The most common carbonate rock is A) dolomite. B) halite. 35) C) limestone. D) calcite.

Answers

Answer 1

Answer:

Answer:

The correct option is : C) limestone.

Explanation:

Carbonate rocks are a type of sedimentary rocks. The carbonate rocks are composed of carbonate minerals. The carbonate minerals are the minerals containing carbonate ion (CO₃²⁻).

The most common type of carbonate rock is limestone. Limestone is composed of the minerals calcite and aragonite, which have a different crystal form of calcium carbonate.

Therefore, Limestone is the most common type of carbonate rock.

Related Questions

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For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomassie Blue followed by the addition of 50 ml of 85% v/v phosphoric acid. This entire mixture is then diluted to 1 liter with water. What is the final concentration of phosphoric acid?

What is the molarity of each ion present in aqueous solutions prepared by dissolving 20.00 g of the following compounds in water to make final volumes equal to 4.5 L.a. Cobalt(III) chloride

b. Nickel(III) sulfate

c. Sodium permanganate

d. Iron(II) bromide

Answers

Answer:

The molarity of Co³⁺ is 0.027 M

The molarity of Cl⁻ 0.081 M

The molarity of Ni³⁺ is 0.022 M

The molarity of SO₄²⁻ is 0.033 M

The molarity of Na⁺ is 0.031 M

The molarity of MnO₄⁻ is 0.031 M

The molarity of Fe²⁺ is 0.021 M

The molarity of Br⁻ is 0.042 M

Explanation:

The molarity of each ion is the molarity of the salt times the number of ions in the formula. First, we will calculate the molarity of each salt.

a. Cobalt(III) chloride. CoCl₃

The molar mass of CoCl₃ is 165.29 g/mol. The molarity of CoCl₃ is:

$(20.00g)/((165.29g/mol).4.5L) =0.027M$

The molarity of Co³⁺ is 1 × 0.027 M = 0.027 M

The molarity of Cl⁻ is 3 × 0.027 M = 0.081 M

b. Nickel(III) sulfate. Ni₂(SO₄)₃

The molar mass of Ni₂(SO₄)₃ is 405.57 g/mol. The molarity of Ni₂(SO₄)₃ is:

$(20.00g)/((405.57g/mol).4.5L) =0.011M$

The molarity of Ni³⁺ is 2 × 0.011 M = 0.022 M

The molarity of SO₄²⁻ is 3 × 0.011 M = 0.033 M

c. Sodium permanganate. NaMnO₄

The molar mass of NaMnO₄ is 141.92 g/mol. The molarity of NaMnO₄ is:

$(20.00g)/((141.92g/mol).4.5L) =0.031M$

The molarity of Na⁺ is 1 × 0.031 M = 0.031 M

The molarity of MnO₄⁻ is 1 × 0.031 M = 0.031 M

d. Iron(II) bromide. FeBr₂

The molar mass of FeBr₂ is 215.65 g/mol. The molarity of FeBr₂ is:

$(20.00g)/((215.65g/mol).4.5L) =0.021M$

The molarity of Fe²⁺ is 1 × 0.021 M = 0.021 M

The molarity of Br⁻ is 2 × 0.021 M = 0.042 M

Which of the following reactions would have the smallest value of K at 298 K? Which of the following reactions would have the smallest value of K at 298 K? A + B → 2 C; E°cell = -0.030 V A + 2 B → C; E°cell = +0.98 V A + B → C; E°cell = +1.22 V A + B → 3 C; E°cell = +0.15 V More information is needed to determine.

Answers

The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

Option A

Generally the equation for the number of electrons transferred is mathematically given as

$nFE^o_(cell)=RT\ln K$

where

T= Temperature

F=25C(298K)

R = Gas constant

R= 8.314 J/K.mol

F = Faraday's constant

F= 96500 C

We see from the equation that the E-cell is directly proportional to K(equilibrium constant of the reaction)

Hence, The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

For more information on Reaction

brainly.com/question/11231920

Answer:

The reaction with smallest value of K is :

A + B → 2 C; E°cell = -0.030 V

Explanation:

$nFE^o_(cell)=RT\ln K$

where :

n = number of electrons transferred

F = Faraday's constant = 96500 C

$E^o_(cell)$ = standard electrode potential of the cell

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = $25^oC=[273+25]=298K$

$K$ = equilibrium constant of the reaction

As we cans see, that standard electrode potential of the cell is directly linked to the equilibrium constant of the reaction.

Higher $E^o_(cell)$ higher will be the value of K.
Lower $E^o_(cell)$ lower will be the value of K.

So, the reaction with smallest value of electrode potential will have smallest value of equilibrium constant. And that reaction is:

A + B → 2 C; $E^o_(cell) =-0.030 V$

Dinitrogen monoxide has a structural formula of NNO and requires resonance structures in order to draw the Lewis structures of the molecule. Based on formal charge distributions, themostsignificant (stable) resonance structure for this molecule exhibits the order of formal charges for the 1st N, the central N, and the O atoms, respectively, as:A. 0,+1,-1
B. -1,+1,0
C. -2,+3,-1
D. 0,0,0

Answers

Three resonance structures contribute to the structure of dinitrogen monoxide.

The resonance structure is invoked when a single structure can not sufficiently explain all the bonding properties of a compound. All the various contributing structures contribute to the final structure of the compound but not all to the same degree.

There are three resonance structures of dinitrogen monoxide. The most stable structure is always the structure that has the formal charges as -1, +1 and zero as shown.

Learn more: brainly.com/question/14283892

Answer:

A. 0, +1, -1

Explanation:

You can draw the lewis structure for NNO 3 ways: With two double bonds N=N=O, with a triple bond between the N and O and single bond between the two N's, or a triple bond between the two N's and a single bond between the N and O.

The goal is to have formal charges that are as small as possible, to have no identical formal charges on adjacent atoms, and to have the most negative formal charge on the most electronegative atom. The most stable structure is the one with the triple bond between the two N's because it gives the formal charges 0, 1, and -1 respectively. Unlike the other two structures, the negative formal charge is correctly placed on O, the most electronegative atom.

Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equation.

Answers

Answer:

30 cm³

Explanation:

Step 1: Given data

Density of aluminum (ρ): 2.7 g/cm³

Mass of aluminum (m): 81 g

Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

In what way(s) is(are) the structure of water similar to that of CHCl3? In what way is the structure of water different from that of CHCl3?

Answers

Answer:

See explanation below

Explanation:

In both cases the central atoms, C in CHCl₃ and O in H₂O, are sp³ hybridized .

Since they are sp³ hybridized we predict an angle between the H-C-Cl and H-O-H of 109.5 º ( tetrahedral ), but two of the sp³ orbitals in water are occupied by lone pairs.

These lone pairs do excercise more repulsion ( need more room ) than the bonds oxygen is making with hydrogen.

As a consequence of this repulsion the angles H-O-H are less than the predicted 109.5º in tetrahedra. ( Actually is 104.5 º)

The chemical reaction for the formation of syngas is: CH4 + H2O -> CO + 3 H2 What is the rate for the formation of hydrogen, if the rate of the formation of carbon monoxide is 0.35 M/s ? g

Answers

Answer : The rate for the formation of hydrogen is, 1.05 M/s

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-(1)/(a)(d[A])/(dt)$

$\text{Rate of disappearance of B}=-(1)/(b)(d[B])/(dt)$

$\text{Rate of formation of C}=+(1)/(c)(d[C])/(dt)$

$\text{Rate of formation of D}=+(1)/(d)(d[D])/(dt)$

$Rate=-(1)/(a)(d[A])/(dt)=-(1)/(b)(d[B])/(dt)=+(1)/(c)(d[C])/(dt)=+(1)/(d)(d[D])/(dt)$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$CH_4+H_2O\rightarrow CO+3H_2$