ENGINEERING COLLEGE

A Coca Cola can with diameter 62 mm and wall thickness 300 um has an internal pressure of 100 kPa. Calculate the principal stresses at a point on the cylindrical surface of the can far from its ends.

Answers

Answer 1

Answer:

Answer:

$\sigma _1=10.33MPa$

$\sigma _2=5.16MPa$

Explanation:

Given that

Diameter(d)=62 mm

Thickness(t)= 300 μm=0.3 mm

Internal pressure(P)=100 KPa

Actually there is no any shear stress so normal stress will become principle stress.This is the case of thin cylinder.The stress in thin cylinder are hoop stress and longitudinal stress .

The hoop stress

$\sigma _h=(Pd)/(2t)$

Longitudinal stress

$\sigma _l=(Pd)/(4t)$

Now by putting the values

$\sigma _h=(Pd)/(2t)$

$\sigma _h=(100* 62)/(2* 0.3)$

$\sigma _h=10.33MPa$

$\sigma _l=5.16MPa$

So the principle stress are

$\sigma _1=10.33MPa$

$\sigma _2=5.16MPa$

Related Questions

Why do we care about a material's ability to resist torsional deformation?(A) Because the angle of twist of a material is often used to predict its shear toughness(B) Because rotating shafts are used in engineering applications(C) We don't care - simply an academic exercise.(D) Because it can determine G and inform us of a materials ability to resist shear deformation
Make a python code.Write a function named max that accepts two integer values as arguments and returns the value that is the greater of the two. For example, if 7 and 12 are passed as arguments to the function, the function should return 12. Use the function in a program that prompts the user to enter two integer values. The program should display the value that is the greater of the two. Write the program as a loop that continues to prompt for two numbers, outputs the maximum, and then goes back and prompts againHere’s an example of program useInput the first number: 10Input the second number: 5The maximum value is 10Run again? yesInput the first number: -10Input the second number: -5The maximum value is -5Run again? noFunction max():Obtain two numbers as input parameters: max(num1, num2):if num1 > num2 max_val = num1, else max_val = num2return max_valMain Program:Initialize loop control variable (continue = ‘y’)While continue == ‘y’Prompt for first numberPrompt for second numberCall function "max," sending it the values of the two numbers, capture result in an assignment statement:max_value = max (n1, n2)Display the maximum value returned by the functionprint(‘Max =’, max_val)Ask user for if she/he wants to continue (continue = input(‘Go again? y if yes’)
Calculate the "exact" alkalinity of the water in Problem 3-2 if the pH is 9.43.Calculate the "approximate" alkalinity (in mg/L as CaCO3 ) of a water containing 120 mg/L of bicarbonate ion and 15 mg/L of carbonate ion.
If you are pouring a large concrete slab and wish to avoid random cracks caused by shrinkage, you would likely provideA. expansion jointsB. isolation jointsC. control jointsD. construction joints
The pressure in an automobile tire depends on thetemperature of the air in the tire. When the air temperature is25°C, the pressure gage reads 210 kPa. If the volume of the tire is 0.025 m3, determine the pressure rise in the tire whenthe air temperature in the tire rises to 50°C. Also, determinethe amount of air that must be bled off to restore pressure toits original value at this temperature. Assume the atmosphericpressure to be 100 kPa.

Aluminum alloys are made by adding other elements to aluminum to im prove its properties, such as hardness or tensile strength. The following table shows the composition of ve commonly used alloys, which are known by their alloy numbers (2024, 6061, and so on) [Kutz, 1999]. Obtain a matrix algorithm to compute the amounts of raw materials needed to pro duce a given amount of each alloy. Use MATLAB to determine how much raw material of each type is needed to produce 1000 tons of each alloy. Composition of aluminum alloys Alloy %Cu %Mg %Mn %Si %Zn 2024 6061 7005 0 7075 356.0 0 0.6 0 0 0 0 4.5 5.6 0 0.6 0 0 2.5 0.3 0

Answers

Answer:

Cu= 60

Mg= 67

Mn= 6

Si= 76

Zn= 101

Explanation:

Solution steps :

1) Creating matrix A holds the composition of each raw material.

2) Submission of composition of each raw material.

3) Multiplying each amount by the total amount needed to be produced.

note

find the attached code

There are many diferent materials available for seal faces . List the following seal face materials in order of hardness. i.e Hardest first, softest last. (a) 316 Stainless Steel (b)-Mild steel (c)- Reaction bonded Silicon carbide (d)- Tungsten carbide

Answers

Answer:

Reaction bonded Silicon carbide: 2500-3500 HV

Tungsten carbide: 1800-2500 HV.

316 Stainless Steel: 152 HV

Mild steel: 130 HV

Explanation:

In order to list those seal face materials by hardness, we look up what are the values of hardness for each material in a hardness scale.

We are going to use Vickers scale, an indentation method of measuring hardness, it measures the deformation left in a sample by a constant compression load from an indenter (a diamond pyramid) with an adequate (to the material) force, as the result is independent from the test force.

1. Reaction bonded Silicon carbide: 2500-3500 HV

2. Tungsten carbide: 1800-2500 HV

3. 316 Stainless Steel: 152 HV

4. Mild steel: 130 HV

What is a SAFETY CHECK

Answers

Answer:

Safety check is defined as rounding to make sure that the patients and the milieu (patients living quarters) is secured and free of harmful items that can be used to hurt someone.

2) The switch in the circuit below has been closed a long time. At t=0, it is opened.Find the inductor current for il(t) for t> 0.

Answers

Answer:

il(t) = e^(-100t)

Explanation:

The current from the source when the switch is closed is the current through an equivalent load of 15 + 50║50 = 15+25 = 40 ohms. That is, it is 80/40 = 2 amperes. That current is split evenly between the two parallel 50-ohm resistors, so the initial inductor current is 2/2 = 1 ampere.

The time constant is L/R = 0.20/20 = 0.01 seconds. Then the decaying current is described by ...

il(t) = e^(-t/.01)

il(t) = e^(-100t) . . . amperes

Transactional Vs Transformational Leadership. Using the Internet, each member of your team should read at least 2 articles each on Transactional Vs Transformational Leadership. Summarize the articles in 300 words or more. Provide appropriate reference. Combine each summarize in one paper but do not change the wording of the original summary. As a term, write a comprehensive summary of the articles. Present a discussion of what your team learned from this exercise?

Answers

Answer: Provided in the explanation section

Explanation:

Transactional Leadership - This leadership style is mainly focused on the transactions between the leader and employees. If the employees work hard, achieve the objectives and deliver the results, they are rewarded through bonuses, hikes, promotions etc. If the employees fail to achieve the desired results, they are punished by awarding lower ratings in the performance appraisal, denying opportunities etc.

In this style, leader lays emphasis on the relation with the followers.

It is a reactive style where the growth of the employee in the organization completely depends on the performance with respect to the activities and deliverables.

It is best suited for regular operations and for a settled environment by developing the existing organizational culture which is not too challenging.

It is a bureaucratic style of leadership where the leader concentrates on planning and execution rather than innovation and creation.

A transactional leader is short-term focused and result oriented. He/she doesn't consider long-term strategic objectives regarding the organization's future.

cheers i hope this helped !!

A solid cylindrical workpiece made of 304 stainless steel is 150 mm in diameter and 100 mm is high. It is reduced in height by 50%, at room temperature, by open-die forging with flat dies. Assume that the coefficient of friction is 0.2. Calculate the forging force at the end of the stroke.

Answers

The answer is "45.3 NM".

There at end of the movement, the forging force is given by

$\to F = Y * \pi * r^2 * [1 + ((2 \mu r)/(3h))]$

h is the final height.

$\to h = (100)/(2)= 50 \ mm$

The ultimate radius is determined by following a volume constancy law, which states that volumes before deformation measured amount following distortion.

$\to \pi * 75^2 * 2 * 100 = \pi * r^2 * 2 * 50\n\n\to 75^2 * 2 = r^2\n\n\to r^2 = 11250\n\n\to r = √(11250)\n\n\to r = 106 \ mm\n\n\to E = \In((100)/(50))\n\n\to E = 0.69\n\n$

You may deduce from the graph flow that $Y = 1000\ MPa$ , thus we use the formula.

$= 1000 * 3.14 * 0.106^2 * [1 + (( 2 * 0.2 * 0.106)/(3 * 0.05))]\n\n= 1000 * 3.14 * 0.011236 * [1 + (( 0.0424)/(0.15))]\n\n= 35.3 * 1.2826\n\n = 45.3 \ MN\n\n\n$