-_-)-_-)

What is the correct name of the compound Mn3(PO4)2? A. manganese phosphate B. manganese(I) phosphate C. manganese(III) phosphate D. manganese(II) phosphate

Answers

The correct name of the compound Mn3(PO4)2 is definitely the last option represented above D. manganese(II) phosphate. I am pretty sure this answer will help you

Final answer:

The compound Mn3(PO4)2 is correctly named as manganese(II) phosphate, based on the rule of naming ionic compounds and considering the oxidation state of the manganese ion.

Explanation:

The correct name of the compound Mn3(PO4)2 is manganese(II) phosphate. This is based on the rule of naming ionic compounds. With ionic compounds, the metal cation's oxidation state is represented in Roman numerals in parentheses if the metal can have more than one charge state.

In this case, the Mn3+ cation in Mn3(PO4)2 has an oxidation state of +2 since the phosphate ions PO4^3- balance out 3 Mn ions. Therefore, the compound is correctly named manganese(II) phosphate.

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